Time speed, work, Alligations and mixtures problems

[ankursanghi]

Originally Posted by estranged_gnrs

answer is 3) 4.17 to A

its mental calc. u can see that A actually sold 1.2 kg sugar,so he shld have got 14.4 mangoes,but he got 15 mangoes.so profit of 0.6,which is 4.17 % of 12.

Rohit

I didn't get the last part... 0.6 is 5% of 12. Did you mean something else??? could u explain?

[eagles_dare13]

he means that 0.6 is 4.17% of 14.4 , which is the number of mangoes he should have got in a no win no loss scenario,

[estranged_gnrs]

Originally Posted by eagles_dare13

he means that 0.6 is 4.17% of 14.4 , which is the number of mangoes he should have got in a no win no loss scenario,

errata!!!

thanks to the eagles who dare.

Rohit

[ankursanghi]

Originally Posted by eagles_dare13

he means that 0.6 is 4.17% of 14.4 , which is the number of mangoes he should have got in a no win no loss scenario,

Got it!! Thanks.

[minali]

hey he s telling he duped with da 1kg wt
500 gm was no where in da picture if he wud have said that 4 every 1000gm ,200 gm were less then we cud have said that he sold 1.2 kg .

confused
plzzzzz help

Originally Posted by estranged_gnrs

answer is 3) 4.17 to A

its mental calc. u can see that A actually sold 1.2 kg sugar,so he shld have got 14.4 mangoes,but he got 15 mangoes.so profit of 0.6,which is 4.17 % of 12.

Rohit

[billa]

Originally Posted by minali

hey he s telling he duped with da 1kg wt
500 gm was no where in da picture if he wud have said that 4 every 1000gm ,200 gm were less then we cud have said that he sold 1.2 kg .

confused
plzzzzz help

yeah. u are right.
the language of the question isnt clear actually.
but jus in case if such a thing comes in the exam. i think u gotta assume tht..seeing the options.

[shivasmiles]

Originally Posted by estranged_gnrs

answer is 3) 4.17 to A

its mental calc. u can see that A actually sold 1.2 kg sugar,so he shld have got 14.4 mangoes,but he got 15 mangoes.so profit of 0.6,which is 4.17 % of 12.

Rohit

Thank you buddy .
Made my life simpler.
The answer is correct.

[eagles_dare13]

HI,
Apart from this forum, can anyone suggest any webiste where we can hone our quant and DI skills..
most of the sites pose very difficult old classics problems whic hneer come in CAt..
and i have no money left to buy abhijit guha )
spent all cash in IMS
frnds pls help

[abhi_g1]

Originally Posted by madhavi

45men can complete a work in 16days. Six days after they started working, 30 more men joined them. How many days will they now take to complete the remaining work??

I'm somehow getting confused...Can somebody ans this Question?

Madhavi

let the work be 720 units therefore work done by each men if the eff is eaqul is 1 unit/day
as all have worked for 6 days therefore work done is equal to 6*45*1 that is 270 units work left is 720-270=450unit
now total men are 45+30 that is 75
hene=ce no of days com to b 450/75=6days

[Ravi Raja]

Originally Posted by madhavi

The graph of x^3 - x^2+2x will cut the X axis at how many points? what will be the co-ordinates of the points at which the graph intersects the X-axis??

Solution:

Equate the expression to 0. Then the values of x thus obtained will give you the co-ordinates of the points at which the curve cuts the x - axis.

One of the values is x = 0.

The remaining two values will be obtained by solving for x^2 - x + 2 = 0

This will give us two values of x, both of which are imaginary. Hence the given curve cuts the x - axis at one point.