@pratskool said:for 20 books cost = 260for n copies n*16, now n*16 > 260... 17,18,19 3 such value exists,,, the problem cant be so easy, perhaps m making a mistake
A Child is saying numbers 1, 2, 3, 4. When he says 1 Another child puts white marble in a box. On saying 2 he puts Blue marble and on saying 3 he puts red ma rble. When child says 4 other child take out white and blue marble. Child says some no. in a sequence then questions are based on the no. of marbles in the box. Like this
1,1,2,3,1, 4, 1,1,3,2,2,4,111?
a) Find the no. of Blue marble in the box ? 2
b) Find the no. of White-2
c) No. of red marbles - 7
1,1,2,3,1, 4, 1,1,3,2,2,4,111?
a) Find the no. of Blue marble in the box ? 2
b) Find the no. of White-2
c) No. of red marbles - 7
how is this anwer possible
@ChirpiBird said:t minutes he drives extra at 4a speed.. so he drives with speed a for 20 + 6 +t mins less than usualtotal distance will be same2.5a*6+4at=(26+t)a26-15=3tt=11/3 mins
Could you explain this in detail please...
@p.bhaskar said:A Child is saying numbers 1, 2, 3, 4. When he says 1 Another child puts white marble in a box. On saying 2 he puts Blue marble and on saying 3 he puts red ma rble. When child says 4 other child take out white and blue marble. Child says some no. in a sequence then questions are based on the no. of marbles in the box. Like this 1,1,2,3,1, 4, 1,1,3,2,2,4,111? a) Find the no. of Blue marble in the box ? 2 b) Find the no. of White-2 c) No. of red marbles - 7how is this anwer possible
When 4, does he take out all the blue and white marbles or just one of each??
@saurav205 there not mentioned anything else.....i think all balls...but they answers as it was shown ther
2.If M person r buying a thing costing D$ each,, if 3 person get away, how much each person has to spend so that total expenditure is same ?.
@p.bhaskar said:2.If M person r buying a thing costing D$ each,, if 3 person get away, how much each person has to spend so that total expenditure is same ?.
D+(3D/m-3)
@amresh_maverick said:Single copy of a book costs $16, but purchasers of 20 copies or more pay only $13 per copy. How many values of 'n' (0
OA: 3 values - 17,18,19
@saurav205 said:Could you explain this in detail please...
yes.. sure
time.. t1 , t2 and t3 for a , 2.5a and 4a.
Distance = at1 + 2.5at2 + 4at3
he starts 20 minutes late,
time left with him = t1 + t2 + t3 – 20.
Time for 4a km/hr....(t3 + t)
Time for 2.5a km/hr ... (t2 + 6)
Time for a km/hr = t1 – (20 +6+t).
distance remains same...
at1 + 2.5at2 + 4at3 = a(t1 – (26+t )) + 2.5a(t2 + 6) + 4a (t3 + t).
earlier i didnt mention this t1,t2,t3 because... obviously yeh katne hi the ..
difference regular day aur late start day mein bas itna tha ki (6 + 20 + t )a distance usne 2.5*6 +4at mein cover kia.
got it?
P.s : sry for late reply, was watching a movie, didnt see the notification. 😛 :)
time.. t1 , t2 and t3 for a , 2.5a and 4a.
Distance = at1 + 2.5at2 + 4at3
he starts 20 minutes late,
time left with him = t1 + t2 + t3 – 20.
Time for 4a km/hr....(t3 + t)
Time for 2.5a km/hr ... (t2 + 6)
Time for a km/hr = t1 – (20 +6+t).
distance remains same...
at1 + 2.5at2 + 4at3 = a(t1 – (26+t )) + 2.5a(t2 + 6) + 4a (t3 + t).
earlier i didnt mention this t1,t2,t3 because... obviously yeh katne hi the ..
difference regular day aur late start day mein bas itna tha ki (6 + 20 + t )a distance usne 2.5*6 +4at mein cover kia.
got it?
P.s : sry for late reply, was watching a movie, didnt see the notification. 😛 :)
70% of the students who joined xyz last year play football, 75% play cricket, 80% play basketball and 85% play carrom. what is the minimum percentage of students who play all four games?
@techgeek2050 said:70% of the students who joined xyz last year play football, 75% play cricket, 80% play basketball and 85% play carrom. what is the minimum percentage of students who play all four games?
10% ??
@techgeek2050 said:@amresh_maverick dunno the OA. plz share ur approach.
Here is the short cut through another prob :)
€œMinimum of all €? regions in Venn Diagrams
In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the minimum possible number of men using all the 5 brands, if all the 100 men use at least one of these brands?
Solution: Sum of the difference from 100 = (100-100) + (100-75)+(100-80)+(100-90)+(100-60) = 95
Again take the difference from 100 = 5 (answer)
€œMinimum of all €? regions in Venn Diagrams
In a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the minimum possible number of men using all the 5 brands, if all the 100 men use at least one of these brands?
Solution: Sum of the difference from 100 = (100-100) + (100-75)+(100-80)+(100-90)+(100-60) = 95
Again take the difference from 100 = 5 (answer)
@amresh_maverick said:Here is the short cut €œMinimum of all €? regions in Venn DiagramsIn a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the minimum possible number of men using all the 5 brands, if all the 100 men use at least one of these brands?Solution: Sum of the difference from 100 = (100-100) + (100-75)+(100-80)+(100-90)+(100-60) = 95Again take the difference from 100 = 5 (answer)
Even shorter cut.
75 + 80 + 90 +60 = 305.
305 - 300 = 5.
regards
scrabbler
75 + 80 + 90 +60 = 305.
305 - 300 = 5.
regards
scrabbler
@amresh_maverick said:Here is the short cut through another prob €œMinimum of all €? regions in Venn DiagramsIn a survey conducted among 100 men in a company, 100 men use brand A, 75 use brand B, 80 use brand C, 90 use brand D & 60 use brand E of the same product. What is the minimum possible number of men using all the 5 brands, if all the 100 men use at least one of these brands?Solution: Sum of the difference from 100 = (100-100) + (100-75)+(100-80)+(100-90)+(100-60) = 95Again take the difference from 100 = 5 (answer)
@techgeek2050 said:70% of the students who joined xyz last year play football, 75% play cricket, 80% play basketball and 85% play carrom. what is the minimum percentage of students who play all four games?
Total = 100%
Football = 100-70 = 30
Cricket = 25
Basketball = 20
Carrom = 15
Total = 90
Min % who play all four games = 100-90 = 10
@techgeek2050 said:70% of the students who joined xyz last year play football, 75% play cricket, 80% play basketball and 85% play carrom. what is the minimum percentage of students who play all four games?
Take the difference of each from 100...then add all the diff and subtract from 100
Will come ojt as 10
@iLoveTorres said:look capital letters cant come in between so the first place can be filled in 7 ways..the remaining three places can be filled up ascase 1) 1 vowel + 2 consonants i.e 3c1*5c2=3*10=30 they can be arranged in 3! case 2) 2 vowels +1 consonant i.e 3c2*5c1 = 3*5=15 they can be arranged in 3!case 3) 3 vowels = 1 way they can be arranged in 3!So totally there are 7*((30+15+1)*6)=7*276=1932
@jain4444 said:7C1 * 14C3 * 3! - 7C1 * 11C3 * 3! = 8358
@Logrhythm said:7c1*3c1*11c2*3! + 7c1*3c2*11c1*3! + 7c1*3c3*3! = 8358...
@chandrakant.k said:first place 7 ways.now case 1 : when 1 vowel is present : 7*3*11*10 = 2310*3(as vowel can be in any of the 3 place) = 6930case 2: when 2 vowels are present : 7*3C2*3*11 = 693case 3 : when all vowels are presnt : 7*3! = 42total = 6930+693+42 = 7665
I am sorry..Had to rush due to some work...
1932 is d correct ans. @iLoveTorres I just want to know one thing..What's wrong in this method??
1st letter can be filled in 7 ways..Now atleast one vowel needs to be considered in 3 ways..
now the rest two letters can be selected out of remaining 13 letters..So, 13C2..
Now the 3 places other than 1st letters casn be arranged in 3! ways..
Ans = 7 * 3 * 13C2 * 3!...Tell me where I am wrong...
@techgeek2050 said:70% of the students who joined xyz last year play football, 75% play cricket, 80% play basketball and 85% play carrom. what is the minimum percentage of students who play all four games?
I + II + III + IV = 70 + 75 + 80 + 85 = 310
And I, II and III can be at most 100 each. So minimum value for IV = 310-300 = 10%
PS: I, II, III, IV denotes number (percentage) of students who play at least one, two, three and four games respectively.
EXT. Qs - What is the maximum percentage of students who play at most two of the four games?
Team BV
And I, II and III can be at most 100 each. So minimum value for IV = 310-300 = 10%
PS: I, II, III, IV denotes number (percentage) of students who play at least one, two, three and four games respectively.
EXT. Qs - What is the maximum percentage of students who play at most two of the four games?
Team BV
@bodhi_vriksha said:Today's teaser Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 891 where each alphabet denotes distinct single digit positive integer.Team BV
@jain4444 @Narci @chillfactor @saurav205
Your answer as well as explanation is correct. But I wanted to teach you a good logic here. Let me try it with a couple of more questions on similar lines. :)
(i) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 800 where each alphabet denotes distinct single digit positive integer.
(ii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 900 where each alphabet denotes distinct single digit positive integer.
(iii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 1000 where each alphabet denotes distinct single digit positive integer.
Team BV
Your answer as well as explanation is correct. But I wanted to teach you a good logic here. Let me try it with a couple of more questions on similar lines. :)
(i) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 800 where each alphabet denotes distinct single digit positive integer.
(ii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 900 where each alphabet denotes distinct single digit positive integer.
(iii) Find sum of all possible values of B + E + H such that ABC + DEF + GHI = 1000 where each alphabet denotes distinct single digit positive integer.
Team BV