@jain4444 said:1 way 1st box = 1 ball 2nd box = 2 balls ..9th box = 9 balls now total sum should be = 45 kg if sum would be = 44.80 then faulty box is box 2 and so on
Awesome approach-out of box thinking 
Due to reducation of 25% in price of oranges a customer can purchase 4 more oranges for 16. what is the original price of an orange.
Due to reducation of 20% in price of oranges a customer can purchase 6kg more oranges for 240. what is the original price per kg of an orange.
@vbhvgupta said:Due to reducation of 25% in price of oranges a customer can purchase 4 more oranges for 16. what is the original price of an orange.
1.33 ?
16/.75x - 16/x = 4
x = 1.33
@vbhvgupta said:Due to reducation of 20% in price of oranges a customer can purchase 6kg more oranges for 240. what is the original price per kg of an orange.
Rs 6.66?
@vbhvgupta said:Due to reducation of 20% in price of oranges a customer can purchase 6kg more oranges for 240. what is the original price per kg of an orange.
same approach as mentioned above...
240/.8x - 240/x = 6
x = 10
240/.8x - 240/x = 6
x = 10
IF f(log base10 x) = a/x
Find f(2x+1)
@vbhvgupta said:Due to reducation of 25% in price of oranges a customer can purchase 4 more oranges for 16. what is the original price of an orange.
say for rs16 u used to buy k oranges. ...one orange for k/16
now for rs 16 u can buy k+4 oranges (k+4)/16
(k/16) = (3/4)*(k+4)/16
k=12
initially u were buying 12 oranges for rs 16.
or 1 orange for 16/12 = 1.33
now for rs 16 u can buy k+4 oranges (k+4)/16
(k/16) = (3/4)*(k+4)/16
k=12
initially u were buying 12 oranges for rs 16.
or 1 orange for 16/12 = 1.33
@vbhvgupta said:Due to reducation of 20% in price of oranges a customer can purchase 6kg more oranges for 240. what is the original price per kg of an orange.
k/240 =4/5(k+6)/240
k=24
24kgs for 240..
so.. original price 10. :)
k=24
24kgs for 240..
so.. original price 10. :)
@saurabhlumarrai said:minimum could be 2.??
@jain4444 said:1 way 1st box = 1 ball 2nd box = 2 balls ..9th box = 9 balls now total sum should be = 45 kg if sum would be = 44.80 then faulty box is box 2 and so on
@ravi.theja OA :1
PQRS is a rectangle.T and U are points on RQ and SR respectively.
The areas of triangles PQT,PUS and TUR are in ratio 4:2:3 and UR=6 ,PS=12
find area of triangle PUT
The areas of triangles PQT,PUS and TUR are in ratio 4:2:3 and UR=6 ,PS=12
find area of triangle PUT
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
@chillfactor said:A set S consists of first n natural numbers such that S = {1, 2, 3, 4, ....., n}. For each of its non-zero subset, alternating sum is defined as :-Arrange the elements in subsets in decreasing order and then alternately add and subtract successive terms such that largest term is always added. For eg:- alternating sum for (1, 3, 5, 7} is 7 - 5 + 3 - 1 = 4 and for {3}, its just 3Find the sum of all such alternating sums for n = 8
8 can only be at (+) positions i.e. 1st position
total number = 2^7
sum = 2^7*8
7 can be at 1 (+) position when highest number in subset is 7 and 1 (-) position when highest number in subset is 8
total numbers = 2^6 in both cases
sum = 2^6*7 - 2^6*7 = 0
6 also can be at 2 (+) position when highest is 6 and when 7&8 both present in subset and
2 (-) position when highest is 7 OR 8
total number = 2^5 in all cases
sum = 2^5*6 + 2^5*6 - 2^*6 - 2^5*6 = 0
like this all other terms also got cancelled
so , we have only 1 term left i.e. 2^7*8
@The_Loser said:Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
9/54 *60 = 10 minutes?
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is?
@The_Loser said:Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
due to stoppages, it covers 9 km less
hence -> 9*60/54 = 10 minutes ka stoppage...