CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
261
@JS-M said:
sry i thought it wrong...must have seen d watch before proceeding ....
can u plz solve dis coz d way m solving is too lengthy!!!
A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train.
262

If a man can save Rs.5 more every year than he did the year before and if he saves 25 rupees in the first year after how many years will his savings be more than1000 rupees altogether and what will be the exact sum with him

263
@sh.arora10 said: A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train.
is it 268.8 miles ??
264
@J_SRAN said:
plz explain bro
1+ sinA/(1-sinA) = 4+ 2rt3
solve it ......
sinA = rt3/2
A = 60
265
@007pagal said:
is it 268.8 miles ??
244.44 miles
266

anybody please solve this one....was posted earlier


1)the perimeter of the an isosceles triangle is 2p units then the area of the same triangle is?

267
@sh.arora10 said: If a man can save Rs.5 more every year than he did the year before and if he saves 25 rupees in the first year after how many years will his savings be more than1000 rupees altogether and what will be the exact sum with him


options
268
@watsnew24 said:
options
1000
1105
1115
1200
269
@sscjindabad said:
explain...
lcm(1 to 10)-1
this would be
(2^3)*(3^2)*5*7-1=2519
270
@sh.arora10 said:
1000
1105
1115
1200
1000 in 20 yrs....????
271
@sh.arora10 said:
can u plz solve dis coz d way m solving is too lengthy!!!
A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train.
let the distance by which faulty engine traveled is X km and speed S km/h
{80/S+X-80/(3/5S)} - X/3/5S = 1 3/5...........(1)
X/2 = X-80/1.45............(2)
find X from (2) and put in (1)

bt option se kare to in NO TIME....

272
@watsnew24 said:
1000 in 20 yrs....????
answer is 1105 in 17yrs..
but i dnt hw to solve dis :(
273
@JS-M said:
let the distance by which faulty engine traveled is X km and speed S km/h
{80/S+X-80/(3/5S)} - X/3/5S = 1 3/5...........(1)
X/2 = X-80/1.45............(2)
find X from (2) and put in (1)
bt option se kare to in NO TIME....
Let the actual speed of train be X miles/hour.
Let the initial distance covered by train is d1.
After fault its speed will be reduced to 3X/5 miles/hour.
So the distance travelled is (3X/5) * 2 = 6X/5 = d2 ----> (i)
So total distance = X + 6X/5 = 11X/5
Now if the fault had occurred at d1 + 50
3X/5 * 5/4 = d2 - 50 -----> (ii)
subtracting (ii) from (i)
(i) - (ii) = (6X/5) - (3X/4) = 50
9X/20 = 50 or X = 1000/9
So the distance d2 = 133.33 miles
So d1 = 11*1000/(9*5) - 133.33 = 111.11
So total distance is 133.33+111.11 = 244.44 miles
274

c u guys after smetme

275
@sh.arora10 said:
answer is 1105 in 17yrs..
but i dnt hw to solve dis
ek baar q fir se repeat karna....

can't be.....
276
@sh.arora10 said:
answer is 1105 in 17yrs..
but i dnt hw to solve dis
@watsnew24 said:
1000 in 20 yrs....????
yr it will form AP with ist term 25 and common difference 5........U can put number of years as N and find the sum........my take

anz will be 1105 in 17 yrs......
277
@JS-M said:
yr it will form AP with ist term 25 and common difference 5........U can put number of years as N and find the sum........my take
anz will be 1105 in 17 yrs......
yaar 5 + 10 +15 +20...... kar k bhi dekha nhi aa raha

calci pe check kro

actual me to karna yahi hai
278
@sh.arora10 said:
answer is 1105 in 17yrs..
but i dnt hw to solve dis
form an AP.. easiest way.. on the sixteenth year, the sum will come to 1000 and on the 17th year, the savings will be 105.. so total will be 1105
279
@watsnew24 said:
yaar 5 + 10 +15 +20...... kar k bhi dekha nhi aa rahacalci pe check kroactual me to karna yahi hai
yr easy way ..........16/2{50+ (16-1)*5} = 1000
now v need >1000, then it will be (1105)
answer me error ni hai.....
280
@Vineeth555 said:
form an AP.. easiest way.. on the sixteenth year, the sum will come to 1000 and on the 17th year, the savings will be 105.. so total will be 1105
yes bro on 16th year 1000 is coming

so he will stop there...?????