Ratio And Proportionbasic Probs!
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Ratio And Proportionbasic Probs!
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Lightbulb Ratio And Proportionbasic Probs! - 18-03-2005, 11:16 AM

QUESTION 1:
RS.9700 HAS BEEN DIVIDED AMONG X,Y,Z SUCH THAT IF THEIR SHARES ARE REDUCED RESPECTIVELY BY RS.30,20 AND 50, THE BALANCES ARE IN THE RATIO OF 3:4:5.WHAT IS Y'S SHARE?
OPTION: 3180,3220,3253.33, 3200.
QUESTION 2:
THE SUM OF RS.530 IS DIVIDED AMONG A,B,C SUCHTHAT A GETS RS.70 MORE THAN B AND B GETS RS.80 MORE THAN C.WHAT IS THE RATIO OF A AND C?
OPTION: 25:18, 18:10 ,9:5, AND 5:2.
QUESTION 3:
TWO ALLOYS CONTAINING COPPER AND IRON ARE IN THE RATIO OF 5:8 AND 5:3.IF THEY MELTED IN EQUAL QUANTITIES,THE RATIO OF IRON TO COPPER IN THE RESULTANT ALLOY WILL BE?
OPTION: 103:105, 15;24, 3:8 ,105:103.
QUESTION 4:THE INCOME OF A AND B ARE IN THE RATIO OF 3:2 AND THEIR EXPENSES ARE IN THE RATIO OF 5:3.IF EACH SAVE RS.3000.THEN B'S INCOME IS?
OPYION: 10000, 6000,9000,12000.
QUESTION 5:RS.11250 ARE DIVIDED AMONG A,B AND C SO THAT A RECEIVES HALF AS MUCH AS B AND C TOGETHER RECEIVE,AND B RECEIVES 1/4TH OF WHAT A AND C RECEIVE TOGETHER.THE SHARE OFA IS MORE THAN THAT OF B BY-
OPTION:1500,3000,1550,3200.

   
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answers! - 18-03-2005, 11:33 AM

Quote:
Originally Posted by swati_swati
QUESTION 1:
RS.9700 HAS BEEN DIVIDED AMONG X,Y,Z SUCH THAT IF THEIR SHARES ARE REDUCED RESPECTIVELY BY RS.30,20 AND 50, THE BALANCES ARE IN THE RATIO OF 3:4:5.WHAT IS Y'S SHARE?
OPTION: 3180,3220,3253.33, 3200.
answer 3220
soln: 9700 - ( 30 + 20 + 50) = 9600
9600/(3+4+5)=800
800*4 = 3200 ....y's reduced share
3200+20 =3220 ...y's share


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18-03-2005, 11:37 AM

Quote:
Originally Posted by swati_swati
QUESTION 2:
THE SUM OF RS.530 IS DIVIDED AMONG A,B,C SUCHTHAT A GETS RS.70 MORE THAN B AND B GETS RS.80 MORE THAN C.WHAT IS THE RATIO OF A AND C?
OPTION: 25:18, 18:10 ,9:5, AND 5:2.
ans. 5:2
soln.
530 - ((70 +80) + 80) = 300
300/3 = 100 ....C
100 + 150 =250 ...A
A:C = 5:2


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18-03-2005, 11:37 AM

Quote:
Originally Posted by swati_swati
QUESTION 2:
THE SUM OF RS.530 IS DIVIDED AMONG A,B,C SUCHTHAT A GETS RS.70 MORE THAN B AND B GETS RS.80 MORE THAN C.WHAT IS THE RATIO OF A AND C?
OPTION: 25:18, 18:10 ,9:5, AND 5:2.
Amounts are C:B:A = x: x+80: x+150

i.e 3x + 230 = 530. x = 100

A:C = 250:100 = 5:2


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18-03-2005, 11:38 AM

Quote:
Originally Posted by swati_swati
QUESTION 2:
THE SUM OF RS.530 IS DIVIDED AMONG A,B,C SUCHTHAT A GETS RS.70 MORE THAN B AND B GETS RS.80 MORE THAN C.WHAT IS THE RATIO OF A AND C?
OPTION: 25:18, 18:10 ,9:5, AND 5:2.
According to the given problem a has 150 more than c and b has 80 more than c

that implies that c has 100 Rs.

B has 180 Rs.

A has 250 Rs.

And so hence the answer is 5 :2

will post the remaining answers soon........

provided they are not already answered.....

Rahul


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18-03-2005, 11:43 AM

gosh did not imagine that i would be the third person posting that answer......



Rahul


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18-03-2005, 11:45 AM

Quote:
Originally Posted by swati_swati
QUESTION 5:RS.11250 ARE DIVIDED AMONG A,B AND C SO THAT A RECEIVES HALF AS MUCH AS B AND C TOGETHER RECEIVE,AND B RECEIVES 1/4TH OF WHAT A AND C RECEIVE TOGETHER.THE SHARE OFA IS MORE THAN THAT OF B BY-
OPTION:1500,3000,1550,3200.
Equations:

I. A+B+C = 11250
II. A = (B+c)/2
III.B = (A+C)/4

To Find:

A - B

Substituting B+C = 11250 - A in II

Therefore A = 11250/3 = 3750

Now

B+C = 7500
and
4B-C = 3750

i.e. B = 11250/5 = 2250

A - B = 3750 - 2250 = 1500


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jeet gayaaaaa!!!!
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Talking jeet gayaaaaa!!!! - 18-03-2005, 11:48 AM

gosh!!!
dint think there wud be such a fight to answer theser questions first..
andy.


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18-03-2005, 11:49 AM

Quote:
Originally Posted by swati_swati
QUESTION 4:THE INCOME OF A AND B ARE IN THE RATIO OF 3:2 AND THEIR EXPENSES ARE IN THE RATIO OF 5:3.IF EACH SAVE RS.3000.THEN B'S INCOME IS?
OPYION: 10000, 6000,9000,12000.
Lets incomes be 3x and 2x
Expenses be 5y and 3y

We have

3x - 5y = 2x - 3y = 3000

i.e. x = 2y .... y = 3000 and x = 6000

B's income = 2x = 2*6000 = 12000


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18-03-2005, 11:55 AM

Quote:
Originally Posted by swati_swati
QUESTION 3:
TWO ALLOYS CONTAINING COPPER AND IRON ARE IN THE RATIO OF 5:8 AND 5:3.IF THEY MELTED IN EQUAL QUANTITIES,THE RATIO OF IRON TO COPPER IN THE RESULTANT ALLOY WILL BE?
OPTION: 103:105, 15;24, 3:8 ,105:103.
Best way to do this prob is have numbers of parts equal..

1st alloy = 5+8 = 13 parts
2nd alloy = 5+3 = 8 parts.

Taking 104 parts of each

Total parts of copper = 5*8 + 5*13 = 40+65 = 105
And that of iron = 8*8 + 3*13 = 64+39 = 103

Resultant alloy = 105:103


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