[certified.pagla]

Originally Posted by smiyc

a,b,c are in AP
>> 2b = a+c
>> 3b = 3/2
>> b = 1/2
>> a+c = 1

a^2,b^2,c^2 are in GP
>> b^4 = a^2*c^2
>> b^2 = ac {b^2 can't be equal to -ac .. as b is real)
>> ac = 1/4

(a-c)^2 = (a+c)^2 - 4ac = 0

a=b=c ... which contradicts with given a<b<c ...

pls check the question

Because it is not given that a and c both are positive/negative, we can take b^2 = -ac.

[santosh.baksi]

Ashish is given Rs.158 in one rupee denomination. He has been asked to allocate them into a number of bags such that any amount required between Re.1 and Rs.158 can be given by handing out a certain number of bags without opening them. What is the minimum number of bags required?
(1) 11 (2) 12 (3) 13 (4) None of these

Kindly answer this question with explanations.

[shashankmishra]

Originally Posted by certified.pagla

Q. Suppose a, b and c are in AP and a^2, b^2 and c^2 are in GP. If a < b < c and a + b + c = 3/2 then what is the value of a ?

Let .......

a = x
b = x + d
c = x + 2d

Also a+b+c = 3/2 or
3x + 3d = 3/2 or (x + d) = 1/2 = b

Now assuming new AP Series........
a = 1/2 -y
b = 1/2
c = 1/2 + y

So a^2 = 1/4 + y^2 - y
b^2 = 1/4
c^2 = 1/4 + y^2 + y

So .............1/16 = [1/4 + y^2 - y]*[1/4 + y^2 + y] or
1/16 = [(1/4 + y^2)^2 - y^2]

Solve for y........

y = 1/root2 , 0

So a = 1/2 - 1/root2 = (1 - root2)/2

Caution : Pls don't cancel out y at any stage otherwise you will end up in getting y = 0 again and again, but we have to find all the possible values of y..........

BTW for y = -1/root , a = (1 + root2)/2 is also possible.........for which a<b<c condition will be violated.......

[certified.pagla]

Q. 2 - sqrt(6407522209)/sqrt(3600840049) =
A. 0.666039
B. 0.666029
C. 0.666009
D. None of the above

Please give best approach to solve bcz answers are very close

[certified.pagla]

Originally Posted by shashankmishra

Let .......

a = x
b = x + d
c = x + 2d

Also a+b+c = 3/2 or
3x + 3d = 3/2 or (x + d) = 1/2 = b

Now assuming new AP Series........
a = 1/2 -y
b = 1/2
c = 1/2 + y

So a^2 = 1/4 + y^2 - y
b^2 = 1/4
c^2 = 1/4 + y^2 + y

So .............1/16 = [1/4 + y^2 - y]*[1/4 + y^2 + y] or
1/16 = [(1/4 + y^2)^2 - y^2]

Solve for y........

y = 1/root2 , 0

So a = 1/2 - 1/root2 = (1 - root2)/2

Caution : Pls don't cancel out y at any stage otherwise you will end up in getting y = 0 again and again, but we have to find all the possible values of y..........

BTW for y = -1/root , a = (1 + root2)/2 is also possible.........

But in that case a<b<c is violated.

[uhhh...]

Originally Posted by santosh.baksi

Ashish is given Rs.158 in one rupee denomination. He has been asked to allocate them into a number of bags such that any amount required between Re.1 and Rs.158 can be given by handing out a certain number of bags without opening them. What is the minimum number of bags required?
(1) 11 (2) 12 (3) 13 (4) None of these

Kindly answer this question with explanations.

consider a binary system where each bag represents the 2^r

so you can construct as many (decimal) using these between 1-158

7 bags containing 2^0 to 2^6 coins.. sum = 2^7 -1 = 127

158 - 127 = 31 need not be decomposed further because the remaining combinations can be created by excluding 2, 4, 8, 16 that we have already constructed.. 8 bags

[uhhh...]

Originally Posted by certified.pagla

Q. 2 - sqrt(6407522209)/sqrt(3600840049) =
A. 0.666039
B. 0.666029
C. 0.666009
D. None of the above

Please give best approach to solve bcz answers are very close

hehe.. wheres my calculator

[arya5139]

Originally Posted by santosh.baksi

Ashish is given Rs.158 in one rupee denomination. He has been asked to allocate them into a number of bags such that any amount required between Re.1 and Rs.158 can be given by handing out a certain number of bags without opening them. What is the minimum number of bags required?
(1) 11 (2) 12 (3) 13 (4) None of these

Kindly answer this question with explanations.

I m getting 12

The bags will contain 1,2,4,8,16,...64 and 1,2,4,8,5 in all total 12 bags

whts OA?

[Kashyap Rastogi]

Originally Posted by certified.pagla

Q. 2 - sqrt(6407522209)/sqrt(3600840049) =
A. 0.666039
B. 0.666029
C. 0.666009
D. None of the above

Please give best approach to solve bcz answers are very close

This is a question from IIFT. Posted this earlier too, but no response. Somebody please share the approach to such questions. If it has appeared in IIFT paper, it must have a soln..

[prateekg23]

Originally Posted by Kashyap Rastogi

This is a question from IIFT. Posted this earlier too, but no response. Somebody please share the approach to such questions. If it has appeared in IIFT paper, it must have a soln..

the best solution is to skip it.there is no hifi funda for such questions. u have to calculate it to 4 decimal places and get ur nerves aching.nd even after thst still there's a possibility tat u might end with the wrong answer.so dont worry enjoy