Here is the short cut through another prob €œMinimum of all €? regions in Venn DiagramsIn a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the minimum possible number of men using all the 5 brands, if all the 100 men use at least one of these brands?Solution: Sum of the difference from 100 = (100-100) + (100-75)+(100-80)+(100-90)+(100-60) = 95Again take the difference from 100 = 5 (answer)
Pls solve this one: In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the maximum possible number of men using 3 of the 5 brands, if all the 100 men use at least one of these brands?
@jain4444@Narci@chillfactor@saurav205Your answer as well as explanation is correct. But I wanted to teach you a good logic here. Let me try it with a couple of more questions on similar lines. (i) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 800 where each alphabet denotes distinct single digit positive integer.(ii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 900 where each alphabet denotes distinct single digit positive integer.(iii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 1000 where each alphabet denotes distinct single digit positive integer.Team BV
1) and 3) not possible as sum of all digits is 45, multiple of 9 but 800 and 1000 are not multiple of 9
Pls solve this one: In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the maximum possible number of men using 3 of the 5 brands, if all the 100 men use at least one of these brands?Team BV
Pls solve this one: In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the maximum possible number of men using 3 of the 5 brands, if all the 100 men use at least one of these brands?Team BV
@jain4444@Narci@chillfactor@saurav205Your answer as well as explanation is correct. But I wanted to teach you a good logic here. Let me try it with a couple of more questions on similar lines. (i) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 800 where each alphabet denotes distinct single digit positive integer.(ii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 900 where each alphabet denotes distinct single digit positive integer.(iii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 1000 where each alphabet denotes distinct single digit positive integer.Team BV
800 I not possible...
900 is ....should be 20 18 and 7....
1000 i havent checked...but think so thats also not possible....
Abhi in office will check when o get back home.....
Pls solve this one: In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the maximum possible number of men using 3 of the 5 brands, if all the 100 men use at least one of these brands?Team BV
M getting 45 for this one...used straight lines and then tried to maximise the portion with 3 overlappinh lines....
Guys pls help me out. what is the best preparation strategy for quant in cat? should i first go through all the concepts of all chapters and then start taking tests....or should i learn a chapter and take its test and then move on to the next chapter?
@jain4444@Narci@chillfactor@saurav205Your answer as well as explanation is correct. But I wanted to teach you a good logic here. Let me try it with a couple of more questions on similar lines. (i) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 800 where each alphabet denotes distinct single digit positive integer.(ii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 900 where each alphabet denotes distinct single digit positive integer.(iii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 1000 where each alphabet denotes distinct single digit positive integer.Team BV
@bodhi_vriksha it is we who learn from the Chillfactor and Jain Bhai..... i think we should be very careful before we decide that we can claim that we can teach these guys. I have been on this forum for just less than 10 years and I can say that Chillfactor is undoubtedly the most talented on the Quant forum, anyone who knows him just bows down to him for what we all have learned from him. Jain Bhai too is held in very high regards on the forum.
Not really blaming you for anything but just pointing it to you in case you are not aware, so that we can be more respectful to the members who are respected by one and all.
An urn contains 75 white balls and 150 black ones. A pile of black ones is also available. The following two-step operation occurs repeatedly. First we withdraw two balls at random from the urn, then: If both are black, we put one of them back in the urn and throw the other away. If one is black and the other white, we put the white one back and throw the black one away. If both are white, we throw both away and put a black ball from the pile into the urn.
What color ball remains in the urn at the end of this exercise?
@bodhi_vriksha it is we who learn from the Chillfactor and Jain Bhai..... i think we should be very careful before we decide that we can claim that we can teach these guys. I have been on this forum for just less than 10 years and I can say that Chillfactor is undoubtedly the most talented on the Quant forum, anyone who knows him just bows down to him for what we all have learned from him. Jain Bhai too is held in very high regards on the forum.Not really blaming you for anything but just pointing it to you in case you are not aware, so that we can be more respectful to the members who are respected by one and all.----------------------------------------------------------------------------An urn contains 75 white balls and 150 black ones. A pile of black ones is also available.The following two-step operation occurs repeatedly. First we withdraw two balls at random from the urn, then:If both are black, we put one of them back in the urn and throw the other away.If one is black and the other white, we put the white one back and throw the black one away.If both are white, we throw both away and put a black ball from the pile into the urn.What color ball remains in the urn at the end of this exercise?ATDH.
black should remain, whatever may be the sequence may be
@bodhi_vriksha it is we who learn from the Chillfactor and Jain Bhai..... i think we should be very careful before we decide that we can claim that we can teach these guys. I have been on this forum for just less than 10 years and I can say that Chillfactor is undoubtedly the most talented on the Quant forum, anyone who knows him just bows down to him for what we all have learned from him. Jain Bhai too is held in very high regards on the forum.Not really blaming you for anything but just pointing it to you in case you are not aware, so that we can be more respectful to the members who are respected by one and all.----------------------------------------------------------------------------
ATDH sir thanks for your kind words but i really don't deserve that much respect , I just like to solve quant problems but i can't be even 1% of you and chill sir , you both are GOD of QUANT and moreover great personalities
@bodhi_vriksha sir I agree with ADTH sir "it is we who learn from chill sir"
How many 4-term geometric sequences have all four terms positive integers less than or equal to 100?
ATDH sir thanks for your kind words but i really don't deserve that much respect , I just like to solve quant problems but i can't be even 1% of you and chill sir , you both are GOD of QUANT and moreover great personalities @bodhi_vriksha sir I agree with ADTH sir "it is we who learn from chill sir" How many 4-term geometric sequences have all four terms positive integers less than or equal to 100?
sir, 116??
with ratio 1 , 100 such G.Ps
with 2 , x*2^3
with 3, x has 3 values
with 4, x has 1 value
so 116 ??
it can be more than this, if we consider G.P such as , 96,48,24,12 and 12,24,48,96 different
in that case it would be 132....
PS: i have been seeing chillfactor sir since the time i have been on PG, 3-4 years, since my 1st day... and there has nt been a single post by him, which had not helped users... immense respect for him...
@bodhi_vriksha it is we who learn from the Chillfactor and Jain Bhai..... i think we should be very careful before we decide that we can claim that we can teach these guys. I have been on this forum for just less than 10 years and I can say that Chillfactor is undoubtedly the most talented on the Quant forum, anyone who knows him just bows down to him for what we all have learned from him. Jain Bhai too is held in very high regards on the forum.Not really blaming you for anything but just pointing it to you in case you are not aware, so that we can be more respectful to the members who are respected by one and all.
Hear, hear ___/\___ and let me add ATDH also to that list, since he is evidently too modest to do so himself :)
----------------------------------------------------------------------------An urn contains 75 white balls and 150 black ones. A pile of black ones is also available.The following two-step operation occurs repeatedly. First we withdraw two balls at random from the urn, then:If both are black, we put one of them back in the urn and throw the other away.If one is black and the other white, we put the white one back and throw the black one away.If both are white, we throw both away and put a black ball from the pile into the urn.What color ball remains in the urn at the end of this exercise?ATDH.
I have a feeling this will be white since there is an odd number of white ones initially.... whites can go out only when "both are white" so the number of whites can reduce by 2 at a time only and ek to bach hi jayega? regards scrabbler
if we happen to pick 2 black balls, till we remove all possible black balls, we would be left with 1 black ball and 75 white ball, next we pick 1 white and 1 black, white back into urn, black out, next 2 white, 1 black enters..
so 73 white 1 black,,
we would be left with 1 white and 1 black, sorry... 1 white should remain in d end...
