Quote:
Originally Posted by shivam_01 hey can u post its process?? |
Ya i take on the preoblem is
888888888888......(888 times) by 45!
finding the number of zeros in the 45! that is
[45/5]+[45/25]= 10
so we can write 888888888888......(888 times) as
= 888888888888......(880 times) + 8888..(8times)
since the first term is divisible by 45! so we need to find the remainder of the second term by the 45! that comes out to be 888..8times
not pretty sure but i hope it is correct can any body else post its answer[/quote]
but i dont how to find remainder whn we have factorail value in denom...can u tell me the approach to use for such prbs