Official Quant thread for CAT 2013

MBA CAT 2024
26868
@albiesriram said:
if p^q is a perfect square and perfect cube it can be represented atleast two ways in the form of p^q . then how will u know what is q?
answer should be e) CBD
haan it can be a multiple of 2 and 3 and 6 from the options....so CBD ...
waise first thought to 6 strike karta hai na...
26869
@Dexian ans is e
26870
@Dexian said:
haan it can be a multiple of 2 and 3 and 6 from the options....so CBD ...waise first thought to 6 strike karta hai na...
Typical prometric wala question that. Easy still taunting.
26871
@Gsathe89 said:
@Dexian ans is e
If it's a perfect square and perfect cube at the same time, then q = 6k

Obviously 2 and 3 are included in 6, so answer should be 6k na?

@albiesriram @Dexian ( bhow bhow )
26872


@albiesriram ya ya got it .... 😁
eg if p=64 and q=1
then option c will be incorrect
26873
@ScareCrow28 said:
If it's a perfect square and perfect cube at the same time, then q = 6k

Obviously 2 and 3 are included in 6, so answer should be 6k na?

@albiesriram @Dexian ( bhow bhow )
arey wahi na 6k is also a multiple of 2 and 3 so 3 options satisfy... so CBD...
26874
@Gsathe89 said:
@albiesriramya ya got it .... eg if p=64 and q=1 then option c will be incorrect
so wats the final ans? c r8?
26875
@Gsathe89 said:
If p^q is a perfect square as well as a perfect cube , where p and q are natural numbers, then q must be a multiple ofa. 2b. 3c. 6d. 9e. cannot be determined
2^6 or 4^3 or 27^2

in all cases p^q is a perfect sq and cube.

so CBD ??
26876
@DarkHorse25 Last option CBD
26877
@Logrhythm yaa
26878
@Dexian said:
arey wahi na 6k is also a multiple of 2 and 3 so 3 options satisfy... so CBD...
But, we always take that options which is the best possible answer
Suppose if a question has following options:

1. x > 1
2. x > 2
3. x > 3
4. x > 4
5. CBD
If x > 2
What will you say ?? CBD ? Or x > 2 ?
26879
@silentstriker said:
The answers are (a) and (d) respectively.
I am not satisfied with the answer, to the first question, given in the source here. That is why I posted it here to have opinions from all of you. Feel free to write your explanations.
26880
@ScareCrow28 said:
If it's a perfect square and perfect cube at the same time, then q = 6kObviously 2 and 3 are included in 6, so answer should be 6k na? @albiesriram@Dexian ( bhow bhow )
P^6k is the number,

P^q form may be one of the following forms, (p^2)^3 here q is 3, (p^3)^2 here q is 2 , (P) ^6 here 6, (p^6)^ 1

We are always not sure what is q. So CBD. for example if we take 64 as a case ,

we can represent 64 as (2^3)^2= (8) ^2 here q is 2
also as (2^2)^3 = 4^3 here q is 3

then we are not sure about its divisibility.
26881
@ScareCrow28 said:
But, we always take that options which is the best possible answer
Suppose if a question has following options:

1. x > 1
2. x > 2
3. x > 3
4. x > 4
5. CBD
If x > 2
What will you say ?? CBD ? Or x > 2 ?
arey log bhai wala sol dekhne se aur bhi clear ho jayega i guess ...........
26882
@silentstriker said:
I am not satisfied with the answer, to the first question, given in the source here. That is why I posted it here to have opinions from all of you. Feel free to write your explanations.
However, I can see that 175 cannot be the answer here as there has to be some overlap. The important thing here is that we are now dealing with 50% and not with 100% as we do normally.
@Subhashdec2
@iLoveTorres
@VJ12
@rnishant231
26883
@silentstriker
1 . C
2 . D
26884
@silentstriker said:
OA KYA HAI.....
26885

2ND IS PRETY STARIGHT FORWARD ...

MY TAKE ON THE FIRST ONE......
TO MAXIMIZE THE NO. OF SINGLE SMOKERS WE HAVE TO MINIMIZE THE NO. OF THOSE WHO SMOKE ALL THREE.... AND PUT THOSE WHO SMOKE TWO = 0
LET THE NO. OF PEOPLE BE 100
AND NO. OF PEOPLE WHO SMOKE ALL THREE BE X...
SO SMOKERS = A+B+C+X= 50
A+B+C+3X = 92
--> 2X = 42
x=21
SO A+B+C CAN BE MAXIMUM 29 (WHEN THERE ARE 100 PEOPLE)
CONVERTING TO THE CASE OF 350
29*350/2
29*7/2 ---WHICH IS NOT POSSIBLE SO DECREASE THE VALUE OF A+B+C= 28
HENCE TOTAL NO..= 98

26886
@psk.becks Please don't write in ALL CAPS! ( If possible ) It doesn't make a good read!
#No-offence! 😃 ..
26887

ok