CGL 2012 Tier 2 Preparations and Results

@Brooklyn said:
found x^2 , x^3
2 x^2=2+rt(3)
4x^3=3rt(3)+5
then i just put values
bhai iska koi fast solution hai toh koi batao???
@Brooklyn said: yar koi Tier2 fulto explanation do as to wat all mrks will maths paper be of , -ve mrking etc
n wat all q nos will dre, types etc

100 q 2 marks each 0.5 negative

as for type syllabus must be known to you

q types are diffrent from previous years (considering the pre )
@sscjindabad said:
bhai iska koi fast solution hai toh koi batao???
yar isse fast kya hai calculate simply x^2 n x^3 didnt take dat long srsly

@watsnew24 said:
100 q 2 marks each 0.5 negativeas for type syllabus must be known to youq types are diffrent from previous years (considering the pre )
n wat abt eng ???

@Brooklyn said:
yar isse fast kya hai calculate simply x^2 n x^3 didnt take dat long srsly
n wat abt eng ???
200 q 1+ 0.25-
@watsnew24 : wat else,how many q from wat topic in eng?? any idea??
@Brooklyn said:
@watsnew24 : wat else,how many q from wat topic in eng?? any idea??


sab ayega bhai 200 q !!!!!!!!!!!

everything will come all types of q

itna sannata kyu hai mere bhai???

Find the error..

(A) He left for Mumbai on Sunday/ (B) arriving there/ (C) on Monday./(D)No error.
@viksg
@viksg : B ???

a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.

@viksg b
@Brooklyn said:
@viksg
@viksg : B ???
don't know the answer...
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.


616 cm^3

use tin foil as lateral surface area
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
616
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
options ....????
@watsnew24 616 cm^3

If cos# + sin#=RT2 Cos# Find Cos# - Sin#


pLz explain this.....

If cos# + sin#=RT2 Cos# Find Cos# - Sin#


pLz explain this.....

the ratio of area of a sector of a circle to the area of a circle is 1:4 if the area of circle is 154cm^2 the perimeter of the sector is .. ???


@watsnew24 said:
616 cm^3use tin foil as lateral surface area
can you please explain how you did this???