@viewpt said:Q: 123123............300 times div by 1001 find the remainder?
10^3%1001 = -1
10^6%1001 = 1
just form sets from right of 3 each with alternate - +
there are 100 such pairs, hence 0....
@viewpt said:Q: 123123............300 times div by 1001 find the remainder?
0...? Divisible hoga na...
regards
scrabbler
regards
scrabbler
@amresh_maverick said:OA : 127PFA@Dexian
but while calculating total number.... are u not xcluding vertices twice in various places...
5c3-7c3-4c3
i mean acc to u we are reading each vertex in 2 different line....
plzz correct me if i m wrong....
@amresh_maverick said:OA : 127PFA@Dexian
but while calculating total number.... are u not xcluding vertices twice in various places...
5c3-7c3-4c3
i mean acc to u we are reading each vertex in 2 different line....
plzz correct me if i m wrong....
@Logrhythm said:abe yaar... hero bann raha tha...bina paper pen ke karke...galati kardi...abb nahi kar raha solve..
arey koi nahi...............
NIna , Teena, Reena see 4 kinds of serials. No serial is liked by all the three gals. Furthermore,for each of the three pairs of gals, there is at least one sserial liked by those two gals and disliked by the third. In how many ways it is possible? Options:108,132,671,846,1105.
@Pradeep_Rss said:A special kind of wine requires to be kept for 4 years in a special chamber as as to acquire the required taste.The cost of manufacturing one bottle is 250 and inventory cost for each bottle is rs 4 per year.The company makes 6000 bottles and keeps them in special chambers, but every year 2% of the bottles break.After 4 years at what price should they sell remaining bottles to make a profit of 10%
318ish?
regards
scrabbler
regards
scrabbler
@Pradeep_Rss
Well 310 aa raha hai mera..
First Year: 6000 bottles..Hence Total Cost= 6000*4 + 250*6000 = 1524000
Second Year: 5880 bottles..Hence Total Cost= 5880*4 = 23520
Third Year: 5880*98/100 = 5762 bottles..Hence Total Cost= 5762*4 = 23048
Fourth Year: 5762*98/100 = 5647 bottles..Hence Total Cost = 5647*4 = 22588
Hence, TC of the Company = 1593156..
Given, 56470*C = 11*1593156
=>C = 310..
Galat lag raha hai mujhe.. Kya 1st year se hi bottles disintegrate karne lagege?
@techgeek2050 said:p,q,r are non negative integers such that p + q + r = 10 the maximum value of pqr + pr + qr + pq isa- >=40 and b- >=50 and c- >=60 and d- >=70 and e- >=80 and dunno the oa. plz post ur approach.
the product is max only when the numbers are as close as possible
Consider a+b = 10 when will a*b be max? oly when a=b=5 right?
So for the max condition of pqr+pr+qr+pq consider p=3.5 q=3.5 r=3
36.75+10.5+10.5+12.25
Though if you take p=3.3 q=3.3 r=3.4 you would get 70.39
so obviously the value lies in the range d- >=70 and
Consider a+b = 10 when will a*b be max? oly when a=b=5 right?
So for the max condition of pqr+pr+qr+pq consider p=3.5 q=3.5 r=3
36.75+10.5+10.5+12.25
Though if you take p=3.3 q=3.3 r=3.4 you would get 70.39
so obviously the value lies in the range d- >=70 and
@viewpt said:Q: 123123............300 times div by 1001 find the remainder?
0 aayega,....
pattern repeats after every 6 numbers....
also 1000/1001 gives R as -1
so 10^6 /1001 will give R of +1
so triplets alternate +1 and -1..
100 triplets....so sum will be 0...
hence divisible....
@iLoveTorres said:the product is max only when the numbers are as close as possibleConsider a+b = 10 when will a*b be max? oly when a=b=5 right?So for the max condition of pqr+pr+qr+pq consider p=3.5 q=3.5 r=336.75+10.5+10.5+12.25Though if you take p=3.3 q=3.3 r=3.4 you would get 70.39so obviously the value lies in the range d- >=70 and
remember p q r shud be integers.................
Q: 37^37^41^43^53 div by 67find R?
Gd Night
Gd Night
@ChirpiBird said:see.. let's take total salary is 700.A would earn 300, B 400.let's say they spend 450 together.. A spends, 200, and B 250so savings ratio will be .. 100/150= 2/3 ... somewhere around .6666..by options.. 9/10=.903/4=.7513/20= .654/5=.80best option would be 13:20.
hmmm 
....bade dino baad darshan hue 
....bade dino baad darshan hue @iLoveTorres said:the product is max only when the numbers are as close as possibleConsider a+b = 10 when will a*b be max? oly when a=b=5 right?So for the max condition of pqr+pr+qr+pq consider p=3.5 q=3.5 r=336.75+10.5+10.5+12.25Though if you take p=3.3 q=3.3 r=3.4 you would get 70.39so obviously the value lies in the range d- >=70 and
bhai p,q,r are integers. answer would be c
@albiesriram said:NIna , Teena, Reena watch 4 kinds of serials. No serial is liked by all the three gals. Furthermore,for each of the three pairs of gals, there is at least one song liked by those two gals and disliked by the third. In how many ways it is possible? Options:108,132,671,846,1105.
Ye kya hai!@albiesriram said:NIna , Teena, Reena watch 4 kinds of serials. No serial is liked by all the three gals. Furthermore,for each of the three pairs of gals, there is at least one song liked by those two gals and disliked by the third. In how many ways it is possible? Options:108,132,671,846,1105.
108?
Either three serials liked by 2 (NT, NR and TR) and the 4th liked by only 1 person (in which case the person liking the 4th can be chosen in 3 ways (N or T or R) and the likes can be arranged among the serials i 4! ways giving 72 ways
Or the 4th serial is also liked by one of the above combos NT, NR or TR. In which case the combo which is doubled can be chosen in 3 ways and then the combos can be arranged among the serials in 4!/2! = 12 ways giving 36 ways.
I am assuming we needn't consider a case where a serial is watched by no-one!
Total 72 + 36 = 108.
regards
scrabbler
Either three serials liked by 2 (NT, NR and TR) and the 4th liked by only 1 person (in which case the person liking the 4th can be chosen in 3 ways (N or T or R) and the likes can be arranged among the serials i 4! ways giving 72 ways
Or the 4th serial is also liked by one of the above combos NT, NR or TR. In which case the combo which is doubled can be chosen in 3 ways and then the combos can be arranged among the serials in 4!/2! = 12 ways giving 36 ways.
I am assuming we needn't consider a case where a serial is watched by no-one!
Total 72 + 36 = 108.
regards
scrabbler
@perseverance07 said:remainder when 2^2 + 22^2 + 222^2 + 2222^2 + ....(222...49twos)^2 is divided by 9?ans options: 2,5,6,7 ?
OA: 6
approach:
since N mod 9= digital sum of digits of N
so reminder is:
2^2+4^2+6^2+8^2+10^2+........98^2{(49*2)^2}
={2^2+4^2+6^2+8^2+5*(1^2+2^2+3^2+......9^2)} mod 9
={4+7+9+1+3} mod 9
=6
approach:
since N mod 9= digital sum of digits of N
so reminder is:
2^2+4^2+6^2+8^2+10^2+........98^2{(49*2)^2}
={2^2+4^2+6^2+8^2+5*(1^2+2^2+3^2+......9^2)} mod 9
={4+7+9+1+3} mod 9
=6
@viewpt said:Q: 37^37^41^43^53 div by 67find R?Gd Night
37^37^41^43^53%67 --- (A)
e(67) = 66
37^41^43^53%66 --- (B)
e(66) = 20
41^43^53%20 = 1
put in (B)
37^1%66 = 37
put in (A)
37^37%67 = 37*(37^2)^18%67 = 37*(29^2)^9%67 = 37^2(37^2)^4%67 = 29*(29^2)^2%67 = 37...