Official Quant thread for CAT 2013


@emanresu said:
@noleI did it orally, heres the pic i drew in my mind, dunno f the ans is rite, plz crosscheck with the question giver
yaar thoda explain kar i am not getting it

@Shrutim90 said:
If we rearrange the letters of the word RAINBOW, How many words will be there in which the vowels are never together?According to me the solution should be : 7! - 5!*3!But the solution given in the book (Quantum CAT) is entirely different. Please let me know how to solve this question.
5p3*4! ?
@nole said:
@emanresu from the figure i understood quadrilateral getting divided into 30 each.after that what did u do ? BED traingle me ki sides 6x,6x kaise ai ? same for traingle AEF ?
@joyjitpal said:
how 6x and 5thora explain kar dena bhai

@raopradeep
As areas of 2 triangles you know and they are between the same parallel lines so their height is same but areas in the ratio 36:30 i.e 6:5. hence their bases must be in the ratio 6:5 as area=0.5*base*height
@emanresu thanks 😃 got it . aj bot doubts solve ho gaye :)

Question :


OA in 5 mins.

Question :


Question :


Question :


If we rearrange the letters of the word RAINBOW, How many words will be there in which A is always before I and I is always before O?

@Shrutim90 said:
@YouMadFellowAnswer is 1440
Yeah, forgot to multiply the 4! :splat: .. Out of touch
@saurav205 said:
Question :
8 is the no sides of the polygon
@Shrutim90 said:
If we rearrange the letters of the word RAINBOW, How many words will be there in which A is always before I and I is always before O?
7!/3!

The OAs are :

25
8
243
23/27...

@saurav205 said:
Question 13:
Out of 36 cases, 27 would have at least one odd number..
The only positive scenarios are for 4,5 and 3,6.. 2 cases apiece.
Hence, 23 cases out of 27 are favorable?
Ans: (1)


PS: Here I am, finally getting a prob qstn correct and find the OA posted 5 min back :banghead:
@bluechameleon18 said:
Out of 36 cases, 27 would have at least one odd number.. The only positive scenarios are for 4,5 and 3,6.. 2 cases apiece.Hence, 23 cases out of 27 are favorable?Ans: (1) PS: Here I am, finally getting a prob qstn correct and find the OA posted 5 min back
No one was replying....Probably everyone went for lunch or something....So I posted the OAs...
@saurav205 said:
Question :
8 ?

(2n - 4)*90 = n/2(2*187.5 + (n - 1)(-15))
n = 8 satisfies
@mailtoankit said:
8 ?(2n - 4)*90 = n/2(2*187.5 + (n - 1)(-15))n = 8 satisfies
I have put up the OA for all the questions...
@saurav205 said:
Question :
Shud be 8
20^2004 + 16^2004 - 3^2004 -1 is divisible by
a)317
b)323
c)253
d)91

@joyjitpal said:
20^2004 + 16^2004 - 3^2004 -1 is divisible by a)317 b)323 c)253 d)91
323