@saurav205 said:0 aayega,....pattern repeats after every 6 numbers....also 1000/1001 gives R as -1so 10^6 /1001 will give R of +1so triplets alternate +1 and -1..100 triplets....so sum will be 0...hence divisible....
@viewpt said:Q: 37^37^41^43^53 div by 67find R?Gd Night
@scrabbler said:108?Either three serials liked by 2 (NT, NR and TR) and the 4th liked by only 1 person (in which case the person liking the 4th can be chosen in 3 ways (N or T or R) and the likes
@albiesriram said:NIna , Teena, Reena watch 4 kinds of serials. No serial is liked by all the three gals. Furthermore,for each of the three pairs of gals, there is at least one song liked by those two gals and disliked by the third. In how many ways it is possible? Options:108,132,671,846,1105.
@iLoveTorres said:bro isko ek simple method se yaad karlo.. if you multiply any three digit number xyz by 1001 you would get xyzxyz.. so if the no of digits given is multiple of 6 then it is completely divisible by 1001 provided the six digits are of the form xyzxyz
I have mentioned that the pattern repeats after every 6...
@Logrhythm said:37^37^41^43^53%67 --- (A) e(67) = 6637^41^43^53%66 --- (B)e(66) = 2041^43^53%20 = 1put in (B)37^1%66 = 37put in (A)37^37%67 = 37*(37^2)^18%67 = 37*(29^2)^9%67 = 37^2(37^2)^4%67 = 29*(29^2)^2%67 = 37...
@scrabbler said:108?Either three serials liked by 2 (NT, NR and TR) and the 4th liked by only 1 person (in which case the person liking the 4th can be chosen in 3 ways (N or T or R) and the likes can be arranged among the serials i 4! ways giving 72 waysOr the 4th serial is also liked by one of the above combos NT, NR or TR. In which case the combo which is doubled can be chosen in 3 ways and then the combos can be arranged among the serials in 4!/2! = 12 ways giving 36 ways.I am assuming we needn't consider a case where a serial is watched by no-one!Total 72 + 36 = 108.regardsscrabbler
OA is 132, After considering The conditions where in no one watches the serial. 36+96 =132.
Hey I am attaching a DI question in here.Kindly solve with detailed solutions.Thanks!!
@Dexian said:serial and songs are the same kya??
. Someone probably copy-pasted and changed variables and forgot to change all...koi ghatiya software engineer hoga....hum bhi yehi karte the CFD assignments mein...:)@pathetic said:Hey I am attaching a DI question in here.Kindly solve with detailed solutions.Thanks!!
@albiesriram said:OA is 132, After considering The conditions where in no one watches the serial. 36+96 =132.
@ScareCrow28 said:Zoom karo it's okay if he has posted DI ka man ni kara though
@pathetic said:Hey I am attaching a DI question in here.Kindly solve with detailed solutions.Thanks!!
@scrabbler said:Assumed so else question makes no sense . Someone probably copy-pasted and changed variables and forgot to change all...koi ghatiya software engineer hoga....hum bhi yehi karte the CFD assignments mein...regardsscrabbler
@abhishek.2011 said:i banged my head yesterday 2 times just because of this question now will post 2 approaches, all the options are wrong herex+y+z=30let y and z be greater than 3x+(4+a)+(4+b)=30here y= 4+a and z = 4+b as a and b can be 0,1..... so y and z will always be greater than 3x+a+b=22solutions = 24c2now these 24c2 solutions will include cases in which x is anything from 0 to 22let x .y ,z all be greater than 3(4+a) + (4+b) +(4+c)=30a+b+c=18 solutions 20c2now 24c2 - 20c2 will include all the numbers having x less than or equal to 3 and y and z greater than or equal to 4let x be 0 y and z can be equal here (15,15) so -1caselet x be 2 y and z can again be equal here (14,14) so -1 casetotal favourable cases24c2- 20c2 -2 =84now this i did for x similarly y and z can also be takenso 84*3c1=252prove me wrong if u can
@pathetic said:Hey I am attaching a DI question in here.Kindly solve with detailed solutions.Thanks!!
@scrabbler said:Can't accept that as the question says "NIna , Teena, Reena watch 4 kinds of serials" So considering a case where 1 serial is not watched at all makes no sense as it contradicts the question. regardsscrabbler
