Quote:
Originally Posted by vivekimmortal
a composite no. has 720 factors, if the no of distint prime factors is max possible, what is the no of pairs of factors which are coprime to each otherand whose product is the given no.
a...8
b...64
c...32
d...16
e...4
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720 = 2*2*2*2*3*3*5
For Max distinct prime factors, Number = a * b * c * d * (e^2) * (f^2) * (g^4) {Where a,b,c,d,e,f,g are Prime numbers}
So Required Ans = 2^(7-1) = 64