Official Quant thread for CAT 2013

MBA CAT 2024
20666
@mohitjain said:
Two commandos A and B are equidistant from a target and the three are in a straight line. Another commando C stands equidistant from A and B such that the distance between him and either A or B is the same as the distance between A and B. What is the ratio of the distance between C and the target to the distance between B and the target?
root3 : 1 hai kya?
20667
@iLoveTorres said:
it should be 39 i guess
No, 201 / 5 = 40.2 so 40 or 41. In this case 40 I suppose (would be 41 only if the very first value satisfied, which it doesn't)

regards
scrabbler
20668
@iLoveTorres said:
it should be 39 i guess
How?
I think its 40..
x varies from -96 to 99...with a cd of 5.
It should come to 40 terms...
20669
@joyjitpal said:
root 3 hoga kya?
@iLoveTorres said:
rt3:1?
@iLoveTorres said:
rt3:1?
yes its rt3..
20670
@mohitjain said:
Two commandos A and B are equidistant from a target and the three are in a straight line. Another commando C stands equidistant from A and B such that the distance between him and either A or B is the same as the distance between A and B. What is the ratio of the distance between C and the target to the distance between B and the target?
bhai OA daal...junta ne answer kar diya hai...
20671
@joyjitpal said:
root 3 hoga kya?
@iLoveTorres said:
rt3:1?
@iLoveTorres said:
rt3:1?
yes its rt3..
20672
@amresh_maverick said:
A merchant cheats by using faulty weights to the extent of 12% and 15% at the time of purchasing and selling. Max profit if SP and CP are same ?2 >No of integral sols of : 3x + 5y =47 |x|
2>nos. of solutions is coming out 2 be 40 i.e 23+17
20673
@amresh_maverick said:
A merchant cheats by using faulty weights to the extent of 12% and 15% at the time of purchasing and selling. Max profit if SP and CP are same ?2 >No of integral sols of : 3x + 5y =47 |x|
OA

1> 31(13/17)%
2> 40 solns
20674
@iLoveTorres said:
it should be 39 i guess
40 aya mera bhi
(x ka range.. 99 to -96)
20675
If f(x) = 2x2 + (ab^2 + ac^2 โ€“ 2abc)x + abc and the minimum value of f(x) is at x = โ€“54, then what is the minimum value of (a + 2b โ€“ 2c)? (Given that a > b > c)
20676
@mohitjain said:
If f(x) = 2x2 + (ab^2 + ac^2 โ€“ 2abc)x + abc and the minimum value of f(x) is at x = โ€“54, then what is the minimum value of (a + 2b โ€“ 2c)? (Given that a > b > c)
18 hai kya??
20677
@saurav205 said:
18 hai kya??
yes bro its 18...used d property of a.m>=g.m!!!as xplained by u 2day..
20678
ABCD is a parallelogram. A point E is selected on AD such that BE = 2 ห†ลก6 units.
Also 2AE = 2AB = BD = 8 units and 5CF = BC where F is a point on BC. Find the ratio of the area of quadrilateral DEFC to the area of parallelogram ABCD.
20679
@mohitjain said:
ABCD is a parallelogram. A point E is selected on AD such that BE = 2 ห†ลก6 units. Also 2AE = 2AB = BD = 8 units and 5CF = BC where F is a point on BC. Find the ratio of the area of quadrilateral DEFC to the area of parallelogram ABCD.
7 : 20? Some weird figure I got :(

regards
scrabbler
20680
@scrabbler said:
7 : 20? Some weird figure I got regardsscrabbler
bhai approach??
20681
@saurav205 said:
bhai approach??
Well....BE is a median (apply Appollonius)

So ED = 1/2 long side AD, FC = 1/5 AD so in the trapezium DEFC, 1/2(ED + FC) = 7/20 of AD. Height same. So ratio of areas = 7:20 if I have done this right. Figure bahut ganda sa draw kiya :(

OA?

regards
scrabbler
20682
@amresh_maverick 1> 08
2> k=103
20683
@ChirpiBird said:
40 aya mera bhi (x ka range.. 99 to -96)
meine calculate nahi kiya tha.. it was jus an approximation.. i kno the difficult part would be done by some1 else in this case it was you :p
20684
@scrabbler said:
7 : 20? Some weird figure I got regardsscrabbler
awesom man ....aap toh genius ho!!!
20685
@mohitjain said:
awesom man ....aap toh genius ho!!!
No yaar...just lot of practice...(and a little luck)

regards
scrabbler