@JS-M said:yr phele kisi post pr explained hai.detail me check plz...
yar meko q nhi smjh aa rha if u can explain wat d q is saying
@pathakrahul said: find out the eqn of the line passing through the point of soln of x+y = 2 and 2x-y = 1......plz give complete soln 1) 2x+3y = 0 2) 2x-3y = 0 3) x= y 4) x = y = 0
x = y ??
bhai log qn I posted in afternoon...
Q1.Solve the equation
sin^7 x +1/sin^3 x = cos^7 x + 1/cos^3 x
Q2.Find the quadrilateral with the largest area given the lengths of its four sides.
@Brooklyn said: the area of a circle whose radius is 8 cm is trisected by two concentric circles the ratio of radii of the concentric circles in ascending order isbtao how to do!!!
rt2:1 hoga bhai answer
bas circles k areas ko equal kar do
@sampras bhai ______//\\______
@gudda1122 said:rt2:1 hoga bhai answerbas circles k areas ko equal kar do@sampras bhai ______//\\______
yar meko q nhi smjh aa rha wat it is sayin can u xplain dat
Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?
A.1/9900 B.99/100 C.100/99 D.1000/99
Q3. The sum of all digits from 1 to 100 is .....
5050/903/901/900
Q4. If a sphere of radius r is divided into four identical parts, then the total surface area of four parts is
4pi*r^2/ 2pi*r^2/8pi*r^2/3pi*r^2
@Brooklyn said:yar meko q nhi smjh aa rha if u can explain wat d q is saying
i think question meant a circle with radius 8 now has 2 concentric circles in it...which are trisecting( yani ki 3 equal hisso me) ...distribute kiya gaya he
abhi ye ratio kiske saaath hogi ??(may b big one ke sath)
radius ke ratio karne he ...
@gudda1122 said:rt2:1 hoga bhai answerbas circles k areas ko equal kar do@sampras bhai ______//\\______
@Brooklyn said:yar meko q nhi smjh aa rha wat it is sayin can u xplain dat
______//\\______ bhaiya
@alkoszzz said: @Brooklyn rt2:1 ??
nope 3 circles hai, btw logic btao yar!! hw d figure will look i cant get dat!!
@sampras : arey sirji ___//\\__
@VENRAG said:i think question meant a circle with radius 8 now has 2 concentric circles in it...which are trisecting( yani ki 3 equal hisso me) ...distribute kiya gaya he abhi ye ratio kiske saaath hogi ??(may b big one ke sath) radius ke ratio karne he ...
thnx got it yar :D
@sampras said: Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?A.1/9900 B.99/100 C.100/99 D.1000/99Q3. The sum of all digits from 1 to 100 is .....5050/903/901/900Q4. If a sphere of radius r is divided into four identical parts, then the total surface area of four parts is4pi*r^2/ 2pi*r^2/8pi*r^2/3pi*r^2
ans 3 is 5050
ans 4 is 8pi r^2
ans 4 is 8pi r^2
bhai log angrezi mein wat lagaoge kya meri... Darr lag raha hai kahi eng bhi maths ke method se solve karne laga toh... mind set ho gaya hai... I solve maths, discuss maths, talk maths, walk maths, sit maths, sleep maths...still score less in maths
@alkoszzz said:ans 3 is 5050 ans 4 is 8pi r^2
bhaiya method bhi bata doh mere paas sirf ans hai soln nahi...
@sampras said: bhai log qn I posted in afternoon...Q2.Find the quadrilateral with the largest area given the lengths of its four sides.
bhai mere ko question samjh nahi aa rha hai
but shayad se answer (side)^2...
reason-
square is an quardilateral
area will be maximum when sides will be as equal as possible
answer kya hai
@Brooklyn said:yar meko q nhi smjh aa rha wat it is sayin can u xplain dat
bhai
question sirf itna sa bol rha hai that
ek bade circle k andar 2 concentric cirlce bana diye
and all these 3 circles have same center
A(1)=A(2)=A(3)
see the figure
bcoz shabdo mein batana muskil tha :P
@sampras said: Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?A.1/9900 B.99/100 C.100/99 D.1000/99Q3. The sum of all digits from 1 to 100 is .....5050/903/901/900Q4. If a sphere of radius r is divided into four identical parts, then the total surface area of four parts is4pi*r^2/ 2pi*r^2/8pi*r^2/3pi*r^2
2. B
3. A
4. C ............................my take
clear hua :)@sampras said: Q2.(1/1*2)+(1/2*3)+(1/3*4) +........................ +(1/99*100) = ?A.1/9900 B.99/100 C.100/99 D.1000/99Q3. The sum of all digits from 1 to 100 is .....5050/903/901/900Q4. If a sphere of radius r is divided into four identical parts, then the total surface area of four parts is4pi*r^2/ 2pi*r^2/8pi*r^2/3pi*r^2
bhai 4th ka solution bata do plz....aa ni raha...
@gudda1122 bhai aap thoda guide karo... quad wala problem... I know the ans but not able to conceptualise..