@Brooklyn answer kya hai??? rt3:rt2:1 ???
@sampras said: bhai log angrezi mein wat lagaoge kya meri... Darr lag raha hai kahi eng bhi maths ke method se solve karne laga toh... mind set ho gaya hai... I solve maths, discuss maths, talk maths, walk maths, sit maths, sleep maths...still score less in maths (tier i)
ha ha ha ha ha
@sampras said: Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?A.1/9900 B.99/100 C.100/99 D.1000/99Q3. The sum of all digits from 1 to 100 is .....5050/903/901/900Q4. If a sphere of radius r is divided into four identical parts, then the total surface area of four parts is4pi*r^2/ 2pi*r^2/8pi*r^2/3pi*r^2
2) 99/100
3)5050
@JS-M said:2. B3. A4. C ............................my take
bhai 3.C aa raha hai thoda method share karna ...
@sampras said: Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?A.1/9900 B.99/100 C.100/99 D.1000/99Q3. The sum of all digits from 1 to 100 is .....5050/903/901/900
1.)99/100
{1-1/100}
2.)20(1)+19(2)+19(3)+19(4)+.........+19(9)
so answer will be
19*45+20+45
isse answer 920 aayega but woh option nahi hai may be i am doing some calu mistake
but method yeh hi h
@anubhav2011 oye n(n-1)/2 se to 5050 hi aaega...901 kahan aaega???
and sphere waale answer mein.....total surface area ek part ka hoga....1/4 ar(sphere) + ar(two semicircles)=pi R^2 + pi R^2=2pi R^2
no1 dere are 4 such parts of sphere so multiply by 4....and u get 8 pi R^2
and sphere waale answer mein.....total surface area ek part ka hoga....1/4 ar(sphere) + ar(two semicircles)=pi R^2 + pi R^2=2pi R^2
no1 dere are 4 such parts of sphere so multiply by 4....and u get 8 pi R^2
@sampras said: @gudda1122 bhai aap thoda guide karo... quad wala problem... I know the ans but not able to conceptualise..
bhai answer sahi h kya????
@gudda1122 said:bhai answer sahi h kya????
sorry yaar forgot to mention in my post... maine just ratta maar liya hai... kisi foreign author ke book mein tha ... its always cyclic quadrilateral.... but unable to explain it to myself...
@JS-M said:....i thought sme of natural number ........its 903
@JS-M said:....i thought sme of natural number ........its 903
@sampras :Sum of digits of 1-100 walle ka 5050 hai naa??
@gudda1122 said:1.)99/100{1-1/100}2.)20(1)+19(2)+19(3)+19(4)+.........+19(9)so answer will be19*45+20+45isse answer 920 aayega but woh option nahi hai may be i am doing some calu mistakebut method yeh hi h
2*{10*(1+2+3+......+9)}+1
@Brooklyn said:@sampras :Sum of digits of 1-100 walle ka 5050 hai naa??
nhi bhai
plz socho tire 2 ka ye level hai kya
straight formula........
plz socho tire 2 ka ye level hai kya
straight formula........
@Brooklyn said:@sampras :Sum of digits of 1-100 walle ka 5050 hai naa??
bhai 1 to 9 digits nine times appear honge .... and then 1... 10 times, 2.... 10 times,............likewise 9.....10 times
@sampras said:bhai 1 to 9 digits nine times appear honge .... and then 1... 10 times, 2.... 10 times,............likewise 9.....10 times
ohho yar q ki languange ki q le rhe ho aaj sab log!! 
puys...do u have ne link for sample papers??? i need sum practice...im very nervous...plss if u have attachments can u post??
@watsnew24 said:nhi bhaiplz socho tire 2 ka ye level hai kyastraight formula........
bhai samjh nahi aaya ... plz elaborate...
@sampras said:bhai samjh nahi aaya ... plz elaborate...
kuch nhi bhai I knew from start it cant be 5050 u cant give such q
@sampras said:2*{10*(1+2+3+......+9)}+1
bhai as usual silly mistake kar di thi19 zayada add kar diye the
aapka n mera method same hai
bas thoda sa likhne ka fark hai
bhai woh quad wala question try karta hu
yeh batao Active/passive+direct/indirect kaha se padu???10th class se apdha nhi h 😞 
wren n martin hai mere pass