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Official Quant thread for CAT 09-III (September onwards)
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:04 PM

Hello people,

Seeing the frenetic pace at which the official quant thread is running,it has raked up 10k posts in 3 months So,here comes another "new thread" for the same.The link for the old threads are:

Official Quant thread for CAT 09-I (till July):http://www.pagalguy.com/forum/quanti...at-2009-a.html (official quant thread for CAT 2009)

Official Quant thread for CAT 09-II (July onwards):http://www.pagalguy.com/forum/quanti...-cat-09-a.html (Official Quant thread for CAT 09-II [July 09 onwards])

I hope not many groan at the post .I know this is not convenient but,am trying to make it as easy as possible for all of us.

Please continue on this thread till CAT 09

Cheers,
Shashank


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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:08 PM

Find the digit sum of the number (ab3cdefghi1)^43, where a, b…. h and i are nine distinct single digit natural numbers. (Digit sum of 926 = 9 + 2 + 6 = 17 = 1 + 7 = 8

Last edited by bhupi3149; 24-09-2009 at 03:19 PM.
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:16 PM

Quote:
Originally Posted by bhupi3149 View Post
Find the digit sum of the number (ab3cdefghi1)43, where a, b…. h and i are nine distinct single digit natural numbers. (Digit sum of 926 = 9 + 2 + 6 = 17 = 1 + 7 = 8
Is 43 the base or should be multiplied by ab3.....
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:20 PM

Quote:
Originally Posted by ved87 View Post
Is 43 the base or should be multiplied by ab3.....

edited the post its ^43
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:21 PM

Quote:
Originally Posted by bhupi3149 View Post
Find the digit sum of the number (ab3cdefghi1)43, where a, b…. h and i are nine distinct single digit natural numbers. (Digit sum of 926 = 9 + 2 + 6 = 17 = 1 + 7 = 8
It will be remainder by 9
(9+4)^43 mod 9

So 4.

@Shashank
The rate at which it's going ull have to open another thread by cat !!!
Jai ho pagal guy ki

Last edited by apocalyptic; 24-09-2009 at 03:24 PM.
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:27 PM

Answer the questions on the basis of the information given below.
545 containers were shifted by a certain number of men and the job took 5 working days to complete.
Everyday after the first day 6 more men were put on the job as a result of which each man had to shift 5 fewer containers than what he shifted on the previous day.

What was the total number of containers shifted on the 3rd day?
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:38 PM

Quote:
Originally Posted by bhupi3149 View Post
Answer the questions on the basis of the information given below.
545 containers were shifted by a certain number of men and the job took 5 working days to complete.
Everyday after the first day 6 more men were put on the job as a result of which each man had to shift 5 fewer containers than what he shifted on the previous day.

What was the total number of containers shifted on the 3rd day?
Is it 169..
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:46 PM

Quote:
Originally Posted by bhupi3149 View Post
Answer the questions on the basis of the information given below.
545 containers were shifted by a certain number of men and the job took 5 working days to complete.
Everyday after the first day 6 more men were put on the job as a result of which each man had to shift 5 fewer containers than what he shifted on the previous day.

What was the total number of containers shifted on the 3rd day?
Let on the third day the number of men be x and they shift y containers per day

By statements
(X-12)(y+10)+(x-6)(y+5)+xy+(X+6)(y-5)+(x+12)(y-10)=545
Or 5xy-300=545
Xy=845/5
=169


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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:52 PM

Quote:
Originally Posted by apocalyptic View Post
It will be remainder by 9
(9+4)^43 mod 9

So 4.
@apocalyptic: Can you please elaborate the steps that you followed to arrive at the result? Are there any shortcuts? Thanks in adv.

Last edited by PwnThatCAT!!!; 24-09-2009 at 03:53 PM. Reason: typo
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Re: Official Quant thread for CAT 09-III (September onwards) - 24-09-2009, 03:55 PM

third thread of the season for quants

spamming is heavy of late


anyways answer for the above question is 169

time for thanks/groans


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