@saurav205Suppose Nimai starts from point A and Nitai from point B. After travelling 400 mts Nimai is back at A but after travelling 700 mts Nitai is not at B or his initial position, but at A. According to me, they can never simultaneously reach their initial positions.Could you please point out where am I missing it ?
bhai they can reach their initial positions simultaneously after travelling 800 and 1400 m respectively, i quoted saurav bro earlier,check my post
how many 3 digit numbers are there in base 7 which when converted to base 10 gives perfect square??
or how many 3 digit numbers in base 7 are perfect square
for 1 it will be 12 but for second it wont be 12 because number with unit digit 9 is never possible in base 7 so it will be 12-3=9( subtracting cases for 7,3,17
Now see .. When person A has travelled 7 one way journeys , person B would have travelled 4 one way journeys . At this moment , they would be at the same point . Till this point, they would have met 7 times as faster person would have crossed slower person 7 times.
Now when they start from the same point , just try and imagine : THIS WOULD BE A REWINDMOVIE OF WHAT HAD EARLIER TAKEN PLACE . They would start together and end at their respective positions after 14 and 8 rounds respectively. So all meeting points would repeat .
deres no aaproach as such ..had 2 check d nos.. d composite odd nos less dan 38 are 9,15,21,25,27,33,35..nt gettin 38 by adding any of those!! aftr dat we can get each even no. as sum of 2 composite
bhai the function will have repeated roots after an interval of 5 integers????? right ?that was the only concept there? rest is just algebra i am not good today thats why commiting stupid errors