Please solve this Q from CL - FLT

[vineet.nitd]

2. The shopkeeper never sells for a loss. If he shuts his shop after 10 hours due to this principle and there was exactly one hour when the number of customers was 10. The number of hours when the number of customers is more than 10 is

a. 0 b. 1 c. 2 d. 3





Solution ::

the shop will be closed only when the customer in the 10 th hr are less than 10.
and also the SP is 440 per item in 10 th hr ...



if we consider a trend in a continuous period in which in every hr the customers are less than 10 ,
then in the 3rd hr the SP must be 510 per item so as to make the SP in 10th hr as 440 with less than 10 customers ......


in the 1st hr ..as per Shopkeeper's principle , we can have 500 as SP only ....

So the increase is from 500 to 510 in the second hr nd in the 2nd hr only 10 customers visit that makes SP as 510 ,

also for the 3rd hr ..So more than 10 customers visit only in 1 hr

Hence 1 year is the solution

[Munira Lokhandwala]

Originally Posted by thakarsagar

2) See , the only possible sequence at which he can sell is...(ie if we are required to find the min no of hours when the no of customers is > 10)

500, 490,480,470,460,450,440,440,450,440

It increases only once.

You are right. I should know I had made the question while in CL