i just want to ask you people one question ye statistics wala paper jo saturday ko hai wo dena jaruri hai kya i mean pata nahin mera subject hi nahin hai statistics fir kyon dikha raha hai admit card main, i m intersted in css only so agar sat ka exam na dun to koi prob to nain hai na, plz clarify
@007pagal said:t=24 units
bhaiya PG jamesbond soln bhi de doh to will be easy to understand , as I donn know the answer..
@nick4uonly said: i just want to ask you people one question ye statistics wala paper jo saturday ko hai wo dena jaruri hai kya i mean pata nahin mera subject hi nahin hai statistics fir kyon dikha raha hai admit card main, i m intersted in css only so agar sat ka exam na dun to koi prob to nain hai na, plz clarify
naah koi fark nahi parega, you will be eligible to be considered for other posts...
@rajbharati said:24 dx(t)/dt =0
thanx bhai got it... meri izzat bacha lee tune... ab chele ram ko kal answr bata doonga...
dx/dt toh velocity hi hoga na.... yaani ki... final velocity zero ho jaayegi jab body rest pe aayega...
@sampras said:thanx bhai got it... meri izzat bacha lee tune... ab chele ram ko kal answr bata doonga...dx/dt toh velocity hi hoga na.... yaani ki... final velocity zero ho jaayegi jab body rest pe aayega...
yup
@sampras said:bhaiya PG jamesbond soln bhi de doh to will be easy to understand , as I donn know the answer..
as the displacement is given,differentiate it once to get dx/dt = velocity and differentiate again to get d^2x/dt^2 = acceleration
now in velocity put t=0 to get u=initial velocity and final velocity is zero
now put all the known values in eqn v = u + at to get the required time
now in velocity put t=0 to get u=initial velocity and final velocity is zero
now put all the known values in eqn v = u + at to get the required time
friends allow me to sign off please... got to go...
good night all ... SD... TC
@sampras said: One qn given by the cand , I could not solve... probably related to kinematics,... of course off the topic, but please bother for solution, ... I forgot those eqns of motion...Q. If the displacement x of a body in linear motion is given by x = (-1/3)t^2+16t+3, where t is the time, then at what time the body comes to rest.??? .... some science student can help..
body comes to rest when v=0=>dx(t)/dt=0
(-1/3)*2t+16=0
1/3t=8
t=24
@sampras said:@samprasnaah koi fark nahi parega, you will be eligible to be considered for other posts...
Bhai, mere ek Semester mein Statistics ka subject tha jo ki semester marksheet mein mention hai. To kaya BTech wala eligilble hoga 15 Sept wale exam ki liye.
@Brooklyn said:if u had statistics as subj in undergrad, then give. Otherwise leave it....
leaving the statistics will create any probs or not ??? i had statistics as one of the subjects in 4th semester of my graduation along with others. m i eligible?
@hasrockzz :then ur eligle. its ur choice if u want to give or not....
if u leave u wont b considered d posts of statiscian and 1 more post
Good Morning All friends, we can discuss our strategies for the tier II Exam on 16.09.12, based on our respective experiences, it would help in finalising a better strategy for taking on the exam...as for me I have already posted on page279 post#5578 and
also by
@mourya09 said: @samprasBhai, mere ek Semester mein Statistics ka subject tha jo ki semester marksheet mein mention hai. To kaya BTech wala eligilble hoga 15 Sept wale exam ki liye.
bhai please go through the notification link.... should have one paper as statistics in your marsheet of final results...
@truly.gone said:isliye bolta hun jiiiiiiiiiiiiiiiiii..................jis maths pe options nehi diya hua, wo maths , maths nehi hain
bhai ye qn kal ke railway ke section engineer ke paper mein aaya tha..maine qn note kiya lekin opn nahi........so sorry...........isi section mein 2 qn thaa... first to maine pahle hi post kar diya hai....second wala bhi put karta hoon...
if x = (root3 + 1)/2
then 4x^3+2x^2 - 8x + 7 is....
if x = (root3 + 1)/2
then 4x^3+2x^2 - 8x + 7 is....
good morning!!
@JS-M said:yr...i have tried it, nd i cudn't find any real factor of thz, must be imaginary.....Not 100% sure dude...
nahi bhai koi imaginary no . option mein nahi tha..though i have put the second qn on reply with truly, go through that it might help u to crack the nut..........
@pathakrahul said:bhai ye qn kal ke railway ke section engineer ke paper mein aaya tha..maine qn note kiya lekin opn nahi........so sorry...........isi section mein 2 qn thaa... first to maine pahle hi post kar diya hai....second wala bhi put karta hoon...if x = (root3 + 1)/2 then 4x^3+2x^2 - 8x + 7 is....
found x^2 , x^3
2 x^2=2+rt(3)
4x^3=3rt(3)+5
then i just put values