Quote:
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Originally Posted by Pinju Hi
Can anyone please solve this problem. If the price of sugar falls by 75/2 %, a person can buy 33 kgs more for Rs.560.If the price had been risen by 75/2 %, how much sugar would he have bought for the same sum ?
1)36
2)40
c)42
d)39
Approach:
I think we can break 75/2 % as 3/8 and then take 5 - 8 -11
as the three ratios...Then how to proceed am not sure...
Please help |
Pls use any existing thread to post new problems.
Answer to this one...
Going by your approach.... Initial price = 8x, After reduction price = 5x
So (560/5x) - (560/8x) = 33
therefore (1/x)*(112-70) = 33
1/x = 33/42 .... or x = 42/33 = 14/11
So new price = 11*(14/11) = Rs.14
Amount of sugar = 560/14 =
40 Kgs i.e. Option (2)
HTH
Gaurav.
PS : Not req. but Kgs at Various cost
Rs. 5x - 88 Kgs
Rs. 8x - 55 Kgs
Rs.11x - 40 Kgs