@cbiofficer said: 1+sinx+sin^2 x + sin^3 x......+ infinity= 4 + 2 root 3nd 0 then x equals to=?
@sh.arora10 said: At what time after 3.00 p.m. is the minutes hand of a clock exactly aligned with the hour hand?
3.32.75.............
@sscjindabad said:Explain!!
let, length of her shadow is x.
in 4 sec d gal cover d distance 4.8m
now one rightangle made by d lamp & total dsnce covered by girl plus length of shadow and other is fored by hieght of the girl and her shadow.
by comparing the 2 triangle we can write,
(0.9/3.6)= (x/4.8)
x=1.6m
so the length of the shadow is 1.6m
@ansh099 said: JS-M bro lcm will be 2520 ... which is completely divisible by all numbers so in order to obtain remainder 1 ....we will add 1 to our obtained lcm.. thus the ans will be 2521. correct me if i m wrong.
Bhai instead of adding 1 u shud subtract 1 n answer wud be 2519
@sh.arora10 said:3hr16.36min
Overlapping time = n + n/11 hrs
where n is the no of hrs passed .
here n=3
so overlapping time = 3+ 3/11 hrs = 3 hrs 180/11 minutes = 3 hr 16.36 mins
@cbiofficer said: 1+sinx+sin^2 x + sin^3 x......+ infinity= 4 + 2 root 3nd 0 then x equals to=?
60 degree......
@JS-M said:3.32.75.............
Overlapping time = n + n/11 hrs
where n is the no of hrs passed .
here n=3
so overlapping time = 3+ 3/11 hrs = 3 hrs 180/11 minutes = 3 hr 16.36 mins
@sscjindabad said: to all the puys:I have not yet recieved my admit card though it is available on the site and it has mentioned only post pref n no state pref as was the case in the PDF file containing the marks secured...Its really bothering me ....Comment solicited...
bro, I received my admit card yesterday. No post preferences or state preferences are mentioned in it. In fact, none of my friends haven't. 

@sscjindabad said:Explain!!
first apply formula of tan in triangle ABC then in triangle DEC and then from the equations u can calculate the value of x i.e the length of her shadow
@sh.arora10 said:Overlapping time = n + n/11 hrswhere n is the no of hrs passed .here n=3so overlapping time = 3+ 3/11 hrs = 3 hrs 180/11 minutes = 3 hr 16.36 mins
i took when both In a straight line ............us hisab se thek hai kya ....plz check??
@007pagal said:first apply formula of tan in triangle ABC then in triangle DEC and then from the equations u can calculate the value of x i.e the length of her shadow
in tan^2 A= 2tan^2 B + 1 then cos^2 A + sin^2 B =?
@sscjindabad said:Bhai explain
percentage error in calculating SA of cube = [{(10.02)^2 - 10^2}*6/{10^2}*6]*100
@JS-M said:i took In a straight line ............us hisab se thek hai kya ....plz check??
ya... overlapping of minute and hour hand, it takes place at 3:16 PM.
or
because it takes every single movement of hour hand after 10 minutes when it reaches 03.16pm it aligned first.
@sh.arora10 said:ya... overlapping of minute and hour hand, it takes place at 3:16 PM.orbecause it takes every single movement of hour hand after 10 minutes when it reaches 03.16pm it aligned first.
sry i thought it wrong...must have seen d watch before proceeding ....
