Use Math or Logic. For example, let's evaluate both (A) and (D).
(A) With the new postage rates, a typical issue under the proposed plan would cost about one, third more to mail than a typical current issue would. - Let's assume the postage currently is $3. So, for one issue with the new postage, it will be $3+1/3rd of $3=$4. So, if they send out 12 issues (without change in subscription amount), the postage would be about $48. Instead, they plan to send out only 6 issues, that would amount to $24 which is lesser than what they are spending right now (12*$3=$36). So, this is actually a saving + profit situation for them. So, it cannot be A.
(D) Most of the advertisers that purchase advertising space in the magazine will continue to spend the same amount on advertising per issue as they have in the past. - Do you see the key here? It's per issue. Now, if the number of issues are reduced from 12 to 6. They can generate only half the amount from advertising. Hence, they will incur a loss.
Hope that helps.
:oops: gr8 logic.. :oops:
but y is this thread so dormant?? puys plz keep this thread alive..
Please suggest some good material for Problem Solving
u r in wrong thread dude.. 😃 but still, solve questions 4m CAT official quant threads.. gmat maths will then look lot easier 😉 kaplan maths is good.. look into OG11 or OG12 math questions as well.. this is juz my opinion.. wait 4 gurus' views..
now 1 DS question.
if a 1. -b 2. -1
one more..
is 2x a multiple of y?
1. 2x+2 is a multiple of y 2. y is a multiple of x
u r in wrong thread dude.. 😃 but still, solve questions 4m CAT official quant threads.. gmat maths will then look lot easier 😉 kaplan maths is good.. look into OG11 or OG12 math questions as well.. this is juz my opinion.. wait 4 gurus' views..
now 1 DS question.
if a 1. -b 2. -1
one more..
is 2x a multiple of y?
1. 2x+2 is a multiple of y 2. y is a multiple of x
for the first one can be answered by either of the two alone
for the second one can be answered by statement 2 alone
Please post the DS questions in the apporpriate thread. This is a thread for problem solving.
Anyways, my answers are given below. Whats the OA?
Q1. Ans B Statement1: -b Multiply each side by (-1) gives: b>a..now b can be any number > -1. Hence insufficient. Statement2: -1 let a = -2; 0let a = -3; 0 let a = -3/2; 0therefore we are getting something of the form 0 Hence sufficient.
Q2. Ans E. Statement1: 2x+2 is a multiple of y For x=1, y=2: 2x is a multiple of y For x=5, y=3: 2x is not a multiple of y. Hence not sufficient. Statement2: y is a multiple of x. Let y = ax. therefore for (2x = by) to be true, b has to be = 2/a. This is true only when a=1 or a=2. (note both a and b are integers). Try putting some numbers. For x = 1 and y = 2: y is a multiple of x and 2x is also a multiple of y. For x = 1 and y = 4: y is a multiple of x but 2x is NOT a multiple of y. Hence not sufficient. Combining the both statments: For x = 1 and y = 2: 2x+2 is a multiple of y; y is a multiple of x; 2x is a multiple of y. For x = 1 and y = 4: 2x+2 is a multiple of y; y is a multiple of x but 2x is NOT a multiple of y. Hence not sufficient.
u r in wrong thread dude.. 😃 but still, solve questions 4m CAT official quant threads.. gmat maths will then look lot easier 😉 kaplan maths is good.. look into OG11 or OG12 math questions as well.. this is juz my opinion.. wait 4 gurus' views..
now 1 DS question.
if a 1. -b 2. -1
one more..
is 2x a multiple of y?
1. 2x+2 is a multiple of y 2. y is a multiple of x
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III
My answer is E, but the answer is given C..Can some one explain ?
Neel for the case 0 0 and c/dgiven d>0,makes c also a positive number,hence I stat is necessary.
Coming to the third statement,consider fraction i.e d=1/2,and c=1/3(this satisfies both I and II.but in III,it does not seem correct,thereby making it NOT necessary.
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III
My answer is E, but the answer is given C..Can some one explain ?
I. c > 0 II. c/d For this I hope there no issue. Just after simplifying the eq we can get the consclusion.
For III. c^2 +d^2 >1 This can't be true all the time. Since from above eq we get c,d>0 but not necessarily integer. Just substitute any value where c+d HTH!
My answer was "I only" but which was not correct, could you please shed some light ??
a)None is the answer...
if the perimeter is
I. 9 then the sides of the traingles are 2,5,2 which is not possible as it violates the rule, sum of two sides should be always greater than the third side...2+2 II. 15 then the sides of the traingles are 2,5,8 which is not possible as it violates the rule, sum of two sides should be always greater than the third side... 2+5 III. 19 then the sides of the traingles are 2,5,12 which is not possible as it violates the rule, sum of two sides should be always greater than the third side...2+5 answer is none !!
Need help here... I wasn't able to understand the question correctly, later I saw the explanation and understood what the question meant. I thought the question meant: The collection consists of various types of oil paintings, IMpressionist, Non Impressionist and maybe some other art. 15% of total was from Impressionist oil painting, 40% Non Impressionist Oil paintings, leaves 45% as rest of art non-oil paintings. and hence got confused while solving it. Do you feel this question is worded ambigiously? What do you do if such ambiguity comes on GMAT? Or such ambigious ones don't come ? This is from a Knewton Test.
In a certain art museum, 15 percent of the collection consists of oil paintings from the Impressionist period. If 40 percent of the oil paintings in the museum's collection are notfrom the Impressionist period, what percent of the museum's collection consists of oil paintings?