Official Quant thread for CAT 2013

@albiesriram said:
I am not sure whether 3D is there in the syllabus or not. But i had one 3D last time. Hence,
Ans b? Inf GP with common ratio 1/rt3.

regards
scrabbler

What is 1^2 - 2^2 + 3^2 - 4^2.......................+199^2 - 200^2?
@rnishant231 said:
No. subset including Richard and Jerry = 127 - 36(for situation in which rich and jerry are already included) = 96..
Isko aur elaborate karna Plz
@Buck.up said:
What is 1^2 - 2^2 + 3^2 - 4^2.......................+199^2 - 200^2?
-20100?

paper saving bhaiyon...
:)

regards
scrabbler

@albiesriram said:
I am not sure whether 3D is there in the syllabus or not. But i had one 3D last time. Hence,
general formula
gp of 1/_/3 common difference
sum _/3r/_/3-1
r=_/3
so 3/_/3-1

1^2 -2^2 = - 3

3^2-4^2 = - 7
5^2-6^2 = - 11
7^2-8^2= - 15

so 50* [ 6 + 49 * 4] = - 10100?
n= 100
so 50 * [6 + 99*4 ] = 20100
@albiesriram said:
1^2 -2^2 = - 33^2-4^2 = - 7 5^2-6^2 = - 117^2-8^2= - 15so 50* [ 6 + 49 * 4] = - 10100?
99 I think? 100 terms are there...

regards
scrabbler

how much % more than the CP shd a shopkeeper mark his good so that after allowing a discount of 12.5% he should have a gain of 5% on his outlay

@Buck.up said:
What is 1^2 - 2^2 + 3^2 - 4^2.......................+199^2 - 200^2?
is it -20100
@albiesriram said:
I am not sure whether 3D is there in the syllabus or not. But i had one 3D last time. Hence,
option b ?
@vbhvgupta said:
how much % more than the CP shd a shopkeeper mark his good so that after allowing a discount of 12.5% he should have a gain of 5% on his outlay
20 %
@vbhvgupta said:
how much % more than the CP shd a shopkeeper mark his good so that after allowing a discount of 12.5% he should have a gain of 5% on his outlay
20% more

Consider CP as 100, means SP is 105
That means after giving 12.5% discount on Marked price he is selling it at 105.
So 87.5% of marked price is 105.
So Marked price is 120.
Hence when CP is 100, marked price is 120. Hence 20% more.
@Buck.up said:
Isko aur elaborate karna Plz
Assume Noah and his friends are N,R(Richard),J(jerry),f1,f2,f3,f4,f5
N has to be there
So,
the case in which there is no restriction on R and J , we can frame subsets
as 7C0 + 7C1 + .... 7C7 = 128 (bcoz all 7 friends are considered)

We need to remove the subsets where R and J are together
as 5C0 + 5C1+....+5C5 = 32 (R and J are already taken , so only 5 friends remaining)

So OA = 128 - 32 =96..Hope it helps
@albiesriram said:
I am not sure whether 3D is there in the syllabus or not. But i had one 3D last time. Hence,
b) 3/ sqrt3 -1
@vbhvgupta said:
how much % more than the CP shd a shopkeeper mark his good so that after allowing a discount of 12.5% he should have a gain of 5% on his outlay
markprice/costprice = 120%
@rnishant231 Thanks bro. Nice lucid explanation
@vbhvgupta said:
how much % more than the CP shd a shopkeeper mark his good so that after allowing a discount of 12.5% he should have a gain of 5% on his outlay
20%
If x^2 + y^2 - 4x - 6y + 13 = 0, then what is x:y?
@Buck.up said:
What is 1^2 - 2^2 + 3^2 - 4^2.......................+199^2 - 200^2?
(1^2-2^2) + (3^2-4^2) + ... + (199^2 - 200^2) = -3-7-11-...-399 = -(3+7+11+...+399)
sum = -50[6 + 396] = -20100