iron weighs 8 times the weight of oak. Find the diameter of iron ball whose weight is equal to that of a ball of oak 18 cm in diameter.?
check the geometry question attached...ignore my ms paint skills...the question is just not getting solved.
Try it guys
ABCD is a square of side 6. The arcs u see are quadrants .
find area of shaded region
@jashholmes said:Q) Find the average of the first 97 natural numbers???
Sum = n*(n+1) /2
AM or average =sum/n = 1/2 (n+1)
n=97 , so 98/2 =49
AM or average =sum/n = 1/2 (n+1)
n=97 , so 98/2 =49
@jashholmes said:Q) the average of 13 papers is 40. The average of the first 7 papers is 42, and of the last seven papers is 35. Find the marks obtained in the 7th paper???
19
@jashholmes said:Q) Find the average of the first 97 natural numbers???
sum of 97/97
(n(n+1))/2*n
97*49/97
49?
@surajmenonv said:check the geometry question attached...ignore my ms paint skills...the question is just not getting solved.Try it guysABCD is a square of side 6. The arcs u see are quadrants .find area of shaded region
ur figure reminded me of special childhood days and MS paint. lolz : sry for spam .
@shinoda said:iron weighs 8 times the weight of oak. Find the diameter of iron ball whose weight is equal to that of a ball of oak 18 cm in diameter.?
9 cm = diameter
PS: Physics ka question ag raha hai
PS: Physics ka question ag raha hai
@jashholmes said:Q) the average of 13 papers is 40. The average of the first 7 papers is 42, and of the last seven papers is 35. Find the marks obtained in the 7th paper???
7*42 + 7*35 - 13*40 = 19
@shinoda said:iron weighs 8 times the weight of oak. Find the diameter of iron ball whose weight is equal to that of a ball of oak 18 cm in diameter.?
9cm?
A tiled floor has dimensions m x n. Dimensions of tile used are n x n.
All tiles are green except diagonal tiles which are red.
After some years, some green tiles are replaced by red tiles to form alternate red green pattern.
How many green tiles were removed? (m not equal to n and total no of tiles odd)
(a) [m^2 + 2(n^2) - 4mn ] / [ 2 (n^2) ]
(b) [ (m-2 (n^2) ) - (n^2) ] / [ 2 (n^2) ]
(c) [ m^2 - 4mn - n^2 ] / [2(n^2)]
(d) [ m^2 - 4mn - 2(n^2) ] / [2 (n^2) ]
Preferrably find the shortest solution :)
@jashholmes said:Q) the average weight of 19 men in a ship is increased by 3.5 KG when one of the men, who weighs 79 KG, is replaced by a new man. Find the weight of the new man up to 2 decimal places???
T/19=A
T=19A
(T-79+new)/19= A +3.5
T- 79 + new = T + 3.5*19
new = 66.5+79
=145.5Kg??
T=19A
(T-79+new)/19= A +3.5
T- 79 + new = T + 3.5*19
new = 66.5+79
=145.5Kg??
@surajmenonv said:check the geometry question attached...ignore my ms paint skills...the question is just not getting solved.Try it guysABCD is a square of side 6. The arcs u see are quadrants .find area of shaded region
Area = (9_/3 - 3*pi)*2
@ChirpiBird said:9cm?
mass of iron = mass of oak
density (iron) = 8 x density of oak
=> (di . 4.pi.r^3) / 3 = (di .4.pi.9^3/) / (3.8)
=> r = 4.5
=> d = 9
@amresh_maverick said:Area = (9_/3 - 3*pi)*2
dont have the answer...give the approach then i can verify buddy
@shinoda said:yep..share ur approach
fe(M)=8oak(M)
4/3*pi*18*18*18 is oak ball.
4/3*pi*r^3 is fe ball
4/3*pi*r^3 = (4/3*pi*18*18*18)*oak(M)/fe(M)
r=9
4/3*pi*18*18*18 is oak ball.
4/3*pi*r^3 is fe ball
4/3*pi*r^3 = (4/3*pi*18*18*18)*oak(M)/fe(M)
r=9
@joyjitpal said:approach bhai
@joyjitpal said:approach bhai
Hint : Join D to O and C to O . Triangle ODC is an equilateral triangle . Now try
@jashholmes said:Q) in a family of 8 males and a few ladies, the average monthly consumption of grain per head is 10.8 KG. In the average monthly consumption per head be 15 KG in the case of males and 6 KG in the case of females, find the number of females in the family???
10.8*(8+f)=15*8+6*f
86.4 +10.8f=120 +6f
4.8f=33.6
f=7
86.4 +10.8f=120 +6f
4.8f=33.6
f=7
@amresh_maverick said:Hint : Join D to O and C to O . Triangle ODC is an equilateral triangle . Now try
first how do u prove its an equilateral triangle?
n even if it is ...wat next..
if u have solved it in ur notebook take a pic n attach maybe?!