@emanresu for 88 2,4,8,11 are the factors but we checking only for 8 and 11 coz if a number is divisible by 8 it should be divisible by 2 and 4 also. that's why we cecking with only 8 ( and not 2,4 ) rite?
yes that's right. like if it is divisible by 6 then it is divisible by 2 & 3. similarly for 8 as 8 can be written as 8=4*2. also as additional info to u for divisibility checking with nos of form 2^n one needs only to check n digits from last with 2^n
so n=1 last digit for divisiblity of 2
n=2 last 2 digits for divisiblity of 4=2^2
n=3 last 3 digits for divisiblity of 2^3=8 and so on.......
In a triangle ABC, three points D,E and F are choosen on sides BC,AB and AC respectively such that DE is parallel to AC and DF is parallel to AB .If the area of the triangle BDE is 36 and that of quadrilateral AEDF is 60,find the ratio of perimeter of triangle CDF to that of triangle ABC.
In a triangle ABC, three points D,E and F are choosen on sides BC,AB and AC respectively such that DE is parallel to AC and DF is parallel to AB .If the area of the triangle BDE is 36 and that of quadrilateral AEDF is 60,find the ratio of perimeter of triangle CDF to that of triangle ABC.
If we rearrange the letters of the word RAINBOW, How many words will be there in which the vowels are never together?According to me the solution should be : 7! - 5!*3!But the solution given in the book (Quantum CAT) is entirely different. Please let me know how to solve this question.
_A_I_O_
Four letters are left and they should be arranged in the gaps, such that middle two gaps have one or more letters in each.
a + b + c +d = 4 , where b,c >=1
=> a + b' + c' + d = 2 => 5C3 ways
Also, A,I,O can be arranged in 3! ways => 5C3 * 3! = 60 ?
If we rearrange the letters of the word RAINBOW, How many words will be there in which the vowels are never together?According to me the solution should be : 7! - 5!*3!But the solution given in the book (Quantum CAT) is entirely different. Please let me know how to solve this question.
seven boxes numbered 1 to 7 are arranged in a row . each is to be filled by either by black or blue ball such that no two adjacent boxes contain blue ball. in how many ways these boxes be filled ?
If we rearrange the letters of the word RAINBOW, How many words will be there in which the vowels are never together?According to me the solution should be : 7! - 5!*3!But the solution given in the book (Quantum CAT) is entirely different. Please let me know how to solve this question.
If we rearrange the letters of the word RAINBOW, How many words will be there in which the vowels are never together?According to me the solution should be : 7! - 5!*3!But the solution given in the book (Quantum CAT) is entirely different. Please let me know how to solve this question.
@emanresu from the figure i understood quadrilateral getting divided into 30 each.after that what did u do ? BED traingle me ki sides 6x,6x kaise ai ? same for traingle AEF ?
