[Vineetverma]

Originally Posted by Vineetverma

see the attachment for diag if u cant se it then srry move on to the next post

nywaz
qn if u were trapped in a square shaped cage ( with megan fox ) in a triangular room in which two corners of the cage are touching the two smaller sides of a triangle and one side of the of the cage is on the largest side of the triangle.. what wud be the size of a side of the square cage

ps: lengths of sides of the triangle 10 , 17 and 21

no answer available

wrkin on it

the room cn be split into two parts (right angled triangles) of dimensions 6,8,10 and 8,15,17

nw i m stuck

[anshul_mechie]

Originally Posted by Vineetverma

see the attachment for diag if u cant se it then srry move on to the next post

nywaz
qn if u were trapped in a square shaped cage ( with megan fox ) in a triangular room in which two corners of the cage are touching the two smaller sides of a triangle and one side of the of the cage is on the largest side of the triangle.. what wud be the size of a side of the square cage

ps: lengths of sides of the triangle 10 , 17 and 21

no answer available

wrkin on it

the answer should be 168/29
what i did was calculate the total area..
then find the height..
then equate the total area with the area of the four parts...
form an equation in s and solve it...
the answer may be wrong bt the approach should be correct.. beacuse it had no glitches..
p.s. the answer is right.. it should be 168/29.. m gettin the total area correct using it..

n BTW
wud nebody bother to find out the side.. if he's in der wid MEGAN fOX...

[Kashyap Rastogi]

<<<snipped>>>

[Vineetverma]

Originally Posted by anshul_mechie

the answer should be 168/29
what i did was calculate the total area..
then find the height..
then equate the total area with the area of the four parts...
form an equation in s and solve it...
the answer may be wrong bt the approach should be correct.. beacuse it had no glitches..
p.s. the answer is right.. it should be 168/29.. m gettin the total area correct using it..

n BTW
wud nebody bother to find out the side.. if he's in der wid MEGAN fOX...

I am getting 5.4 cm (div in the ratio 10:17)

nd abt measuring the sides so true

[shashankmishra]

Originally Posted by Vineetverma

see the attachment for diag if u cant se it then srry move on to the next post

nywaz
qn if u were trapped in a square shaped cage ( with megan fox ) in a triangular room in which two corners of the cage are touching the two smaller sides of a triangle and one side of the of the cage is on the largest side of the triangle.. what wud be the size of a side of the square cage

ps: lengths of sides of the triangle 10 , 17 and 21

no answer available

wrkin on it

Area of triangle = 84 so height = 8........

Now consider it as similar triangle ..........So we have
Side of square = x

(8-x) / 8 = x / 21

x = 168/29


What MEGAN FOX ........

Who cares the side........ Damn!! Who cares the CAGE.....

[anshul_mechie]

Originally Posted by Vineetverma

I am getting 5.4 cm (div in the ratio 10:17)

nd abt measuring the sides so true

168/29 is 5.79... almost there...
hw did u get 5.4..post d approach...

[Vineetverma]

Originally Posted by anshul_mechie

168/29 is 5.79... almost there...
hw did u get 5.4..post d approach...

srry used the wrng approach hence the wrng ans i guess i must ve been majorly distracted

ur approach is right

[divishth]

Originally Posted by Vineetverma

The Megan Fox Love Triangle

Anshul Is Correct, Have My Approach

Area Of triangle = root[(s)(s-a)(s-b)(s-c)] = 84
Also, 1/2 * b * h = 84
h = 8

Now Let Triangle Be AEH, Square Be BCGF And Altitude Be ED
By Similarity,
BC/ED = AB/AD
AD = AB*ED/BC .. (1)
Also, HF/HD = GF/ED
HD = HF*ED/GF .. (2)

Adding 1 and 2
AD + HD = ED/BC * (AB + HF) (because BC=GF)
21 = 8/BC * (AH - BF)
21 = 8/BC * (21 - BC)
21BC = 168 - 8BC
29BC = 168
BC = 168/29

[Abhinav90]

Originally Posted by anshul_mechie

plz post the solution with an UNDERSTANDABLE approach for dis one...

for any natural nos. let k be the index of the highest power of 2 which divides the number. among the first 100 natural nos. all those nos. for which k is even are removed. find the index of the highest power of 2 which divides the product of remaining nos.

can anyone tell me what is meant by 'index' of a number?
or provide a link to understand the same....

[harshkumar1]

Originally Posted by crack_2009

How many different prime numbers are factor of N if
log11log13log17log19N =23

where 11,13,17,19 are bases to log ?

options

1) 2
2) 7
3) 4
4) 0
5) None of these

(loglogloglog N )/log11*log13*log*17*log19 = 23
log log log log N = 23 * log11 * log13 * log17 * log19
log log log log N = 23 * log(11+13+17+19)
log log log log N = 23 * log(60)
log log log N = 60^23
log log N = 10 ^ (60^23)
log N = 10 ^ (10^ 60 ^23)
N = 10 ^ (10 ^ 10 ^ 60 ^ 23)
N = (5 * 2) ^ (10 ^ 10 ^ 60 ^ 23)
Hence there should be 2 prime nos only.

2(Option 1)

Plz post the OA for this.