hello puys...
hope every1 doing great in GMAT prep. here is a nice one on probability... bit easy and wellknown from MGMAT...
Renne has a bag of candy. The bag has 1 candy bar, 2 lollipops, 3 jellybeans and 4 truffles. Jack takes one piece of candy out of the bag at random. If he picks a jellybean, he chooses one additional piece of candy and then stops. If he picks any non-jellybean candy, he stops picking immidietely. After jack picks his candy, renee will pick a piece of candy. what is the probability that Renee picks a Jellybean?
Its a PS and no options given. it has just 1 correct answer. will post OA soon. good luck!! 
hello puys...
hope every1 doing great in GMAT prep. here is a nice one on probability... bit easy and wellknown from MGMAT...
Renne has a bag of candy. The bag has 1 candy bar, 2 lollipops, 3 jellybeans and 4 truffles. Jack takes one piece of candy out of the bag at random. If he picks a jellybean, he chooses one additional piece of candy and then stops. If he picks any non-jellybean candy, he stops picking immidietely. After jack picks his candy, renee will pick a piece of candy. what is the probability that Renee picks a Jellybean?
Its a PS and no options given. it has just 1 correct answer. will post OA soon. good luck!! :cheerio:
Is the answer 3/10?
Jack pick Jellybean*Jack picks another Jellybean*Renne picks JB+ Jack picks JB* Jack picks any other candy than JB*Renne picks JB+Jack picks any othe candy apart from JB* Renne picks JB
Solution:
3/10(J picks JB)*2/9(R picks JB) + 7/10(J picks non JB)*3/9(R picks JB) = 27/90 = 3/10.
Is it right?
Solution:
3/10(J picks JB)*2/9(R picks JB) + 7/10(J picks non JB)*3/9(R picks JB) = 27/90 = 3/10.
Is it right?
Yup, u got that right in the hole... perfect explanation...
Can someone please help me understand this questions and also the answer:
For a finite sequence of nonzero numbers, the number of variations in sign
is defined as the number of pairs of consecutive terms of the sequence for
which the product of the two consecutive terms is negative. What is the number
of variations in sign for the sequence 1,-3,2,5,-4,-6?
a. One
b. Two
c. Tree
d. Four
e. Five
Another one:
In isosceles triangle RST what is the measure of angle R?
1) The measure of angle T is 100 degree
2) The measure of angle S is 40 degree
a.Statement (1) alone is sufficient, but statement (2) alone is not sufficient
b.Statement (2) alone is sufficient, but statement (1) alone is not sufficient
c.Both statements TOGETHER are sufficient, but neither statement alone is
sufficient.
d. Each statement alone is sufficient
e. statements (1) and (2) TOGETHER are NOT sufficient.
Here I feel that the answer is (d), but GMATPrep says the answer is (a).
In isosceles triangle RST what is the measure of angle R?
1) The measure of angle T is 100 degree
2) The measure of angle S is 40 degree
a.Statement (1) alone is sufficient, but statement (2) alone is not sufficient
b.Statement (2) alone is sufficient, but statement (1) alone is not sufficient
c.Both statements TOGETHER are sufficient, but neither statement alone is
sufficient.
d. Each statement alone is sufficient
e. statements (1) and (2) TOGETHER are NOT sufficient.
Here I feel that the answer is (d), but GMATPrep says the answer is (a).
Can someone please help me understand this questions and also the answer:
For a finite sequence of nonzero numbers, the number of variations in sign
is defined as the number of pairs of consecutive terms of the sequence for
which the product of the two consecutive terms is negative. What is the number
of variations in sign for the sequence 1,-3,2,5,-4,-6?
a. One
b. Two
c. Three
d. Four
e. Five
For the given sequence 1,-3,2,5,-4,-6
1 * -3
-3 * 2
5 * -4
Only 3 pairs of consecutive numbers exist, the product being negative.
Another one:
In isosceles triangle RST what is the measure of angle R?
1) The measure of angle T is 100 degree
2) The measure of angle S is 40 degree
a.Statement (1) alone is sufficient, but statement (2) alone is not sufficient
b.Statement (2) alone is sufficient, but statement (1) alone is not sufficient
c.Both statements TOGETHER are sufficient, but neither statement alone is
sufficient.
d. Each statement alone is sufficient
e. statements (1) and (2) TOGETHER are NOT sufficient.
Here I feel that the answer is (d), but GMATPrep says the answer is (a).
As the equal sides are not mentioned in the question explicitly, take each statement individually & then calculate the other two angles ( these being equal ).
St1 : Other two angles => 40 degree
St2 : Other two angles => 70 degree
agreed. But what do you feel is the answer. From your reply you also seem to say that (d) is the answer.
Another one:
n is a positive integer and product of all integers from 1 to n both inclusive is a multiple of 990.what is least possible value of n:
a.10
b. 11
c. 12
d. 13
e. 14
Another one:
n is a positive integer and product of all integers from 1 to n both inclusive is a multiple of 990.what is least possible value of n:
a.10
b. 11
c. 12
d. 13
e. 14
n should be 11.
PGPEX_aspirant Saysagreed. But what do you feel is the answer. From your reply you also seem to say that (d) is the answer.
Tracing back from the answer, we need to follow a convention then, which I never used before.
While considering triangle RST, ST is to be taken as base & then we can conclude with answer (a).
Can you please explain how you arrived at n = 11 ( thats the right answer).
Thanks for your prompt replies.
Tracing back from the answer, we need to follow a convention then, which I never used before.
While considering triangle RST, ST is to be taken as base & then we can conclude with answer (a).
No. Even in that case I do not agree with you. Even if ST is the base, then, I can conclude angle S and angle T to be equal, in that case, angle R can be (180-40-40 = 100), so I still feel, (d) is the correct answer. Does this makes sense?
Can you please explain how you arrived at n = 11 ( thats the right answer).
Thanks for your prompt replies.
990 = 2 * 3 * 5 * 11.
The highest number in the above list is 11.
Product of 1 to n = 1 * 2 * 3 ........ n
Any number "n" less than 11 will give a product which is missing one of the numbers listed above. Hence, 11 needs to be considered atleast.
990 = 2 * 3 * 5 * 11.
The highest number in the above list is 11.
Product of 1 to n = 1 * 2 * 3 ........ n
Any number "n" less than 11 will give a product which is missing one of the numbers listed above. Hence, 11 needs to be considered atleast.
Thanks. I got the idea.
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies te integer on te card by te next larger integer. If each possible product is between 15 and 200, then te least and greatest integers on the cards could be
a. 3 and 15
b. 3 and 20
c. 4 and 13
d. 4 and 14
5. 5 and 14
Please post your answer with explanation.Thanks!
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies te integer on te card by te next larger integer. If each possible product is between 15 and 200, then te least and greatest integers on the cards could be
a. 3 and 15
b. 3 and 20
c. 4 and 13
d. 4 and 14
5. 5 and 14
Please post your answer with explanation.Thanks!
1*2=22*3=63*4=124*5=20>15
Thus, least integer should be 4.
13*14=18214*15=210>200
Thus, greatest integer should be 13. Answer is C...
What's the OA?
good one from some other forum...
Car B begins moving at 2 mph around a circular track with a radius of 10 miles. Ten hours later, Car A leaves from the same point in the opposite direction, traveling at 3 mph. For how many hours will Car B have been traveling when car A has passed and moved 12 miles beyond Car B?
4PIE-1.6
4PIE+ 8.4
4pie + 10.4
2PIE - 1.6
2pie - 0.8
guys, please provide explanation.
good one from some other forum...
Car B begins moving at 2 mph around a circular track with a radius of 10 miles. Ten hours later, Car A leaves from the same point in the opposite direction, traveling at 3 mph. For how many hours will Car B have been traveling when car A has passed and moved 12 miles beyond Car B?
4PIE-1.6
4PIE+ 8.4
4pie + 10.4
2PIE - 1.6
2pie - 0.8
guys, please provide explanation.
IMO answer is (4 pi - 1.6)
By the time car A starts traveling car B has traveled 20 miles on a track that is 20Pi long i.e. circumference.
so to cover at the relative speed of 5 mph it will take
(20pi - 12) / 5 = 4pi - 1.6 hrs.
What's the OA?