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Originally Posted by sbhaskaran2k Hi One more question of same type. . 1) At 12 noon, A starts by car from P and reaches Q which is 120 km away in 4 hrs. B Starting at Q at 1 p.m can reacah p at 3-40 p.m. When will the distance between then is 7.5 kms.. |
Speed of A ... 120/4 = 30 Km/hr.
Speed of B ... 120/(160/60) = 120*60/160 = 45 Km/hr
At 1 pm, A has travelled 30 Kms. So he is 90 Kms from B when B Starts.
Now since both are moving towards each other, the relative speed is (30+45) = 75 Km/hr.
So in 1 hr and 12 mins, they will meet each other i.e. at 2:12 pm.
There are two instances when there is 7.5 Kms between them.
When they are moving together, they cover 75 kms in 1 hr, so 7.5 kms are covered in 6 mins.
So 6 mins before and after they meet, there is 7.5 kms between them.
Time being
2:06 pm and 2:18 pm 
HTH
Gaurav.