[richa bhatia]

Question:
A circular table is pushed in one of the corners of the room. The corner is making an angle of 90. There is a spot on the edge of the table that is 9 m away from one of the walls and 8 m away from another (both these walls are the ones which form the corners in ques)
(i) How many such tables are possible?
(ii) what is the diameter of the table?
(iii) If the spot is on the edge which is in between the ponts of contact of the table and walls, then what is the radius of the table?

Question 2:
PQR is a 3 digit no. How many no are thre such tha P^3 + Q^3 + R^3= PQR
I dont have the answer to second ques.. please tel what shud b the approach...

[amitnsitian]

thanks a ton richa

that was a really useful info

[warrior]

Originally Posted by richa bhatia

Question:
A circular table is pushed in one of the corners of the room. The corner is making an angle of 90. There is a spot on the edge of the table that is 9 m away from one of the walls and 8 m away from another (both these walls are the ones which form the corners in ques)
(i) How many such tables are possible?
(ii) what is the diameter of the table?
(iii) If the spot is on the edge which is in between the ponts of contact of the table and walls, then what is the radius of the table?

Question 2:
PQR is a 3 digit no. How many no are thre such tha P^3 + Q^3 + R^3= PQR
I dont have the answer to second ques.. please tel what shud b the approach...

qn1:

(i) two tables are possible
(ii) 10, 58 are the diameter
(iii) what are you trying to ask?is the ans 5

[Dhaval Patel]

Originally Posted by warrior

qn1:

(i) two tables are possible
(ii) 10, 58 are the diameter
(iii) what are you trying to ask?is the ans 5

warrior can u explain how?

[tac007]

Originally Posted by bhars18

Hi,

Take the chord as AB with centre C. Let O be the centre of the circle. COD is the perpendicular bisector of AB to the major arc. By the problem, AB = CD = 36.

Let the circle be of radius r. So, the lengths OD = OA = OB = r.
OC = CD - OD = 36-r.
In triangle COA (or COB for that matter) applying pythogoras theorem,
(36-r)^2 + 18^2 = r^2

Solving for r, we get r = 22.5.

Hope that helps.

Regards,
Bharathi.

the solution is ok..but if the PERPENDICULAR does not go through the CENTRE of the CIRCLE then this solution no possible..correct me if i am wrong..thanx

[shashank3012]

Originally Posted by tac007

the solution is ok..but if the PERPENDICULAR does not go through the CENTRE of the CIRCLE then this solution no possible..correct me if i am wrong..thanx

hi tac,

i hope you have seen the date of the post you are replying to.please avoid replying to old threads.post in the active threads instead.

Thread closed.