give me this ten digit number

[ankushgrover]

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this is a ten digit number,starting from the left the first digit is divisible by 1, first two digits are divisible by 2(ex. 12), first 3 digits are divisible by 3(ex 126)....and so on till the 10 digit number is divisible by 10.
you can use any digit from 0-9 only once.
it took me one hour to solve this(ya i'm that bad at quant ... how fast can you answer this?

[QuintEssence]

Originally Posted by ankushgrover

- - - - - - - - - -
this is a ten digit number,starting from the left the first digit is divisible by 1, first two digits are divisible by 2(ex. 12), first 3 digits are divisible by 3(ex 126)....and so on till the 10 digit number is divisible by 10.
you can use any digit from 0-9 only once.
it took me one hour to solve this(ya i'm that bad at quant ... how fast can you answer this?

d00d..plz post ur question here

BTW the last digit should be zer0 ..the fifth should be 5

http://www.pagalguy.com/cat/viewtopic.php?t=772

[capricious]

1472583690

Nice problem, it was mindboggling but I enjoyed every bit of it.
I'm not sure if there are other such no.s, if yes then do let me know.

My approach:

Let the face value notation be abcdefghij

so j=0, e=5 obvious. Some of digits 0-9 is 45 which is multiple of 9 so we'll find other no.s and 'i' will be the left one,as it satisfies its property inherently.
b,d,f,h should be even
so a,c,g,i should be odd.
as c is odd so d can be either 2 or 6(abcd%4=0)
similarly h can be 2 or 6.
b,f can be hence 4,8.
Now after hit and trial I got the above answer.
Notice the sequence in no.s 1-4-7-2-5-8-3-6-9-0. Beautiful, isn't it?

[whocarez]

Originally Posted by capricious

1472583690

Nice problem, it was mindboggling but I enjoyed every bit of it.
I'm not sure if there are other such no.s, if yes then do let me know.

My approach:

Let the face value notation be abcdefghij

so j=0, e=5 obvious. Some of digits 0-9 is 45 which is multiple of 9 so we'll find other no.s and 'i' will be the left one,as it satisfies its property inherently.
b,d,f,h should be even
so a,c,g,i should be odd.
as c is odd so d can be either 2 or 6(abcd%4=0)
similarly h can be 2 or 6.
b,f can be hence 4,8.
Now after hit and trial I got the above answer.
Notice the sequence in no.s 1-4-7-2-5-8-3-6-9-0. Beautiful, isn't it?

Incorrect answer my friend! Check for 1st 8 digits they are not divisible by 8 (just check 836 which is not divisible by

Correct answer would be 3-2-1-6-5-4-7-2-9-0

[erudite79]

wrong answer as well,2 is being used twice and there is no clue about 8,tricky prob i guess,

[whocarez]

oh that was a typical typo its

3-8-1-6-5-4-7-2-9-0

well i was thinking about the divisibility of 2 and wrote 2 instead of 8. Silly of me

[capricious]

yes kids, u r right. I was wrong. But I think my approach was right, I must have missed up something in my way! But, what did I miss?

[sandyee4u]

12640256810




it took me 6 minutes, i put on the stop clock

[rahulatcloudnine]

Originally Posted by sandyee4u

12640256810




it took me 6 minutes, i put on the stop clock

hey sandee...

Looks like u have forgotten that u can use every number only once from 0-9.

Hope u regain ur senses and read the previous posts before posting something......

Rahul

[khanna_sumit]

Originally Posted by ankushgrover

- - - - - - - - - -
this is a ten digit number,starting from the left the first digit is divisible by 1, first two digits are divisible by 2(ex. 12), first 3 digits are divisible by 3(ex 126)....and so on till the 10 digit number is divisible by 10.
you can use any digit from 0-9 only once.
it took me one hour to solve this(ya i'm that bad at quant ... how fast can you answer this?

first of all this number should start with 9 and end with 0(think why)........and by the way i have found one such number......with little logic and little guesswork.....and i have a hunch that there should be more than one numbers of this kind....one i have found is this

9678345120