Official Quant thread for CAT 2013

@Ashank.Dubey said:
Use pythagoras triplets.
That I did, and when I first saw the prob I used options too (it is an old CAT or XAT prob I suppose). Just that the question posted didn't have options and your solution says to use them, which is adding insult to injury :splat:

regards
scrabbler

@scrabbler said:
Er, what options? The solution you posted says "use options" but original posts did not have options so it was a much more painful solution!!regardsscrabbler
If you don't want to use answer options. Solving 2r^2 + 3r = 9(9 + 6r)^1/2 is more painful.
@albiesriram said:
Correct sir, Share your valuable approach..
In such problems where i dont have any idea how to approach , I start with small cases .

Here, when x=0 , value of expression=0 .. and when x=1..value of exp is 20 ...
so when we vary x from 0 to 1 , we get different values from 0 to 20 .. now let's check which values we got and which we didnt.. now analysing, we skipped values at values of x which make more than one of the terms out of 2x,4x,6x,8x as integers .. ex= for x=1/2 all become integers. so we skipped 3 values ..similarly at x=1, we skipped 3 values..
now at x=1/4 and x=3/4 we skip one value each .. so we skipped total of 8 values in first 20 nos..
hence we will skip 8/20*1000=400 values in 1000 nos..
so we can obtain rest 600 values 😃 hope u understood n liked this unique approach of mine :)

Team BV--Pratik Gauri
@bodhi_vriksha said:
In such problems where i dont have any idea how to approach , I start with small cases . Here, when x=0 , value of expression=0 .. and when x=1..value of exp is 20 ...so when we vary x from 0 to 1 , we get different values from 0 to 20 .. now let's check which values we got and which we didnt.. now analysing, we skipped values at values of x which make more than one of the terms out of 2x,4x,6x,8x as integers .. ex= for x=1/2 all become integers. so we skipped 3 values ..similarly at x=1, we skipped 3 values..now at x=1/4 and x=3/4 we skip one value each .. so we skipped total of 8 values in first 20 nos..hence we will skip 8/20*1000=400 values in 1000 nos..so we can obtain rest 600 values hope u understood n liked this unique approach of mine Team BV--Pratik Gauri
awesome!
@bodhi_vriksha said:
In such problems where i dont have any idea how to approach , I start with small cases . Here, when x=0 , value of expression=0 .. and when x=1..value of exp is 20 ...so when we vary x from 0 to 1 , we get different values from 0 to 20 .. now let's check which values we got and which we didnt.. now analysing, we skipped values at values of x which make more than one of the terms out of 2x,4x,6x,8x as integers .. ex= for x=1/2 all become integers. so we skipped 3 values ..similarly at x=1, we skipped 3 values..now at x=1/4 and x=3/4 we skip one value each .. so we skipped total of 8 values in first 20 nos..hence we will skip 8/20*1000=400 values in 1000 nos..so we can obtain rest 600 values hope u understood n liked this unique approach of mine Team BV--Pratik Gauri
sir yeh part thoda explain kar do pls
@bodhi_vriksha
@iLoveTorres said:
sir yeh part thoda explain kar do pls
at x=1/2 , all four [2x] , [4x],[6x] and [8x] become integers simultaneously ..

so here , we got 1 value instead of 4 .. hence we missed 3 values .. what i mean is ..take x=0.6
we get [2x]=1
[4x]=2
[6x]=3
and [8x]=4 .. so here we get diff values but it is not so in case of x=1 and x=1/2 .. so we skipped 3 values in prev case .. hope you got it now :)

Team BV--Pratik Gauri
:applause:

In such problems where i dont have any idea how to approach , I start with small cases .
@iLoveTorres said:
sir yeh part thoda explain kar do pls
what he means to say is put x=0.5 u will get 10

and put x=.4999999 infinite times
u will get
[2x]=0
[4x]=1
[6x]=2
[8x]=3

hence 6

7,8,9 can never be achieved

hence we skipped 3 values
@maroof10 said:
Ram marks up his goods by 40% and gives a discount of 10%.Apart from this,he uses faulty balance which reads 800 gms for 1000 gms .What is his net profit/loss percentage?
57.5%
@Ashank.Dubey said:
arun=v1
varun=v2
kinnamala=v3
2d/v1+v2 =8/3
2d/v1+v3=3
2d/v2+v3=24/5

v2=D/4
v3=D/6
v1=D/2

Arun and varun meet at 20 kms from D
arun travels D+20 varun travels D-20
d+20/d-20 =d/2 / d/4
D=60
v3=10??

@Ashank.Dubey



@bodhi_vriksha said:
In such problems where i dont have any idea how to approach , I start with small cases . Here, when x=0 , value of expression=0 .. and when x=1..value of exp is 20 ...so when we vary x from 0 to 1 , we get different values from 0 to 20 .. now let's check which values we got and which we didnt.. now analysing, we skipped values at values of x which make more than one of the terms out of 2x,4x,6x,8x as integers .. ex= for x=1/2 all become integers. so we skipped 3 values ..similarly at x=1, we skipped 3 values..now at x=1/4 and x=3/4 we skip one value each .. so we skipped total of 8 values in first 20 nos..hence we will skip 8/20*1000=400 values in 1000 nos..so we can obtain rest 600 values hope u understood n liked this unique approach of mine Team BV--Pratik Gauri
sir one trivia
how did u get that it will be skipping values on 1/4
as in y not 1/6?

@bodhi_vriksha said:
In such problems where i dont have any idea how to approach , I start with small cases . Here, when x=0 , value of expression=0 .. and when x=1..value of exp is 20 ...so when we vary x from 0 to 1 , we get different values from 0 to 20 .. now let's check which values we got and which we didnt.. now analysing, we skipped values at values of x which make more than one of the terms out of 2x,4x,6x,8x as integers .. ex= for x=1/2 all become integers. so we skipped 3 values ..similarly at x=1, we skipped 3 values..now at x=1/4 and x=3/4 we skip one value each .. so we skipped total of 8 values in first 20 nos..hence we will skip 8/20*1000=400 values in 1000 nos..so we can obtain rest 600 values hope u understood n liked this unique approach of mine Team BV--Pratik Gauri
sir ye cases kaise banai jinke ley check karna hai?? e.g. 1/4 n 3/4...

€Ž4 / (1 + (1^2/(2 + 3^2/(2 + 5^2/(2 + 7^2/(2 + 9^2/(2 + ... ) ) ) ) ) ) ) =?

The answer is Weird hence i am taking back the question. Sorry for the inconvenience caused.. The answer btw is pi i guess. Anyway, beyond the scope of CAT.


Today is Pi day. 3/14

@Ashank.Dubey said:
answer should be 10 .. feeling too lazy to retype ..@Subhashdec2 has already provided the solution above :)

Team BV--Pratik Gauri
@Subhashdec2 said:
sir one triviahow did u get that it will be skipping values on 1/4as in y not 1/6?
I did check at 1/6 also .. even 1/8 .. This ques took me approx 5 mins to solve :(

That is why i call this SMALL CASE APPROACH .. It takes time but generally is v effective :)

Team BV--Pratik Gauri
@Ashank.Dubey 10?
@albiesriram said:
€Ž4 / (1 + (1^2/(2 + 3^2/(2 + 5^2/(2 + 7^2/(2 + 9^2/(2 + ... ) ) ) ) ) ) ) =?P.S: No OA available..
These type of ques should be solved with options . With options available, this question is a one liner . :)

Team BV--Pratik Gauri
@albiesriram said:
€Ž4 / (1 + (1^2/(2 + 3^2/(2 + 5^2/(2 + 7^2/(2 + 9^2/(2 + ... ) ) ) ) ) ) ) =?P.S: No OA available..
Around 4 / 1.2....would pick relevant option...

regards
scrabbler