@Budokai001 said:IF f(log base10 x) = a/xFind f(2x+1)
2a ?
@The_Loser said:A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is?
let the speed of the car be v
so speed of train = 3v/2
=> 75/v - 75/(3v/2) = 125/600
=> v = 120 kmph
@The_Loser said:A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is?
speed of car=v
train =3v/2
time taken=75/v
75/v-75*2/3v=12.5/60
25/v=12.5/60
v=120?
Compute the sum of all n for which the equation 2x + 3y = n has exactly 2011 nonnegative (x; y >= 0)
integer solutions.
integer solutions.
@iLoveTorres said:bhai yeh kya kiya hai? do you mind explaining your approach in detail..
It is a divisibility test for 7...can be derived using the seed number approach...don't remember the details...not very useful in most situations :(
regards
scrabbler
regards
scrabbler
@Budokai001 said:PQRS is a rectangle.T and U are points on RQ and SR respectively.The areas of triangles PQT,PUS and TUR are in ratio 4:2:3 and UR=6 ,PS=12find area of triangle PUT
is it 42?
@The_Loser said:A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is?
car xkm/hr .. train 1.5xkm/hr
75/x= 75/1.5x + 12.5/60
x= 120
75/x= 75/1.5x + 12.5/60
x= 120
@The_Loser said:Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
in one hour.. it covers 9km less.
this is where the time was spent as stoppage. so, (9/54)= 1/6 hour = 10 minutes.
this is where the time was spent as stoppage. so, (9/54)= 1/6 hour = 10 minutes.
@Budokai001 said:PQRS is a rectangle.T and U are points on RQ and SR respectively.The areas of triangles PQT,PUS and TUR are in ratio 4:2:3 and UR=6 ,PS=12find area of triangle PUT
42?
@gnehagarg said:Compute the sum of all n for which the equation 2x + 3y = n has exactly 2011 nonnegative (x; y >= 0)integer solutions.
:D12060-65
regards
scrabbler
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is
@ChirpiBird said:explain please.
@gnehagarg said:Compute the sum of all n for which the equation 2x + 3y = n has exactly 2011 nonnegative (x; y >= 0)integer solutions.
Umm looked for a pattern...I found that for n = 0 ek hi solution hai. Also for 1, 2, 3, 4, 5. But at 6, 2 solutions milenge. then at 12, 3. And so on. So 6*2010 ko pehli baar milenge 2011 solutions and 2012 will happen at 6*2011. So 12060 to 12065...
regards
scrabbler
@The_Loser said:A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is
4.14 ?
@The_Loser said:A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is
speed of A = 25/18 mps
A covers 100m in 72 secs
B covers 92 m in 80 sec....so speed of B = 92/80 or 92/80*(18/5) = 4.14 kmph
@scrabbler said:Umm looked for a pattern...I found that for n = 0 ek hi solution hai. Also for 1, 2, 3, 4, 5. But at 6, 2 solutions milenge. then at 12, 3. And so on. So 6*2010 ko pehli baar milenge 2011 solutions and 2012 will happen at 6*2011. So 12060 to 12065...regardsscrabbler
ye ques CAT/XAT lvl ka hai?? :(
@Logrhythm said:ye ques CAT/XAT lvl ka hai??
Ho sakta hai...level has been varying widely in the last few years...last year most sections had a few sitters and a few nightmares...
Why btw? Did you find it too easy or too painful? 😃 For me the latter since algebra is my weakest link...
regards
scrabbler
Why btw? Did you find it too easy or too painful? 😃 For me the latter since algebra is my weakest link...
regards
scrabbler