@hedonistajay said:Find the number of divisors of 1080 excluding the throughout divisors, which are perfect squares... ??
29..
@hedonistajay said:Find the number of divisors of 1080 excluding the throughout divisors, which are perfect squares... ??
29
@hedonistajay said:is 1 not a perfect square ... ??
i have a doubt in that case
i have not subtracted 1
should we have to do so?
i have not subtracted 1
should we have to do so?
@amresh_maverick said:1>How many perfect squares are the divisors of the product 1!*2!*3!.....8!
iska solution koi dal do :)
@joyjitpal said:i have a doubt in that casei have not subtracted 1should we have to do so?
i am also not sure ... and I do not have OA ..
@ravihanda said:No of zeroes at the end of 25! +26! + 27! + 28! + 30!To understand this, let us understand the basic idea firstWhat will be the number of 0s at the end of a + b + c would depend upon the least number of 0s that any one of a or b or c has. For eg: 300 + 120000 + 17272730 will end in 1 zeroBut, if they have the same number of zeroes, we will also have to consider the last non-zero digit.For eg: 12000 + 161237000 + 1212331000 will not end in 3 zeroes but in 4 zeroes because the last non-zero digits 2, 7 and 1 will add up to generate an extra zero.If you understood the above part, read on.We first need to figure out how many zeroes do the factorials individually haveNumber of zeroes is given by the sum of the quotients obtained by successive division of n by 5.Among the ones mentioned, 25!, 26!, 27! and 28! have 6 zeroes each.30! has 7 zeroes.We also need to consider the right most digits of 25!, 26!, 27! and 28!R(n!) = Last Digit of [ 2^a x R(a!) x R(b!) ]where n = 5a + bUsing this we get, right most non zero digits of 25! as 4 => 26! will end in 4*6 or 4=> 27! will end in 4*7 or 8=> 28! will end in 8*8 or 4=> 25! + 26! + 27! + 28! will not end in 6 zeroes but in 7 zeroesWe know that 30! ends in 7 zeroes.So, the overall number 25! + 26! + 27! + 28! + 30! would end in 7 zeroes
One more step sirjee: we also need to ensure that there is no 8th zero...by combing the last non-zero digit of (30!) and that of (25!+26!+27!+28!) (is case mein nahin hai)
regards
scrabbler
If we express 41(3/17) % as a fraction, then it is equal to???
a) 17/7
b) 7/17
c) 12/17
d) 3/17
a) 17/7
b) 7/17
c) 12/17
d) 3/17
@amresh_maverick said:1>How many perfect squares are the divisors of the product 1!*2!*3!.....8!
Yeh shayad 360 hoga...
Edit: Approach updated below...
regards
scrabbler
Edit: Approach updated below...
regards
scrabbler
@jashholmes said:If we express 41(3/17) % as a fraction, then it is equal to???a) 17/7b) 7/17c) 12/17d) 3/17
700/17 % = 7/17
regards
scrabbler
regards
scrabbler
@amresh_maverick said:My approach: 1! * 2! * 3! * .... * 8! can be broken down into primes as 2^23 * 3^9 * 5^4 * 7^2 (Please check, I might have got this wrong)1>How many perfect squares are the divisors of the product 1!*2!*3!.....8!
Now to get a perfect square n^2 as a factor of this, n can have powers of 2 (from 2^0 till 2^11 - 12 ways), 3 (from 3^0 till 3^4 - 5 ways), 5 (from 5^0 till 5^2 - 3 ways) 7 (from 7^0 till 7^1 - 2 ways) and hence we can choose such an n in 12 * 5 * 3 * 2 = 360 ways. OA please?
regards
scrabbler
The price of sugar is reduced by 25% but in spite of the decrease, aayush ends up increasing his expenditure on sugar by 20%. What is the percentage change in his monthly consumption of sugar???
@scrabbler said:700/17 % = 7/17regardsscrabbler
I reached till 700/17%!!!
But if you convert it into percentage terms then it comes out to be 700x100/17... Then how come it comes out to be 7/17???
By the way your answer is right!!!
But if you convert it into percentage terms then it comes out to be 700x100/17... Then how come it comes out to be 7/17???
By the way your answer is right!!!
@jashholmes said:The price of sugar is reduced by 25% but in spite of the decrease, aayush ends up increasing his expenditure on sugar by 20%. What is the percentage change in his monthly consumption of sugar???
P" = 3P/4
Expen New = 1.2 E
P *Q = E.
3P/4 * Q" = 1.2 E
Dividing both -
3Q"" / 4Q = 6/5
So, Q" = 8/5
So, Increase % = 3/5 = 60 %
@jashholmes said:I reached till 700/17%!!!But if you convert it into percentage terms then it comes out to be 700x100/17... Then how come it comes out to be 7/17???By the way your answer is right!!!
700/17 is already is percentage form.
7/17 was its fractional form IMO. :)
In a class, 25% of the students were absent for an exam. 30% failed by 20 marks and 10% just passed because of grace marks of 5. Find the average score of the class in the remaining students school an average of 60 marks and the past marks are 33 (counting the final scores of the candidates)???
@jashholmes said:I reached till 700/17%!!!But if you convert it into percentage terms then it comes out to be 700x100/17... Then how come it comes out to be 7/17???By the way your answer is right!!!
Fraction to percent, multiply by 100, percentage to fraction, divide by 100!
regards
scrabbler
regards
scrabbler