@Brooklyn said:found x^2 , x^32 x^2=2+rt(3)4x^3=3rt(3)+5then i just put values
bhai iska koi fast solution hai toh koi batao???
@Brooklyn said:found x^2 , x^32 x^2=2+rt(3)4x^3=3rt(3)+5then i just put values
@Brooklyn said: yar koi Tier2 fulto explanation do as to wat all mrks will maths paper be of , -ve mrking etcn wat all q nos will dre, types etc
@sscjindabad said:bhai iska koi fast solution hai toh koi batao???
@watsnew24 said:100 q 2 marks each 0.5 negativeas for type syllabus must be known to youq types are diffrent from previous years (considering the pre )
@Brooklyn said:yar isse fast kya hai calculate simply x^2 n x^3 didnt take dat long srslyn wat abt eng ???
@Brooklyn said: @watsnew24 : wat else,how many q from wat topic in eng?? any idea??
itna sannata kyu hai mere bhai???
Find the error..
a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
If cos# + sin#=RT2 Cos# Find Cos# - Sin#
If cos# + sin#=RT2 Cos# Find Cos# - Sin#
the ratio of area of a sector of a circle to the area of a circle is 1:4 if the area of circle is 154cm^2 the perimeter of the sector is .. ???
@watsnew24 said:616 cm^3use tin foil as lateral surface area