If N is a natural number and N! ends with m zeroes, then the number of zeroes that (5N)! ends with is always
(a) N+(m/2)
(b) (N/5)+m
(c) 5m+1
(d) Cannot be determined
@aishwarya_menon
Could u help me find if my profile is a suitable one to get a call from new IIM's ???
X - 73.6
XII - 84.65
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Work Ex - 6 (As of 03-Sep-2012)
Appearing for CAT... This year....
Could u help me find if my profile is a suitable one to get a call from new IIM's ???
X - 73.6
XII - 84.65
B.E - 73
Work Ex - 6 (As of 03-Sep-2012)
Appearing for CAT... This year....
Gud Morning Team __________/\_________
How many sets of three distinct factors of the number N = 2^6 3^4 5^2 can be made such that the factors in each set has a highest common factor of 1 with respect to every other factor in that set?
a)236 b)360 c)104 d)380 e)None of these
How many sets of three distinct factors of the number N = 2^6 3^4 5^2 can be made such that the factors in each set has a highest common factor of 1 with respect to every other factor in that set?
a)236 b)360 c)104 d)380 e)None of these
236?
Sets of form ( 2^x , 3^y , 5^z) -> 6x4x2=48
Sets of form (1 , 3^y , 5^z) -> 4x2=8
Sets of form (2^x , 1 , 5^z) -> 6x2 = 12
Sets of form (2^x , 3^y , 1)-> 6x4 =24
Sets of form (1 , 2^x x 3^y , 5^z) ->6x4x2 = 48
Sets of form (1 , 2^x x 5^z , 3^y) ->6x4x2 = 48
Sets of form (1 , 5^z x 3^y , 2^x) ->6x4x2 = 48
Total = 48+8+12+24+48+48+48 = 236@seetharam7 said:There are 90 questions in a test. Each correct answer fetches 1 mark, each wrong answer attracts a penalty of 1/4 mark and each unanswered question attracts a penalty 1/8 mark. If a candidate scored 23 marks, what is the minimum no of questions answered wrongly by him ?
Take x, y, z be the number of questions answered correctly, wrongly and unanswered resp.
So X + Y + Z = 90
Also X - Y/4 - Z/8 = 23
ie 8X-2Y-Z = 184
Solvind two equations ull get 9X - Y = 274.
X = (274+Y)/9. ie 274 + Y should be divisible by 9.
So the minimum possible value for Y is 5.
@seetharam7 said:If N is a natural number and N! ends with m zeroes, then the number of zeroes that (5N)! ends with is always
Its N+m. N is a natural number and N! ends with m zeroes means the highest power of 5 in N! is m. Lets assume N = 10. Highest power of 5 in 10!, ie (m) is 2. and in (5*10)! is 12 = N+m.
Sec1 20C 5W.......55
Sec2 17C 7W.......44
OA 99.
Pathetic accuracy in both the sections. I am sure this marks wont even touch 97 percentile mark considering the difficulty level of the paper. It was almost par with the actual CAT standard.
Hope many of you cross 120 mark here....ATB guys...:)
@vinmohcetvmklm : buddy i saw your post in 1306 discussion thread....140+ marks in this paper deserves respect without any doubt.!!! i hope you are from Kerala coz i remember seeing your posts in the same thread. Requesting you to be active in this thread so that we all can get some positive inputs from you in the final days of preparation.
@raku1989 In the 1st question, if you substitute Y=5, you get X=31 and Z=64. Using those values, you won't get marks scored as 23 right ?
and in the 2nd question 5N doesn't mean 5*N. 
@raku1989 In the 1st question, if you substitute Y=5, you get X=31 and Z=64. Using those values, you won't get marks scored as 23 right ?
and in the 2nd question 5N doesn't mean 5*N.
1) Y=5, X=31, Z= 54
2) Yea 5N means 5*N itself...what else it can be?
* is the multiplication function.
@raku1989 Sorry for the 1st question, i thought it was 100 ques 
And 5N DOESN'T mean 5*N. Eg: You took N=10. Then 5N is 510 .
@raku1989 Sorry for the 1st question, i thought it was 100 ques
And 5N DOESN'T mean 5*N. Eg: You took N=10. Then 5N is 510 .
Are you sure about this???
I dont think so....Nyways if it is 5*N ans is N + m.
But if it is dat way i dont know how to find a relation between N and m.
@raku1989 No. Not sure. I forgot where i saw the question and solution also . Totally in a messed up situation. Have been sitting with quant stuff since morning.
. Totally in a messed up situation. Have been sitting with quant stuff since morning. Changed CAT date to Oct 18, morning slot. Taking NMAT on Nov 13. @joethaliath There are lots of weekday slots available.
AIMCAT 1306
QA/DI 14A 11C 3W = 30
VA/LR 25A 19C 6W = 51
OA 39A 30C 9W = 81
@seetharam , my preps is as i told u on on phone 😃 .. going through different quant topics , taking 2 mocks a week .. hovering around the 70-80percentiles