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Originally Posted by gugu
Solve the following sum:-
1. If x+y+z=5 & xy+ yz +zx =3 then the least & largest value of x is:-
(a) 10/3 , 5 (b) -1, 13/3 (c) 17/3 , 7 (d) None of These.
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y = 5-(x+z)
substituting this in xy+ yz +zx =3
=> x(5-(y+z)) + (5-(x+z))z + zx = 3
=> z^2 -(5-x)z + x^2 -5x + 3 = 0
for real z,
(5-x)^2 - 4(z^2 -5z +3) >=0
3x^2 - 10x -13 <= 0
(3x-13)(z+1)<=0
hence the largest and the smalles values are (13/3, -1). Answer option b.