@Estallar12 said:Yeh kisi mock ka question hai.Answer will be 1.
Haa.. It's from CMAT mock..! But if answer is 1, then will all the entities sum up to 80.??
@amresh_maverick said:Hint : Join D to O and C to O . Triangle ODC is an equilateral triangle . Now try
thanx
2*(9*root3 - 3 *pie)
2*(9*root3 - 3 *pie)
@surajmenonv said:first how do u prove its an equilateral triangle?n even if it is ...wat next..if u have solved it in ur notebook take a pic n attach maybe?!
O lies on circumference , hence OD = radius =6 cm similarly OC
and also D is the centre of the arc and circle
and also D is the centre of the arc and circle
@sbharadwaj said:Haa.. It's from CMAT mock..! But if answer is 1, then will all the entities sum up to 80.??
Yeah it will sum up to 50. :)
1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?
2> N =2^2999 * 5^3002 , some of digits of N ?
3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?
PS: 2 min mein solve karo, main 5 min mein dinner karke aata hun
@amresh_maverick said:1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?2> N =2^2999 * 5^3002 , some of digits of N ?3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?
1> 2 (1+4+1+6 =12 =2)
2> 8 ( 125*10^2999)
3> 1*5*2 =10 ..?
10+A+B+C = 9k
a+b+c = 8, 17 or 26
abc divisible by 8
c can be 2, 4, 6 or 8
When c=2
a+b = 6
abc = (1,5),(5,1),(2,4),(4,2),(3,3)
Hence, Only number 1 and 5 satisfy
Hence number is 523152
And we can see it is divisible by 7 also...
@ChirpiBird said:fe(M)=8oak(M)4/3*pi*18*18*18 is oak ball.4/3*pi*r^3 is fe ball4/3*pi*r^3 = (4/3*pi*18*18*18)*oak(M)/fe(M)r=9
yaar samajh nahi aaya r = 9 to radius hua na?? so d = 18 ?
the price of a tv set worth 20000 is to be paid in 20 installments of rs 1000 each. if the rate of interest be 6% per annum(simple),and the 1st instalment is paid at the time of purchase,then value of last installment coverin the interest as well be:
a 1050
b 2050
c 3000
d none
a 1050
b 2050
c 3000
d none
@amresh_maverick said:1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?2> N =2^2999 * 5^3002 , some of digits of N ?3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?PS: 2 min mein solve karo, main 5 min mein dinner karke aata hun
2
8
10 ?
@mailtoankit said:yaar samajh nahi aaya r = 9 to radius hua na?? so d = 18 ?
did right on paper, typed it wrong here , sry.. galti se yahan 18 likh dia.. 18cm is diameter,wahan 9 ana h.
aur r=4.5 aayega.
@amresh_maverick said:1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?2> N =2^2999 * 5^3002 , some of digits of N ?3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?PS: 2 min mein solve karo, main 5 min mein dinner karke aata hun
2>
ans is 8
(2^2999*5^2999)*5^3
(10000...2999 number of zeroes)*125
12500000....2999 zeroes.
sum of digits is 8.
ans is 8
(2^2999*5^2999)*5^3
(10000...2999 number of zeroes)*125
12500000....2999 zeroes.
sum of digits is 8.
@amresh_maverick said:1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?2> N =2^2999 * 5^3002 , some of digits of N ?3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?PS: 2 min mein solve karo, main 5 min mein dinner karke aata hun
3> 10?
not sure though.
got abc as 152.
not sure though.
got abc as 152.
@amresh_maverick said:1> unit digit of 1^2! + 2^3! + 3^4! +......+50^51! ?
5
@amresh_maverick said:2> N =2^2999 * 5^3002 , some of digits of N ?
8
@amresh_maverick said:3> 523abc is divisible by 7,8 9. Find the value of a*b*c ?
@amresh_maverick said:PS: 2 min mein solve karo, main 5 min mein dinner karke aata hun
@ChirpiBird said:2> ans is 8(2^2999*5^2999)*5^3(10000...2999 number of zeroes)*12512500000....2999 zeroes.sum of digits is 8.
or divide by 9 and get the remainder...
Sove for X and Y-
X^1/2 + Y = 2
X + Y^1/2=3