Last 2 digits for 37^64??
@2013IsMine said:Let cost price be P S.P of 20 articles each=P1from profit percent we getP1=4/3PLet S.P of 30 articles each=P2From loss we get P=6/5P2....P2=5/6Poverall C.P=50Poverall S.P =20*4/3P + 30*5/6P=155/3 Pprofit=155/3-50/50=5/(3*50)*100=10/3 %
Can explain more abr.p=6/5p2 plz
lekin 10/3 matlab... 33.33%
is it that high...
i think it will be 3.33%
plzz confirm....
is it that high...
i think it will be 3.33%
plzz confirm....
@Kira1591 said:Nice dude ur correct ans is 10/3 . Thanx mate . Ans is 10/3
lekin 10/3 matlab... 33.33%
is it that high...
i think it will be 3.33%
plzz confirm....
is it that high...
i think it will be 3.33%
plzz confirm....
@Dexian said:lekin 10/3 matlab... 33.33%is it that high...i think it will be 3.33%plzz confirm....
3.33% ...
@Kira1591 said:Can explain more abr.p=6/5p2 plz
loss=C.P-S.P
now loss given=6P2
6P2=30P-30P2
P2/5=P-P2
p=6/5P2
Ans is 3.33 .
The ratio of the monthly income of A and B is 3:4.The ratio of the monthly expenditure of A and B is 4:5 .Which of the following represents a possible value of the ratio of their savings?
a)9:10 b)3:4 c)13:20 d)4:5
3x-4y/4x-5y stuck here 
@Dexian said:lekin 10/3 matlab... 33.33%is it that high...i think it will be 3.33%plzz confirm....
Dude 10/3 = 3.33 only...
regards
scrabbler
regards
scrabbler
ho gya...@pakkapagal said:The ratio of the monthly income of A and B is 3:4.The ratio of the monthly expenditure of A and B is 4:5 .Which of the following represents a possible value of the ratio of their savings?a)9:10 b)3:4 c)13:20 d)4:53x-4y/4x-5y stuck here
Original Numerator is 75% of Denominator. If reduction in N were to be 75% that of D the fraction would not change.
But....reduction in N is 80% of reduction in D. So has to be less than 3/4 na? Only 1 answer satisfies...13/20.
regards
scrabbler
But....reduction in N is 80% of reduction in D. So has to be less than 3/4 na? Only 1 answer satisfies...13/20.
regards
scrabbler
@Dexian said:ye kaise kiya??
37^64
37^2 last 2 digits = 69
so now 69^32 last 2 digit = 61^16
so 1 in unit digit and for tens place 6*6 =36
take the 6..
so 61 aayega....
A Five digit number is formed by using 1,3,5,7 and 9 without repeating any of them.What is the sum of all such possible numbers?
a)6666600
b)6666660
c)6666666
d)None of these
@saurabhlumarrai said:A Five digit number is formed by using 1,3,5,7 and 9 without repeating any of them.What is the sum of all such possible numbers?a)6666600b)6666660c)6666666d)None of these
a)6666600
@saurabhlumarrai said:A Five digit number is formed by using 1,3,5,7 and 9 without repeating any of them.What is the sum of all such possible numbers?a)6666600b)6666660c)6666666d)None of these
its option a)6666600...
@saurabhlumarrai said:Its correct. approach please...
there is a formula for that- (n-1)!*(sum of all numbers)*(111...n times)...