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Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Re: Number System
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Re: Number System - 28-08-2008, 01:50 PM

i guess its 72...but m sure this not the correct ans....coz we have 1000 as denom...so ans will b in decimal plz tell the correct ans[/quote]

Hi...i think ques is not very clear...it can be 402 raise to power 257/1000 or (402^257)/1000 but i think in both cases ans wud be 72....acc to me decimal shud not come in to picture cos we look for remainder....can anyone plz post d rite ans...
   
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Re: Number System
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Re: Number System - 29-08-2008, 10:02 AM

Quote:
Originally Posted by prakharc View Post
For d=8:- a=1,b=2,c=3,e can be any number <64
So
Out of given options only d=8 is a possibility where we can have some values for rest numbers
So d=8 can be a solution...rest all can't even be the solution. that's why i chose 8

let's take next highest number i.e. d=5 ..so d^2=25
a=1 nothing else possible...b=2 only value possible....no value for c is possible as for c=3 c^3>d^2.....so d=5 not possible..Since d=5 not possible..smaller number then that are definetely not possible
reminder for 88888888..by 45!
   
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Re: Number System
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Re: Number System - 29-08-2008, 10:05 AM

Quote:
Originally Posted by hieveryone View Post
i guess its 72...but m sure this not the correct ans....coz we have 1000 as denom...so ans will b in decimal plz tell the correct ans
Hi...i think ques is not very clear...it can be 402 raise to power 257/1000 or (402^257)/1000 but i think in both cases ans wud be 72....acc to me decimal shud not come in to picture cos we look for remainder....can anyone plz post d rite ans...[/quote]
can u find reminder for 888888888888......(888 times) by 45!
   
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Re: Number System
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Re: Number System - 29-08-2008, 10:15 AM

Quote:
Originally Posted by krishnamba View Post
Hi...i think ques is not very clear...it can be 402 raise to power 257/1000 or (402^257)/1000 but i think in both cases ans wud be 72....acc to me decimal shud not come in to picture cos we look for remainder....can anyone plz post d rite ans...
can u find reminder for 888888888888......(888 times) by 45![/quote]



is the remainder is 28..


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Re: Number System
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Re: Number System - 29-08-2008, 10:40 AM

Quote:
Originally Posted by masoom View Post
can u find reminder for 888888888888......(888 times) by 45!


is the remainder is 28..[/quote]
I Think the answer is 88..8 (10 times)
How come u are getting 28 as the answer
please post ur approach


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Re: Number System
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Re: Number System - 29-08-2008, 10:43 AM

Quote:
Originally Posted by shivam_01 View Post
is the remainder is 28..
I Think the answer is 88..8 (10 times)
How come u are getting 28 as the answer
please post ur approach[/quote]

yaar actually i am confused

..whether it is 45 or factorial 45...


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Re: Number System
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Re: Number System - 29-08-2008, 04:34 PM

Quote:
Originally Posted by masoom View Post
I Think the answer is 88..8 (10 times)
How come u are getting 28 as the answer
please post ur approach
yaar actually i am confused

..whether it is 45 or factorial 45...[/quote]
in case it is 45 then ur answer is coreect otherwise in case if 45! mine is correct i guesss


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Re: Number System
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Re: Number System - 29-08-2008, 10:31 PM

Quote:
Originally Posted by shivam_01 View Post
is the remainder is 28..
I Think the answer is 88..8 (10 times)
How come u are getting 28 as the answer
please post ur approach[/quote]
hey can u post its process??
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Re: Number System
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Re: Number System - 30-08-2008, 10:10 AM

Quote:
Originally Posted by nidhisoni24 View Post
I Think the answer is 88..8 (10 times)
How come u are getting 28 as the answer
please post ur approach
hey can u post its process??[/quote]
Ya i take on the preoblem is

888888888888......(888 times) by 45!
finding the number of zeros in the 45! that is
[45/5]+[45/25]= 10
so we can write 888888888888......(888 times) as
= 888888888888......(880 times) + 8888..(8times)

since the first term is divisible by 45! so we need to find the remainder of the second term by the 45! that comes out to be 888..8times

not pretty sure but i hope it is correct can any body else post its answer


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Re: Number System
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Re: Number System - 30-08-2008, 11:06 AM

Quote:
Originally Posted by shivam_01 View Post
hey can u post its process??
Ya i take on the preoblem is

888888888888......(888 times) by 45!
finding the number of zeros in the 45! that is
[45/5]+[45/25]= 10
so we can write 888888888888......(888 times) as
= 888888888888......(880 times) + 8888..(8times)

since the first term is divisible by 45! so we need to find the remainder of the second term by the 45! that comes out to be 888..8times

not pretty sure but i hope it is correct can any body else post its answer[/quote]

but i dont how to find remainder whn we have factorail value in denom...can u tell me the approach to use for such prbs
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