CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
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@gudda1122 said: @sampras bhai
prabhu
\\_________o//
yaar ek baat batao
aapne jo question distribution diya h maths ka woh last year tier-2 par based h ya phir jo is year paper aaa rhe h us par based hai
bhai last year based hai... post mein I have mentioned that... this year I am thinking it will be diff as per trend...
Geo .... 10 Qns
Trigo ... 10 Qns
rest all will remain more or less same...
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@sampras said: @gudda1122 , @JS-M bhai and others who are still awake... Good Night all... allow me to sign off please...neck paining.... feeling to rest...
Gud nyght...........dude
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@gudda1122
bro qns dekh ke jaane ka mann nahi kar raha hai... par fir aane ke liye jaana toh padega hi...see you all tomorrow... better if we can discuss more of strategies now...byeeee
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@sampras said:
@gudda1122
bro qns dekh ke jaane ka mann nahi kar raha hai... par fir aane ke liye jaana toh padega hi...see you all tomorrow... better if we can discuss more of strategies now...byeeee
ha bhai bilkul
:) \m/
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@gudda1122 said:
ya sure bhai tc....miles to go before we sleep
bhai value kya li yeh batao
yr guess kiya tha.........actually 4,4,4,5 rakhe ne 189 aa raha hai........nd ye 256 to ho nahi sakti....so nly vlue satisfying z 232....
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@JS-M said:
yr guess kiya tha.........actually 4,4,4,5 rakhe ne 189 aa raha hai........nd ye 256 to ho nahi sakti....so nly vlue satisfying z 232....
take x=5,y=1,z=5,w=6
we get (5-1)(1+4)(5-1)(6-2) = 4*4*4*4 = 256
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@007pagal said:
take x=5,y=1,z=5,w=6 we get (5-1)(1+4)(5-1)(6-2) = 4*4*4*4 = 256
but all the values must be greatr than 2........
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@JS-M said:
but all the values must be greatr than 2........
......are bhai dhyan nahi diya us taraf to
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@JS-M said:
but all the values must be greatr than 2........
bhai ab sirf 3 din reh gaye hain exam main par mujhe achi feel nahi aa rhi hai....lag rha hai exam acha nahi hoga
english main to bilkul bhi confidence nahi hai
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@007pagal said:
bhai ab sirf 3 din reh gaye hain exam main par mujhe achi feel nahi aa rhi hai....lag rha hai exam acha nahi hoga english main to bilkul bhi confidence nahi hai
yr aisa hi lagta hai last week pe.........don't worry sab acha hoga, last ke 3 din english zadya padho........maths ke sirf formulas padho, don't learn new concepts now.....stick to the basics.........everythng will be supr dupr gud.
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If x+y+z+w = 17.then find the maximum possible value of (x-1)(y+3)(z-1)(w-2),no need to do value check as there are 4 variables.
In these type of questions where multiplication(addition) is given and you have to find the max or min of Addition(Multiplication) ===>Always Use Arithmetic Mean >= Geometric Mean.
Thus using this we get,
(x-1) + (y+3) + (z-1) + (w-2) /4 >= rt{1/4}((x-1)(y+3)(z-1)(w-2)) {root to the power 4}
=>x+y+z+w-1/4>= rt{1/4}((x-1)(y+3)(z-1)(w-2))
=>17-1/4 = 4 >= rt{1/4}((x-1)(y+3)(z-1)(w-2))
=>(x-1)(y+3)(z-1)(w-2) Hence max value is 256.
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good morning everyone 😃

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Good morning puys
1) when 25^25 is divisible by 26, the remainder is ___________

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@sandy73 said: Good morning puys 1) when 25^25 is divisible by 26, the remainder is ___________
25
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How to solve dis:


A wheel rotates 3.5 times in one second. What time in seconds does the wheel take to
rotate 55 radian of angle?
1. 1.5 b. 2.5 c 3.5 d 4.5

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@truly.gone said:
aare tumne usskin jo quote kiya tha, o message maine ek discussion pe bola tha, jismein, ye assume kiya ja raha tha, us din koyi ladki online nehi hain.......bt suddenly u appeared.....our discussions was something out of topic , hum log time pass kar rehe the,,,,,if u dont see the whole discussion u ll nt understand...
ok...............
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@abhi_1234
Answer sahi bhai. plz expln.
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p^2=qy+rz , q^2=rz+px , r^2=px+qy then (x/p+x) + (y/q+y) + (z/r+z) is ??
Answer is 1 .

Help me out as how to approach such problems ?
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@sandy73 said: Good morning puys 1) when 25^25 is divisible by 26, the remainder is ___________
25????
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@rahulshaitan said: good morning everyone
gd mng..............plz answer my query...........mera admit card abhi tk mere ghar nahi pahuncha..............do i need to inform SSC office?.............or just take a print out of the online admit card