x1 X 2/x1 X 3x1/2 X 8/3x1 X 15x1/8 X 16/5x1 X 35/16 X 128/35
=384
edit: school-level mutiplication error
@albiesriram said:
x(n) = n/x(n - 1)
=> x(n)*x(n - 1) = n
=> x(n)*x(n - 1) = n
=> x1*x2 = 2
x3*x4 = 4
x5*x6 = 6
x7*x8 = 8
So, x1x2x3x4x5x6x7x8 = 16*4! = 384
@rnishant231 said:pls explain this one..
x1+x1+x3+4x4= 20 can be solved by letting x4= 0,1,2,3,4,5
when x4 = 0, x1+x2+x3+0= 20 which has 22C2 solutions
when x4 = 1, x1+x2+x3= 16 which has 18c2 solutions...
.
.
.
when x4 = 5 only one solution i.e.(0,0,0,5)
hence 22C2+18C2+14C2+10C2+6C2 + 2C2
@albiesriram said:NOpe
ya, i understand chillfactor's soln above
trying to figure out what im doing wrong...
@albiesriram said:
x1*x2*...x8 wala..
Is it 384.??
@ScareCrow28 : I went on writing the terms and then multipying 'em. It took only 2 mins for that though, yet is there any other approach.?
@imrover said:sir, could you please elaborate on your approach?
the no.shud be of the form of 648K. so d only no. divisible in dat range of 523000 to 523999 is somethin around 5235_ _.so dere can only b 1 no.
i m nt sir ..i am a newbie here!!
i m nt sir ..i am a newbie here!!
@albiesriram said:NOpe
haha, i messed up the multiplication it is actually 128X3 = 384
i should be more careful....
it is late , though 
@mohitjain well, that signal thing beside your alias shows "expert pagal"....so thought why take a chance :P
and sorry, where did u get this 648k from?
and sorry, where did u get this 648k from?
@sbharadwaj said:x1*x2*...x8 wala.. Is it 384.?? @ScareCrow28 : I went on writing the terms and then multipying 'em. It took only 2 mins for that though, yet is there any other approach.?
x1*x2 = 2
x3*x4 = 4 and so on... Answer in seconds
@chillfactor Sir ne b yahi kia h.. 😃
Maine b chill sir jaisa kia h 😛 :splat:
Solution:
To find : x1.x2.x3.x4.x5.x6.x7.x8
Given:
xn = n / x n-1 ;
x1 = 97->dump it.
we have,
xn = n/xn-1 or,
x.xn-1 = n.
so x2.x1 = 2, x4.x3= 4 , x6.x5=6, x8.x7=8
2.4.6.8= 384 OA
A shopkeeper bought an article for 360. the profit made by the shopkeeper after selling it after a 11.11% discount is 40. FIND marked price
@imrover said:@mohitjain well, that signal thing beside your alias shows "expert pagal"....so thought why take a chance and sorry, where did u get this 648k from?
9,7,8 ka l.c.m se..the first no.divisible by 9,7,8 together is 648 so every no has to be multiple 0f 648
hope u get it!
hope u get it!
@vbhvgupta said:A shopkeeper bought an article for 360. the profit made by the shopkeeper after selling it after a 11.11% discount is 40. FIND marked price
450 it is
@vbhvgupta said:A shopkeeper bought an article for 360. the profit made by the shopkeeper after selling it after a 11.11% discount is 40. FIND marked price
CP = 360
SP = 0.8889*MP
Profit = 40
0.8889MP - 360 = 40
MP = 450 ?
@mohitjain arey 9,8,7 ka lcm would be 504.
btw, this way we are aonly considering the last three digits. the complete number is 523_ _ _. How can we conclude just by looking at the last three digits?
btw, this way we are aonly considering the last three digits. the complete number is 523_ _ _. How can we conclude just by looking at the last three digits?
@imrover said:@mohitjain arey 9,8,7 ka lcm would be 504.anyway, got d approach. thanks.
sry calculation error
..feelin sleepy
@mohitjain
this way we are only considering the last three digits. the complete number is 523_ _ _. How can we conclude just by looking at the last three digits?
this way we are only considering the last three digits. the complete number is 523_ _ _. How can we conclude just by looking at the last three digits?