@bs0409 said:65^43^54^12 is divided by 32. Remainder=?
should be 1...
e(32) is 16
43^54^12%16
e(16) is 12
54^12%16
54^12%12 = 6^12%12 = (36)^6%12 = 0
=> 65%32 = 1...
@The_Loser said:sry bro, do not have any concrete method.but saw this type of question quite a few backit was simply the HCF of 100 & 120 that is 20. so (2^100-1)(2^120 - 1) ----------> (2^20 - 1)
Find GCD of (2^100)-1 and (2^120) -1
2^100 - 1 = 2^100 - 1^100
Now a^n - b^n is always divisible by a - b
So this will be divisible by any 2^x - 1^x where x is a factor of 100. (2^10 - 1^10, 2^50 - 1^50, 2^20 - 1^20, 2^5 - 1^5, 2^25 - 1^25 and so on)
Similarly 2^120 - 1 will be divisible by any 2^y - 1^y where y is a factor of 120.
The highest common one here is 2^20 - 1. Now proving that it is the GCD I don't know...
regards
scrabbler
2^100 - 1 = 2^100 - 1^100
Now a^n - b^n is always divisible by a - b
So this will be divisible by any 2^x - 1^x where x is a factor of 100. (2^10 - 1^10, 2^50 - 1^50, 2^20 - 1^20, 2^5 - 1^5, 2^25 - 1^25 and so on)
Similarly 2^120 - 1 will be divisible by any 2^y - 1^y where y is a factor of 120.
The highest common one here is 2^20 - 1. Now proving that it is the GCD I don't know...
regards
scrabbler
@Logrhythm said:should be 1... e(32) is 1643^54^12%16e(16) is 1254^12%1654^12%12 = 6^12%12 = (36)^6%12 = 0=> 65%32 = 1...
Aila itna lamba solution....
65^43^54^12 is divided by 32. Remainder=?
65 when divided by 32 is 1. So 65^anything when divided by 32 is 1. End of story. :)
regards
scrabbler
65^43^54^12 is divided by 32. Remainder=?
65 when divided by 32 is 1. So 65^anything when divided by 32 is 1. End of story. :)
regards
scrabbler
Q) Fresh grapes contain 90% water by weight whereas dry grapes contain 20% water by weight. Ram buys 64 kgs of fresh grapes for Rs. 160. At what price should Ram sell the dry grapes to get a profit of 20%
@scrabbler said:Aila itna lamba solution....65^43^54^12 is divided by 32. Remainder=?65 when divided by 32 is 1. So 65^anything when divided by 32 is 1. End of story. regardsscrabbler
hahaha....i knw....but i was really getting bored... 😃
but abb SB ki junta jaag rahi hai 😛
@tmohan02 said:Q) Fresh grapes contain 90% water by weight whereas dry grapes contain 20% water by weight. Ram buys 64 kgs of fresh grapes for Rs. 160. At what price should Ram sell the dry grapes to get a profit of 20%
24 / kg?
regards
scrabbler
regards
scrabbler
32^32^32 MOD (7)=????
@bs0409 said:65^43^54^12 is divided by 32. Remainder=?
1?
65^43^54^12 mod 32 = 1^43^54^12 mod 32 = 1
@tmohan02 said:Q) Fresh grapes contain 90% water by weight whereas dry grapes contain 20% water by weight. Ram buys 64 kgs of fresh grapes for Rs. 160. At what price should Ram sell the dry grapes to get a profit of 20%
64kg grapes contain 6.4kg pulp and rest water..
for dry grapes --> (6.4+x)*.2 = x
=> x = 1.6kg
so wt of dry grapes = 8kg
SP = 1.2*160 = 192
hence 192/8 = 24/ kg dry grapes....
@bs0409 said:32^32^32 MOD (7)=????
Not sure what I did, confooz ho gaya:(
Edit: 4.
embarrassing error 
1^odd ko -1 liya...regards
scrabbler
@tmohan02 said:Q) Fresh grapes contain 90% water by weight whereas dry grapes contain 20% water by weight. Ram buys 64 kgs of fresh grapes for Rs. 160. At what price should Ram sell the dry grapes to get a profit of 20%
24.
@bs0409
Shld be 4..
Here, E(7)= 6..Hence Rem[32^6/7] = 1
Now, Since the power is 32^32..we will have to simplify this power in terms of 6k + r..Hence, we need, Rem[32^32/6] = ?
Now, Rem[32^32/6] => Rem[2^32/7] = 4..
Hence, 32^32^32 can be written as 32^(6k + 4)
Hence, Rem[32^6k*32^4/7] = Rem[4^4/7] = 4..
@scrabbler said:2?Not sure what I did, confooz ho gayaregardsscrabbler
@Logrhythm said:3^32^32%73^4%7 = 4...
@pyashraj said:@bs0409Shld be 4..Here, E(7)= 6..Hence Rem[32^6/7] = 1Now, Since the power is 32^32..we will have to simplify this power in terms of 6k + r..Hence, we need, Rem[32^32/6] = ?Now, Rem[32^32/6] = 4..Hence, 32^32^32 can be written as 32^(6k + 4) Hence, Rem[32^6k*32^4/7] = Rem[4^4/7] = 4..
@bs0409 said:OA-4.......................(7^11^22^33^44) MOD (5)=??
11^22^33^44%4
(-1)^even = 1
=> (-2)^1%5 = 2 or -3...
EDIT: -2 nahi 2 hoga...
@bs0409 said:@saurav205OA-4.......................(7^11^22^33^44) MOD (5)=??
Is baar 2?
7^4k+1/5...
regards
scrabbler
7^4k+1/5...
regards
scrabbler
@Logrhythm said:(-2)^11^22^33^44%5..11^22^33^44%4(-1)^even = 1=> (-2)^1%5 = -2 or 3...
why -2 rem 7/5 is 2 naa
1> How long is the side of the largest equilateral triangle that can be inscribed in a square whose side has length 1 ?