@ChirpiBird said:either equate the saving to 9520or subtract the expenditure and then equate to 9520.X- .20X-.12x-.204x=9520x=20000
Your signature, man! Your signature, man!
p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?
0
1
3(p-q)(q-r)(r-p)
(p-q)(q-r)(r-p)
0
1
3(p-q)(q-r)(r-p)
(p-q)(q-r)(r-p)
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
3(p-q)(q-r)(r-p)
@jashholmes said:If the price of rice increases by 45%, how much should one reduce the consumption in order to keep expenditure constant???What is the logic of solving this question???What are the shortcut methods for solving this question???
let price be .. 100
new price is 145
expenditure is constant.
(c*p)/e= (c1*p1)/e
where c1,p1 is new consmption n new price respectively.
or 100*c=c1*145
c1/c=100/145
so change should be (c1-c)/c= 100-145/145 (-ve shows reduction)
somewhere around 31.03%???
new price is 145
expenditure is constant.
(c*p)/e= (c1*p1)/e
where c1,p1 is new consmption n new price respectively.
or 100*c=c1*145
c1/c=100/145
so change should be (c1-c)/c= 100-145/145 (-ve shows reduction)
somewhere around 31.03%???
@jashholmes said:Shyam spends 20% of his monthly income of this household expenditure, 15% of the rest of books, 30% of the rest on clothes and says the rest. On counting, he comes to know that he has finally saved Rs9520. Find his monthly income??? What is the shortcut of solving this type of questions???
speed up ur calculations & u can solve this faster..
it requires to be solved or u can cross check with answers after getting equations.
20000
@jashholmes said:In a class, 25% of the students were absent for an exam. 30% failed by 20 marks and 10% just passed because of grace marks of 5. Find the average score of the class in the remaining students school an average of 60 marks and the past marks are 33 (counting the final scores of the candidates)???a) 37.266b) 37.6c) 37.8d) 36.93
i got 37.6 ....is it right?
@ChirpiBird said:i got 37.6 ....is it right?
consider 100 students.
25 didnt appear.
30 got 13 marks. (33-20)
and 10 got 33 exactly (forget the 5 grace marks .. passing matters.. that's engg blood talking!!! )
rest 35 students got 60 marks.
so class average will be.. (33*10+13*30+35*60)/75=2820/75 =37.6
correct me if i am wrong :)
25 didnt appear.
30 got 13 marks. (33-20)
and 10 got 33 exactly (forget the 5 grace marks .. passing matters.. that's engg blood talking!!! )
rest 35 students got 60 marks.
so class average will be.. (33*10+13*30+35*60)/75=2820/75 =37.6
correct me if i am wrong :)
@ScareCrow28 said:Options kya die h tumne?? Option 4) 1.07...Already been discussed
bhai iska soltn batana iam not getting this
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
3(p - q)(q - r)(r - p) ?
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
3(p - q)(q - r)(r - p) ?
@ChirpiBird said:consider 100 students.25 didnt appear.30 got 13 marks. (33-20)and 10 got 33 exactly (forget the 5 grace marks.. passing matters.. that's engg blood talking!!! )rest 35 students got 60 marks.so class average will be.. (33*10+13*30+35*60)/75=2820/75 =37.6correct me if i am wrong
U are defintly right 
both the answer & remark
@ScareCrow28 said:45*4 =2020+4 = 2424/4 =66-4 = 22*4 = 88+4 = 12..Repetition of operators *, +, / and - with "4" ..Ans 12 hai kya?
may be...bt i like it.
@Cat.Aspirant123 said:steps ?
I put p=1, q=2 and r=3
As for rigorous solution, I have to try that first 
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
3(p-q)(q-r)(r-p)
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
m late
is the answer option 3rd?
circumcentre of triangle ABC is O. /_BAC=85 & /_BCA=75 den /_OAC ?
40
60
70
90
40
60
70
90
@Cat.Aspirant123 said:p q r are real numbers, den (p-q)^3 + (q-r)^3 + (r-p)^3 equals ?013(p-q)(q-r)(r-p)(p-q)(q-r)(r-p)
open with formula..
p^3 + q^3 + r^3 - p^3 - q^3 - r^3 +3pq^2 + 3qr^2 + 3 rp^2 - 3qp^2 -3rq^2 -3pr^2..
clearly 3 *(something) , rest is cancelled... you may go ahead and check further but you may save time and mark c.
Although, do check just in case if they have none of these option.
multiply the (p-q)(q-r)(r-p) given in C option and see it it gives "something" part.
p^3 + q^3 + r^3 - p^3 - q^3 - r^3 +3pq^2 + 3qr^2 + 3 rp^2 - 3qp^2 -3rq^2 -3pr^2..
clearly 3 *(something) , rest is cancelled... you may go ahead and check further but you may save time and mark c.
Although, do check just in case if they have none of these option.
multiply the (p-q)(q-r)(r-p) given in C option and see it it gives "something" part.