and i tried just few values. eg:0,4,8. Needed to get a value which will make the equation -ve. All the other values will be satisfied. 
@Kevin88 You didn't give the options and i tried just few values. eg:0,4,8. Needed to get a value which will make the equation -ve. All the other values will be satisfied.
and i tried just few values. eg:0,4,8. Needed to get a value which will make the equation -ve. All the other values will be satisfied.
@seetharam7
He..he !!!
Actually the sol only tells us the total no of values.
I had got till your eq. Then i solved for b^2-4ac >=0.
Here you will get k = 8,3.
This is were by foolishness kicked in.
The OA had 7,8,9,10 values.
I ticked 9 values (ranging from 0-8) without substituting the limit values back in the original eq
He..he !!!
Actually the sol only tells us the total no of values.
I had got till your eq. Then i solved for b^2-4ac >=0.
Here you will get k = 8,3.
This is were by foolishness kicked in.
The OA had 7,8,9,10 values.
I ticked 9 values (ranging from 0-8) without substituting the limit values back in the original eq
@seetharam7
Was getting the eq as k^2-11k+24>=0. Wanted to know whether this method of solving for real values of k is rt or not in this context ?
About the others Q's,, still waiting to hear back from the others
Regarding the one on increasing no:'s, i think you need not consider distinct alone...1111111 also satisfies rt ?
Still waiting to hear back from ash27winz about the solution..
Considering both 1000 & 2000 : Total No's in purview =1001.
Nos divisible by 2 = 501.
Nos divisible by 3 = 333.
Nos divisible by 6 = 167.
So Ans = 1001-501-333+167=334
Was getting the eq as k^2-11k+24>=0. Wanted to know whether this method of solving for real values of k is rt or not in this context ?
About the others Q's,, still waiting to hear back from the others
Regarding the one on increasing no:'s, i think you need not consider distinct alone...1111111 also satisfies rt ?
Still waiting to hear back from ash27winz about the solution..
Considering both 1000 & 2000 : Total No's in purview =1001.
Nos divisible by 2 = 501.
Nos divisible by 3 = 333.
Nos divisible by 6 = 167.
So Ans = 1001-501-333+167=334
@seetharam7 BTW congrats on the good performance in 1304.
I on the other had a very ordinary outing.... 4 calculation mistakes in QA did me in !!
For S2, wanted to test out whether i had it in me to attempt all 30
I did
!!! & as they say the rest is history 
Got a mediocre score of 91
@raku1989 @pugna @rohan_bhaskar .... Must have ***** it... up , down & sideways !!!
@Kevin88 Your method is right. But i usually apply it only for questions involving equations like "does any real value for k exist ? ". Have never used it in inequalities. :)
Guys...some official commitments kept me busy last couple of days...Got to resume my preps as the D day is getting closer..Giving AIMCAT 1304 tomorrow.
@seetharam7 Congrats buddy for the Century hit!!...
@Kevin88 Sorry for the silence for many of your posts..Ill be active 2mrw onwards.
@Kevin88 hi buddy.i've not given 1304 yet.will give it 2moro morning at 10:00 am.I'll definitely let you know how it turned out :)
@seetharam7 happy to see that ur scores are really improving :). Keep up the good work
@Ash27Winz
Your approach ain't wrong.. i followed the same... (Post your steps & lets take a look at it)..
In the Q, considering 1000 & 2000 will not make a difference as both are not coprime to 2304.
I considered them for easier calculation.
Total No's in purview =1001.
Your approach ain't wrong.. i followed the same... (Post your steps & lets take a look at it)..
In the Q, considering 1000 & 2000 will not make a difference as both are not coprime to 2304.
I considered them for easier calculation.
Total No's in purview =1001.
Nos divisible by 2 = 501.
Nos divisible by 3 = 333.
Nos divisible by 6 = 167.
So Ans = 1001-501-333+167=334
QA/DI 27A 26C 1W == 77
VA/LR 30A 21C 9W == 54
OA 57A 47C 10W == 131 .... RCs were misleading...rest all were fine..but personally I dont think one can expect so easy an Sec 1 in QA for real CAT..anways ATB 😃
Can someone tell me how to approach questions of the kind i have posted below ?
If 'a' and 'b' are integers, 5a + 23b = 58, has
(a) no solution for a
(b) no solution for a > 260 and b > -60
(c) a solution for a between 260 and 285
(d) a solution for b between -67 and -64
@seetharam7 Bro, could you repost options c & d.. cant make head or tail of both options !!!
@pugna Keep up the awesome scores brother !!!
@pugna Keep up the awesome scores brother !!!
(C) a solution for a between 260 and 285
(D) a solution for b between -67 and -64
I am not able to use """" signs in equations !! 
@Kevin88 Yes. The answer is (c). @raku1989 @rohan_bhasker @pugna Can you people come up with a method ?
My AIMCAT 1304 scores
@Sec 1 22C 2W 64
Sec 2 18C 7W 47
OA 40C 9W 111
Not a great score, but happy that it has 3 digits :)
@seetharam7
Try solving it this way.....
5a+23b = 58.
a+(23/5)b = 58/5
ie, Rem(23/5)b has to be 3.
so b is of the form 1+5k.
Substitute this in the main equation and ull get a=7-23k
See the options and find out the ans then.
Option 1 can be true. for k=-1. b=-4 and a=30 satisfy the eqn.
Option 2 for k=-12, a=283 and b=-59. . So option 2 also can be true.
Option 3 is true with the above value of a.
Option4 cannot be possible. Since for k=-13 b=-64 and for k=-14, b=-69. So no values are possible for b between -64 and -67(both exclusive i considered).
So how can the answer be Option 3 here....
AIMCAT 1304
Sec 1 30A 27C 3W........78
Sec2 21A 18C 3W.......51.
Overall....129. (My personal best in this AIMCAT series so far...)
)