CAT 2012 Kerala study group

sharing a question from the prepathon


What is the unit €™s place digit of 13^(15^(17^19))?

1) 3
2) 9
3) 7
4) 1
@joethaliath 3 ?

U mean 3rd option or the 1st ? 😁 my bad

1) 3 ?

answer is 7 😃


I liked the way they solved it..

13^(15^(17^19))?

here , they wrote 15^(17^19) as (16 - 1 ) ^ odd no:

= 4k -1

therefore , 13^ (4k-1) will end in 7 using the cyclicity of the no:3

Nice. I got till the odd number part. I thought 15^odd no would give something ending in 5 and then 13^(4k+1).

😃 btw..congrats on hitting the century mark

I would like to show a "oppikkal" yet kinda effective technique(which many of you might be already using). The following question is from CL Unproc 10.


Given below are a few sentences. Each sentence has a pair of words that are italicised. From the italicised words, select the most appropriate words (A or B) to form correct sentences. The sentences are followed by options that indicate the words, which may be selected to correctly complete the set of sentences. From the options given, choose the most appropriate one.

The government is assessing (A) / accessing (B) every aspect of the situation.
The doctor councilled (A) / counseled (B) her to avoid lifting heavy objects.
She has a flair (A) / flare (B) for painting.
The speaker struck a chord (A) /cord (B) with his audience.

Options
a) ABAA
b) ABAB
c) AABB
d) BBAA

If you look at the options , A comes appears as ans for sentence 1 in 3 options, B comes appears as ans for 2nd sentence in 3 options and A comes as answer for sentence 3 in 3 options . So most probably the answer is of form ABA and an unknown 4th. So if you know the correct alternative for 4th sentence you can answer it within seconds.(Here the correct answer is ABAA).

But we have to be careful as it is an "educational or logical" guess and probability of getting it correct all the time is not 100%.

I usually take chances, especially during the last 5 mins or so and mark 1-2 questions like these. Fortunately I have got them right most of the time.


@joethaliath Thanks man. But a seeing a score of 32 in sect 2 less than month before CAT isn't exactly good. I am sure i got 9 LR questions correct, which means VA 19A 6C 13W. I am analyzing the sect 2 of the previous Aimcats right now.
@spdspd hehe 😃 thanks for sharing it da..sometimes it can catch us off guard like u said.. But its always worth the try!!


@seetharam7 yea..sec2 happens ! abberation may b!! sort it out next time!

Can you guys tell in what sequence you attempt questions in section 2 . I mean, RC first followed by LR sets and so on ? Or some other way ? What is the best way according to you?

@joethaliath , @seetharam7 @Kevin88

Anyways, I have tried various method and the sequence I felt most comfortable with was RC first, LR second and all others later, serially(Be it PJ or para completion) . Since I hate RCs( being too lazy to read) If I keep it for the end, I will just read it like a zombie-without energy and concentration. So I prefer to finish it off first.
@spdspd Dude, i just mentioned that i suck at sect 2. Anyways, i usually follow this order :
VA-LR-RC...first 15 mins for VA..then next 25-30 for LR and final 25-30 min for RC. The reason is simple. After sect 1, need to relax, so i go for the verbal.Then LR is my strong point, so i spent max time on it and get all correct. RCs are always tough for me.

Can someone post any thread that would help me with RCs ?

@spdspd
Jagan, even i generally try & follow the same strategy as seetharam.
However, i tend to change based on the difficulty of the paper & my mindset at the time.





How many numbers between 1000 and 2000 are co prime to 2304??

I approached it by subtracting the prime factor multiples (ie of 2 and 3) from the range. But the answer does not match...
Anyone explain y??

@Ash27Winz

Is the answer 334 ? (1001-501-333+167)
@Kevin88 what are the answers to the questions i solved yesterday ?
@seetharam7
Sorry, was waiting for the others !!
The answer to the log question is rt... the one on arrangement is wrong !!
@seetharam7 said:
I finally got
(4-k)x^2 + 4x + (7-k) >=0
Trial and error
k=0,1,2,3,4,5,6,7....8 values..
when k=8, we get
-4x^2 + 4x -1 >=0....so no value of x will satisfy the inequality...
This is rt.. however regarding the method, did you manually put in all values from 0 to 8 or went about with the options ?
@Kevin88 Ok I didn't get the question correctly. Whether its distinct digits or not. Please post the solution if you can and explain how you solved ash27winz' question