[uhhh...]

Originally Posted by Kashyap Rastogi

This is a question from IIFT. Posted this earlier too, but no response. Somebody please share the approach to such questions. If it has appeared in IIFT paper, it must have a soln..

i was trying a taylors for the inverse problem .. its cumbersome.. but only yaw tuo

[sd7]

sorry to post this DI problem here. can anyone plz provide the solution.


The following table gives the distributions of 100 business schools based on the scores obtained by them in five different parameters. the max possible score in any of these parameters is 100.

1. What is the min no. of schools which could have scored 40 points or more but less than 80 points in at least two of the five parameters? a) 0 b) 13 c) 16 d) 18

2. what is the max no. of schools which could have scored 40 points or more but less than 60 points in atleast 3 of the 5 parameters. a) 22 b) 24 c) 9 d) 15

Please give your approach.

[Kashyap Rastogi]

<<<snipped>>>

[sriny_97]

In a country, the currency consists of a set of notes of different denominations.if the sum of all denominations is 63 units of currency, then what is the minimum number of denominations that can be there so that all the transactions can be made (in integers)?
a.3
b.5
c.6
d.9
e.cant be determined

============================================
A retailer has n stones by which he can measure(weigh) all quantities from 1kg to 121 kg(in integers only) by keeping these stones on either side of the balance.what is the minimum value of n?
a.3
b.4
c.5
d.11
e.none of the above

==============================================
the value of 1+(2/3)+(4/9)+(6/27)+(8/81)+(10/243)+.....is
a..2/3
b..5/2
c..19/45
d..81/27
e..none of the above

plz explain methods used...thq

[sachinverma]

HAS ANYONE SOLVED QUANTEXPERT NOVEMBER QUANT CONTEST QUESTIONS.
I AM GETTING 6 AS THE ANSWER FOR THE 1ST QUESTION.
PLEASE CONFIRM IF I M RIGHT
www(dot)quantexpert(dot)in

[shashankmishra]

Originally Posted by sriny_97

In a country, the currency consists of a set of notes of different denominations.if the sum of all denominations is 63 units of currency, then what is the minimum number of denominations that can be there so that all the transactions can be made (in integers)?
a.3
b.5
c.6
d.9
e.cant be determined

============================================
A retailer has n stones by which he can measure(weigh) all quantities from 1kg to 121 kg(in integers only) by keeping these stones on either side of the balance.what is the minimum value of n?
a.3
b.4
c.5
d.11
e.none of the above

==============================================
the value of 1+(2/3)+(4/9)+(6/27)+(8/81)+(10/243)+.....is
a..2/3
b..5/2
c..19/45
d..81/27
e..none of the above

plz explain methods used...thq

(1) The denominations will follow powers of two.......
So 1 , 2 , 4 , 8 , 16 , 32 = 6 in number.......



(2) The weight of stones will follow powers of three.......
So 1 , 3 , 9 , 27 , 81 = 5 in number.......



(3) It is an AGP.....
Let
S = 1+(2/3)+(4/9)+(6/27)+(8/81)+(10/243)+.....

3S = 3 + 2 + 4/3 + 6/9 + 8/27..........

Subtracting..........

2S = 4 + 2/3 + 2/9 + 2/27 + 2/81...........

S = 5/2

[Kashyap Rastogi]

Originally Posted by sd7

sorry to post this DI problem here. can anyone plz provide the solution.


The following table gives the distributions of 100 business schools based on the scores obtained by them in five different parameters. the max possible score in any of these parameters is 100.

1. What is the min no. of schools which could have scored 40 points or more but less than 80 points in at least two of the five parameters? a) 0 b) 13 c) 16 d) 18

2. what is the max no. of schools which could have scored 40 points or more but less than 60 points in atleast 3 of the 5 parameters. a) 22 b) 24 c) 9 d) 15

Please give your approach.

1. 0
2. 15

Not very sure.. What's the OA??

[Kashyap Rastogi]

Originally Posted by shashankmishra

(1) The denominations will follow powers of two.......
So 1 , 2 , 4 , 8 , 16 , 32 = 6 in number.......



(2) The weight of stones will follow powers of three.......
So 1 , 3 , 9 , 27 , 81 = 5 in number.......



(3) It is an AGP.....
Let S = 1+(2/3)+(4/9)+(6/27)+(8/81)+(10/243)+.....
3S = 3 + 2 + 4/3 + 6/9 + 8/27..........

Subtracting..........

2S = 4 + 2/3 + 2/9 + 2/27 + 2/81...........

S = 5/2

Can you please eleborate a bit on the first two Qs.. Why powers of 2 and 3??

[shashankmishra]

Originally Posted by Kashyap Rastogi

Can you please eleborate a bit on the first two Qs.. Why powers of 2 and 3??

Refer to the following post, also see near by posts............

http://www.pagalguy.com/forum/cat-an...ml#post1681746 (The PG Dream Team' 09)

[sachinverma]

Originally Posted by sachinverma

HAS ANYONE SOLVED QUANTEXPERT NOVEMBER QUANT CONTEST QUESTIONS.
I AM GETTING 6 AS THE ANSWER FOR THE 1ST QUESTION.
PLEASE CONFIRM IF I M RIGHT
www(dot)quantexpert(dot)in

Try this:
How many ordered pairs (x,y) of integers are possible for xy/(x+y) = 196?
Source:quantexpert(dot)in