[chetna]

hello ppl

plz suggest me the name of the book u all r referring to.

thanks

[kmdivya]

hi frens,got infy call.......pls help me understand these probs...r the answers correct for these?if yes pls xplain


A lorry starts from Banglore to Mysore at 6.00 A.M, 7.00 A.M, 8.00
am.....10 pm. Similarly one another starts from Mysore to Banglore at 6.00
am,7.00 am, 8.00 am.....10.00pm. A lorry takes 9 hours to travel from Banglore
to Mysore and vice versa.
(i) A lorry which has started at 6.00 am will cross how many lorries. Ans: 10.
(ii) A lorry which had started at 6.00pm will cross how many lorries. Ans: 14(14 is given but i got13).

For every one hour two trains will start at the same time ,one from Bangalore to Madras another

from Madras to Bangalore On parallel tracks. All trains travel with same speed and each train will

take 5 hours to reach the other station.How many trains, one train will meet during the journey?

Ans:10(10is given but i got 11)

[chetna]

first problem
=================
(i have assumed that the concerned lorries are starting from bangalore)

1)If a lorry has started at 6 a.m it will reach its destination at 3pm.
thus it will meet the lorries which have started their journey from mysore from 6 am till 3 pm i.e 10 lorries.......but the lorries which had started their journey from mysore at 9 pm and 10 pm( the prev day) will also reach b'lore at 6 am and 7 am respectively....and which come across the lorry...thus according to me the no of lorries crossing it should be 12.....correct me plz...i might be wrong

2)A lorry which has started it journey at 6 p.m from bangalore will come across the following lorries:-
The concerned lorry starting from b'lore at 6 pm will reach mysore at 3am.

a lorry starting at 9 am from mysore will reach b'lore at 6 pm

thus the lorries starting from mysore at
9 am,10 am,11 am,12 pm,1 pm,2 pm,3pm ,4pm,5 ,m,6 pm,7 pm,8 pm,9 pm,10 pm
will all cross the concerned lorry.

Thus the no of lorries =14

second problem
(i m considering that the train is starting off from bangalore towards madras)
==================
when the train will start its journey from b'lore it will come across the train which has started its journey from madras 5 hours ago.it will reach madras after 5 hours .but when it reaches the madras station it wud stop and its journey wud be over.So even if it meets a train which must starting off from madras ,we won't consider it as its journey is already over and in the question it has been asked to give the no of trains that is coming across during its journey.
so according to me the answer is 10
(5 hours ago+4 ago+3+2+1+at the time the train started+1 hour later+2 later+3 later +4 later)

[Maro16]

guys, in our school in the philippines, our teacher asked us to make a book report about the "SHAKUNTALA" by Kalidasa because we're currently studying Indian literature. I was asked to make a character analysis about every character of shakuntala~I was hoping if you guys could help me out~The project is to be passed on February 3, 2006 (this Friday in the Phil.).

Please~Help me Out~!!

[vineet.nitd]

Originally Posted by chetna

first problem
=================
(i have assumed that the concerned lorries are starting from bangalore)

1)If a lorry has started at 6 a.m it will reach its destination at 3pm.
thus it will meet the lorries which have started their journey from mysore from 6 am till 3 pm i.e 10 lorries.......but the lorries which had started their journey from mysore at 9 pm and 10 pm( the prev day) will also reach b'lore at 6 am and 7 am respectively....and which come across the lorry...thus according to me the no of lorries crossing it should be 12.....correct me plz...i might be wrong

2)A lorry which has started it journey at 6 p.m from bangalore will come across the following lorries:-
The concerned lorry starting from b'lore at 6 pm will reach mysore at 3am.

a lorry starting at 9 am from mysore will reach b'lore at 6 pm

thus the lorries starting from mysore at
9 am,10 am,11 am,12 pm,1 pm,2 pm,3pm ,4pm,5 ,m,6 pm,7 pm,8 pm,9 pm,10 pm
will all cross the concerned lorry.

Thus the no of lorries =14

second problem
(i m considering that the train is starting off from bangalore towards madras)
==================
when the train will start its journey from b'lore it will come across the train which has started its journey from madras 5 hours ago.it will reach madras after 5 hours .but when it reaches the madras station it wud stop and its journey wud be over.So even if it meets a train which must starting off from madras ,we won't consider it as its journey is already over and in the question it has been asked to give the no of trains that is coming across during its journey.
so according to me the answer is 10
(5 hours ago+4 ago+3+2+1+at the time the train started+1 hour later+2 later+3 later +4 later)

Solutions:
1)
a)
the bus goin at 6 am will cross the buses starting at 10 pm the previous night, nd then starting from 6 am to 2pm from the other side ... since the question asks about crossing and not meeting we wont consider the buses when this bus starts it journey and when it ends the journey. means the bus starting at 3 pm from other side should not be taken into consideration as well as the bus reachin at 6 am while that bus's start of journey ,also should not be taken into consideration....
hence total buses it passes will be 1+9=10

b)
similarly,
the buses from 10 am to 10 pm starting from the other side wiill cross the bus starting from the other end. We will again ignore the bus which is reachin at 6 pm towards the starting point as the question asks about the buses crossed.
hence the ans would be 13 buses

2)
Again let us consider a train starting at 6 am.
But here we have to keep in mind that it asks about meeeting and not crossing of trains .hence after this train reaches on the other side at 11 am it will meet the train staring at 11 am from the other side also.but while plying from its starting point we dont consider a meeting wid the train arriving at 6 am from the point of start, since the journey has not yet started.
so , it will meet trains which start at,2am to 11 am...

hence the total number of trains met by any one train will be 10..

[chetna]

Originally Posted by vineet.nitd

Solutions:
1)
a)
the bus goin at 6 am will cross the buses starting at 10 pm the previous night, nd then starting from 6 am to 2pm from the other side ... since the question asks about crossing and not meeting we wont consider the buses when this bus starts it journey and when it ends the journey. means the bus starting at 3 pm from other side should not be taken into consideration as well as the bus reachin at 6 am while that bus's start of journey ,also should not be taken into consideration....
hence total buses it passes will be 1+9=10

b)
similarly,
the buses from 10 am to 10 pm starting from the other side wiill cross the bus starting from the other end. We will again ignore the bus which is reachin at 6 pm towards the starting point as the question asks about the buses crossed.
hence the ans would be 13 buses

2)
Again let us consider a train starting at 6 am.
But here we have to keep in mind that it asks about meeeting and not crossing of trains .hence after this train reaches on the other side at 11 am it will meet the train staring at 11 am from the other side also.but while plying from its starting point we dont consider a meeting wid the train arriving at 6 am from the point of start, since the journey has not yet started.
so , it will meet trains which start at,2am to 11 am...

hence the total number of trains met by any one train will be 10..

oh yes vineet

thanks for the solution.I got the point.But i m not sure about the third solution.Its all about what u assume....So i guess even if my solution would be considered...anyway can u plz tell me which book do u follow.I just wanna the name of the book by shakuntala devi that u guys generally follow

cheers
chetna

[kmdivya]

hi chetna n vineet thanks a lot for ur answers...pls help me sove this

There are 9 coins. Out of which one is odd one i.e. weight is less or more. How many iterations of weighing are required to find odd coin? the answer given is 3....but wat i get is 2

[vineet.nitd]

Originally Posted by kmdivya

hi chetna n vineet thanks a lot for ur answers...pls help me sove this

There are 9 coins. Out of which one is odd one i.e. weight is less or more. How many iterations of weighing are required to find odd coin? the answer given is 3....but wat i get is 2

Solution:

Lets divide the coins in group of 3 each ...
Now since we dont know whether the defective coin is heavier or lighter.So, we take the first 2 groups of three coins and weigh them on a pan balance ..keep each group on either side.

Now there may be two cases ...

Case1: if the balance shows inequality on both sides ..its for
sure that either of these groups has the defective coin.We also take into account that which pan of the balance goes up nd which goes down...(important ) .....(a)
now we take any one group out of this and weigh it with the left third group.
if the balance shows equality then the defective coin was in the other group which we weighed earlier.
or if there is inequality it means the defective coin is in the group common to both the weighing cases we have taken ..
So till now we have considered just 2 steps.
Now after knowing which group of 3 coins has the defective one ...
we will finally take any 2 coins out of the reamining 3 ..nd weigh them ...
if the weight is equal ...then the 3rd coin left is defective . if the weight is unequal .then we see that which side of the pan has gone up and which has gone down.........(b)
now considering the points (a) and (b)
we can easily know the defective coin nd whether it is heavier or lighter ...
This was the worst case scenario .and it took 3 steps to determine the defective coin as well as the fact that whether it was heavier or lighter .
Case2: If the result of weighing first two groups shows equality by the balance ..then the defective coin is in third group..
now since from the previous weighing we dont get an idea whether the coin is lighter or heavier ..
we have to perform two more steps in weighing the remaining three coins which wud perfectly determine the defective coin and whether it is heavier or lighter than the rest coins ...
in the left 3 coins we take any 2...
Case2.1)
if the weight is equal the defective coin is the third ...we can know here the defective coin in only two steps but we cud not determine whether it was heavy or light..
so one more step by weighing the defective coin with one of the equal coins wud determine if the defective coin is heavier or lighter ..although the question doesnt aske us to determine the lightness or heaviness of the coin to be found...
Case2.2)
If by weighing any two coins in the left lot we get inequality. we again weigh one of these two coins with the third one keepin g in mind which side of the pan balance went up and which side went down in the previous weighing.
then in these two steps plus the previous step we wud know that which is the defective coin and is it heavier or lighter..
hence in total 3 iterative steps required ..

[kmdivya]

i totally agree with ur answer...but lemme show u another probs where the answer is a lil diffrnt
There are 6561 balls out of them 1 is heavy.Find the min. no. of times the balls have to be weighed for finding out the haevy ball.
the answer is 8...acc to ur method it shd b 9 isnt it

[msuresh]

friends i posted the que in another thread but i didnt got reply.pls post the solution as fast as possible coz i am preparing for INFY test which is on 5th feb...

1.at a fair i bought 6 pineapples and two jackfruits for rs15.if i could have bought 4 more pineapples for rs14 than jackfruits for rs9.what would be the price of each?

2.the combined ages of reena and seena are 44 and reena is twice as old as seena was then reena was half as old as seena will be when seena is 3 times as old as reena was when reena was 3 times as old as seena.how old is reena?

3.i have 3 squre boards,the surface of the first containing 5 sqr feet more than the second and the second containing five sqr feet more than the third.can u find the exact measurement for the sides of the boards?

4.there r two systems of measuring temp like celsius & farenheit. if 36 in A equals 14 in B and 133 in A equals 87 in B at what temp will the two be equal?

5.IF A= 4,A+B+C+D = D+E+G+H=G+H+I=17..
whats the value of D and G.


advanced thanks...