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Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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msksent msksent is offline
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reply to shiks - 04-10-2005, 10:42 AM

Quote:
Originally Posted by shiks
plz answer this.....

4. Escalator based ques::
There is an escalator and 2 persons move down it. A takes 50 steps and B takes 75 steps while the escalator is moving down. Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps. Find the number of steps in the escalator while it is stationary.

Plz post d ans with exp solns asap.....
Let A takes t time for completing 1 step during which B completes 3 steps. Since A takes 50 steps, the time needed will be 50t and similarly for b time needed will be 25 t. Hence we can make the equations as keeping x as total number of steps
(x -- 50) / 50t = (x--75)/25t which upon simplification will give that
x -- 50 == 2x -- 150 and x= 100 steps.


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04-10-2005, 01:20 PM

hi msksent,
thnx 4 d solns......plz also post d solns 4 d ques 2 & 3....
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Reply to shiks - 04-10-2005, 01:23 PM

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plz answer this.....

2. A clock takes 7 secs to strike 7 ,how long will it take to strike 10?

.
For striking 7, the gap is 6. Hence for the 6 gaps, it took 7 seconds. Hence for 1 gap = 7/6 seconds.
Now to strike 10, gaps are 9. For 9 gaps, time will be 9 * 7/6 = 10.5seconds


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reply to shiks - 04-10-2005, 01:26 PM

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3. A child questions his father, "What is your father's age", to which the father answers "He was aged X in year X^2 (X square) ". If the context is 20th Century, What is his Date of Birth?
In the year X^2, his age is X. In the 20th century, we have years from 1901 -- 2000. But among them only perfect squarer is 1936. Hence in 1936, the age will be 1936^0.5 = 44. Hence he must have born in 1936 -- 44 == 1892.


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04-10-2005, 02:03 PM

Quote:
Originally Posted by msksent
For striking 7, the gap is 6. Hence for the 6 gaps, it took 7 seconds. Hence for 1 gap = 7/6 seconds.
Now to strike 10, gaps are 9. For 9 gaps, time will be 9 * 7/6 = 10.5seconds
xplain a lil more .I think striking 7, the gap is 7 ??? so 1 sec each so for 10 answer will be 10.


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reply to apple - 04-10-2005, 02:34 PM

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xplain a lil more .I think striking 7, the gap is 7 ??? so 1 sec each so for 10 answer will be 10.
For 7 o clock, the clock will strike 7 times. The gap between 1 strike and the other is waht causing the time. Hence for 7 strikes, it has 6 gaps and so on. In these type of problems, this is the methodology.


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04-10-2005, 02:45 PM

Quote:
Originally Posted by msksent
For 7 o clock, the clock will strike 7 times. The gap between 1 strike and the other is waht causing the time. Hence for 7 strikes, it has 6 gaps and so on. In these type of problems, this is the methodology.
got it thanks


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Re: reply to shiks - 08-10-2005, 11:36 AM

Quote:
Originally Posted by msksent
Let A takes t time for completing 1 step during which B completes 3 steps. Since A takes 50 steps, the time needed will be 50t and similarly for b time needed will be 25 t. Hence we can make the equations as keeping x as total number of steps
(x -- 50) / 50t = (x--75)/25t which upon simplification will give that
x -- 50 == 2x -- 150 and x= 100 steps.
hiiiii msksent !!!

m lil dumb at quant so can you plz let me know y time taken by B will be 25t. I dont seem to understand.

Thanks for the patience.

Tinki.
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Re: reply to shiks - 08-10-2005, 11:48 AM

The problem says that A takes 50 steps and B takes 75 steps while the escalator is moving down. Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps. If we assume t as time for A to take 1 step, then in the same time of t B will complete 3 steps. Hence as B has to take 75 steps, time needed will be 75/3 t= 25t. Hope it is clear now.


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Re: reply to shiks - 08-10-2005, 11:57 AM

thanks !!!!!!!!!!!
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