CGL 2012 Tier 2 Preparations and Results

@JS-M said: A number N leaves a remainder 11 when divided by M..and remainder 92 when divided by 8M...what will be the remainder when divided by 4M???1)11 2)46 3)92 4) 38
yr easiest way batao to zara isko solve karne ka......without assumng any value??
gud ques still solvin
@JS-M said:
........
38?

@cbiofficer said:
den
92 z d answr.......
@JS-M said:
yr post check karo questn dala hai??
@JS-M
92 is cuming by two cases is it???
@mickym said:
92 is cuming by two cases is it???
......zara batana to...

an equilateral triangle

each side 12cm
find area of greatest square in it..?

a square each side 6cm

all 4corners cut to make regular octagon
find perimeter
@JS-M said:
......zara batana to...
see u will get this
M= 81/ x1-8x2

Now M = 81 or 27 or 9
but not 9 coz in one eqn remainder is 11
so 81 or 27 possible
take 81
=> x1-8x2=1
so let X1=9
x2= 1
N= 81* 9+ 11= 740
also N= 8*1*81+ 92= 740
so 740 mod 324 = 92

similarly chk with othrs

bhai ye dono ques kro fr mai chla

@cbiofficer said: an equilateral triangle
each side 12cm
find area of greatest square in it..?
432(7+4rt3)
@mickym said:
432(7+4rt3)
wrng
@cbiofficer said:
wrng
ok wait

bhai ans is 36..baaki kal krte h...gudnght @mickym 22 nd @JS-M 22..

@cbiofficer said:
wrng
432(7-4rt3)
@cbiofficer said: an equilateral triangle
each side 12cm
find area of greatest square in it..?
144(7-4sqrt3) ?
@JS-M said:
yr why u assumed X=9 and x2=1??
u can assume any value that satisfy eqn
however u hav to chk that N shud come same from both eqns
u will get same result....
@mickym said:
432(7-4rt3)
mera to 144(7-4sqrt3) aa rha h...?
@blade014 said:
mera to 144(7-4sqrt3) aa rha h...?
side of sqr kitna aaya??
@mickym said:
side of sqr kitna aaya??
12(2-sqrt3)
@mickym said:
side of sqr kitna aaya??
so gye ho lgta h...tada..!! cya