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Originally Posted by nutz83 @ Sat Nov 13, 2004 8:56 am
Please do solve this in detail...I have no clue abt races
Ram and Shyam run a race of 2000m.first ram gives shyam a start of 200 m and beats him by 30 s.Next, ram gives Shyam a start of 3 mins and is beaten by 1000 metres.Find the time in minutes in which Ram and Shyam can run the race separately.
Ans : 4 mins and 5 mins
By the way , isn't it unlikely a calender problem will come again??  ...since it came last year...
thanks
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I m using simple time-speed-distance relationships to solve this one...
Shud state that i m usually apprehensive taking up such prob. in the actual test..
Here is wat we can interpret from the two races...
1) In the first race Shyam gets 200 m start... i.e. he has to run only 1800m..
So (Time taken by Ram to run 2000m) = (Time taken by Shyam to run 1800m) - 30
Let speeds be R and S, therefore the equation becomes..
(2000/R) = (1800/S) - 30
2) Ram starts 3 mins after Shyam and losed by 1000m
Hence (Time taken by Ram to run 1000m) = (Time taken by Shyam to run 2000m) - 180
i.e. (1000/R) = (2000/S) - 180
Now solving this for (1/R) and (1/S)...we have
R = (25/3) and S = (20/3)
To find time taken....
For Ram = (2000/R) = 240 = 4 min.
For Shyam = (2000/S) = 300 = 5 min.
Hope i m clear...
Gaurav.